similar to: linear regression: Is there a way to get the results of lm as variables

Hi, I recently discovered the R program and I thought it could be useful to me. I have to analyse data saved as .Px file (x between 0 and 8 - .P0 files have 18 lines at the beginning that I have to skip). New files are generated everyday. This is my strategy : In order to analyse the data, I first want to copy the new data in a database in MySQL (which already contains the previous data). So

Hello, I want to do normality test on my data I write this but I don't understand the display of the results ks.test(data,"pnorm") In fact I want to know if my data is a normal distribution. I have to check the p-value or D? Thanks. _____________________________________________________________________________ l [[alternative HTML version deleted]]

Dear R-listers, I am trying to compute simultaneous confidence intervals with simint from the package multcomp. 230 measures (abundance) have been taken in 23 sites (factor) of a data.frame (donnees: a file can be sent on request, saved with save(donnees,file="donnees")). I would like to get all pairwise comparisons with : mc<- simint(ren~ID,type="Tukey",data=donnees) I

Hi, I have a data frame of 2 columns with the following types : data$day char data$value num And I plot my data with : plot(strptime(donnees$day,format="%Y-%m-%d %H:%M:%S"),donnees$value, type="l") And I'd just like to get the numerical value of the integration of this graph. I looked at ?integrate but, as far as I understood (that is, not very much, due to my poor

Dear R Users, If we issue simple plot command in R we don't get legend of the plot automatically. For example, following lines plots two curves, but to write a legend of these two curves there is no simple command. I checked with ?legend but it seems bit complicated for me. Does anyone know how to get a legend in a simple way for following R plot. Thanks, Yogesh >plot (x,y,

Hello Rhelpers, I am trying to represent the following data (hereafter named donnees) in a barchart with a grouping variable : site traitement date s res 1 NT 17/10/2005 normal 76.2 1 T 17/10/2005 normal 103.2 1 NT 23/11/2005 tardif 81.6 1 T 23/11/2005 tardif 98 2 NT 15/10/2005 normal 72.71 2 T 15/10/2005 normal 94.47 2 NT 15/11/2005 tardif 79.65 2 T 15/11/2005 tardif 94.7

I am thinking of buying a Portec MV370 (single channel VoIP/GSM gateway) I am after feedback reports both good and otherwise please. Thanks, Michael

hello! je veux importer un fichier de donnees excel que j'ai au prealable converti en fichier txt avec separateurs tab, fichier de la forme entree simple (suite de colonnes contenant des variables). Voila ma ligne de commande : > poussins <- read.table("poussins.txt", header=T, sep="\t") et sa reponse Erreur dans scan(file = file, what = what, sep = sep, quote =

hello, I work since a few time on R and i wanted to know how to obtain the Wald chi square value when you make a binary logistic regression. In fact, i have the z value and the signification but is there a script to see what is the value of Wald chi square. You can see my model below, Best regards, S??verine Erhel [Previously saved workspace restored] > m3 = glm(reponse2 ~ form +

Dear collegues. I am using scan( ) to read from a table (a csv file). I am wondering how to let the program know that the end of the file is reached? Your help will be highly appreciated! Best Wishes Yuchen Luo [[alternative HTML version deleted]]

All, Recently I ran across a URL documenting published research using R: http://www.cgd.ucar.edu/ccr/ammann/millennium/CODES_MBH.html A note on the site indicates that the code is being revised. The code and data are provided, so that one could reproduce the results without having to buy a proprietary software program. In poking around the R website it is clear that a lot of thought has gone

In a lattice 11x11 with 6 repetitions, we want to compare lines to their two parents. 3 of the 6 repetitions are sprinkled and the 3 others not. There are 5 factors : hm (hydrous mode), variety, block, rep and grandrep. grandrep gathers two repetition, a sprinkled and a not (as in Split Plot !). I use lme but I have problems in random. Can someone help me ? Ibnou DIENG

Hallo everyone, excuse me if this is not a genuine R question but I do not know where to ask else. Referring to e.g. https://stat.ethz.ch/pipermail/r-help/2004-December/062114.html I wonder if these measurements of 3000 criminals (raw data) are available anywhere. At least I didn't find them in the R datasets package or by means of Google. What I did find was a table of frequencies of

Hola Colegas: Me reintegro al estudio de R y quisiera me pudieran resolver el problema que planteo en el archivo adjunto. Gracias anticipadas. *MANOLO MÁRQUEZ P.* ------------ próxima parte ------------ Se ha borrado un adjunto en formato HTML... URL: <https://stat.ethz.ch/pipermail/r-help-es/attachments/20130511/b0c9f15d/attachment.html> ------------ próxima parte ------------ An embedded

Bonjour, Je suis actuellement doctorant (en fin de th?se) et je vais avoir besoin de me servir de R. Devant apprendre R tout seul, je suis tomb? sur un mail de vous disant que vous aviez r?aliser un tutorial sur ce logiciel pour des 100% d?butant comme moi J'aurai essentiellement ? utiliser des algo de clustering (SOM ou Nu?e dyna) sur des matrices pouvant faire 41x230 Cependant je

Hi all R users I did a logistic regression with my binary variable Y (0/1) and 2 explanatory variables. Now I try to draw my nomogram with predictive value. I visited the help of R but I have problem to understand well the example. When I use glm fonction, I have a problem, thus I use lrm. My code is: modele<-lrm(Y~L+P,data=donnee) fun<- function(x) plogis(x-modele$coef[1]+modele$coef[2])

> No HTML this time. Sorry Dear all, I am attempting to model some one-dimensional data using Gaussian mixture model with mclust.? Generally, the data that I have have 3 overlapping populations (with one of them being the majority, and the other two combining to less than 15%) and for some reason, mclust consistently ignores the smaller peaks, giving me strange values for the means

Dear statistitians / R users, I was told to analyse the effects of the four factors using lm or update for aov. The following is the result from lm. As you can see that in the last few lines enclosed coefficients. 1)Does this mean I can write a formula, like yield =0.26 + 0.03*H + 1.48*T + 0.04*L + 0.004*C 2) in the two levels design, is there any difference between I use (-1, 1) to

Hi I am working on corpora of automatically recognized utterances, looking for features that predict error in the hypothesis the recognizer is proposing. I am using the glm functions to do logistic regression. I do this type of thing: * logistic.model = glm(formula = similarity ~., family = binomial, data = data) and end up with a model: > summary(logistic.model) Call:

Hi All, I was wondering if someone could help me to solve this issue with lmer. In order to understand the best mixed effects model to fit my data, I compared the following options according to the procedures specified in many papers (i.e. Baayen <http://www.google.it/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&ved=0CDsQFjAA