similar to: sort dates within a factor

hi ,everyone, I have a script shown as below: > bj2=bjerrdata$tyerr[bjyearnum[2]+1:bjyearnum[3]] > length(bj2) [1] 448 while > b=bjyearnum[3] > a=bjyearnum[2]+1 > bj1=bjerrdata$tyerr[a:b] > length(bj1) [1] 169 it is different with bj2 and bj1 . and the array bjyearnum is [1] 0 279 448 633 1021 1365 1813 2237 2839 3314 3798 4157 12 why bj1 is 169 while bj2 is 448

this blog entry http://www.viggie.com/blog/software/opensuse-ubuntu-usage-experience , if credible , would seem to suggest that there is no good reason to choose Suse. I really don't have time for such nonsense, maybe I'll just reinstall as Ubuntu. Also, noticed that GCC was not installed when Suse installed. That's just weird, GCC is part of Linux. And if you try to install GCC,

Hi, I'm plotting a bar chart like this: ggplot() + geom_bar(data=res,aes(fill=f1,x=f2,y=y),stat="identity",position="dodge") f1 contains quite a few levels and the plot is really quite difficult to read when the order of bars on the graph and on the legend does not match. This problem has been discussed recently here:

The following code isn't working and we can't figure out why.. letters = c("A","B","C","D","E","F","G","H","I","J") numbers = 1:3 for(i in 1:6){ #6 letters for (j in 1:3) { #3 numbers for (k in -1:1) {

I am trying to reshape a data set. Could someone please help me with the reshape, cast, and melt functions? I am new to R and I have tried reading up on how to use the reshape package, but I am very confused. Here is an example of what I am trying to do: subject coder score time [1,] 1 1 20 5 [2,] 1 2 30 4 [3,] 2 3 10 10 [4,] 2 2

Hi all, I use "write.csv" and "write.table" to write a data frame in a file like following: write.csv2(allRandomTestCase_XDroped, "allRandomTestCase.csv") But in the created file "allRandomTestCase.csv" an additional column with consecutive numbers is automatically added to the column of the data frame "allRandomTestCase_XDroped". That is why my

My uncle recently bought a new computer and he wants me to help him install Guitar Pro. The thing is, he doesn't have Windows, and I'm thinking of installing Ubuntu with wine on the comp. Quiz time! Can you use wine, with GP, and if you can, deos it perform poorly in any ways?

Hi everyone, I've got quite a few labels along the x axis and ggplot2 basically just crams them on top of each other. Is it possible to reduce the font size and/or text direction? Stretching the "windows" device window manually also helps, but I found that setting the parameters for the pdf device (where my scripts should print the data), such as paper="a4r" just results

I have a simple 1 way anova coded like summary(ANOVA1way <- aov(Value ~ WellID, data = welldata)) How can I use the BY function to do this ANOVA for each group using another variable in the dataset?? I tried coding it like this, but it doesn't seem to work. summary(ANOVA1way <- by(welldata, Analyte, function(x) aov(Value ~ WellID, data = welldata))) In SAS I would code it like this:

I have a bit of a quandy. I'm working with a data set for which I have sampled sites at a variety of dates. I want to use this data, and get a running average of the sampled values for the current and previous date. I originally thought something like ddply would be ideal for this, however, I cannot break up my data by date, and then apply a function that requires information

I have a large dataset grouped by a factor and I want to perform a regression on each data subset based on this factor. There are many ways to do this, posted here and elsewhere. I have tried several. However I found one method posted on the R wiki which works exactly as I want, and I like the elegance and simplicity of the solution, but I don't understand how it works. Its all in the formula

Dear list, I need help, since I can not come up with an easy solution to convert this vector test <- c('p','p','t','t','t') to [1] NA NA 1 2 3 which means the occurences of 't' should be summed up at the corresponding positions. The solution should also be able to handle the following scenarios: test2 <-

Hi all, I'm doing nonlinear regressions on data with several factors. I want to fit say a logistic curve with different parameter values for each factor level. So I'm doing something like: tmp <- by( myData, list(myFactor1, myFactor2), function(x) nls(...) ) It works fine. However, I could not find an easy way to retrieve fitted values. I can use fitted() on each element of tmp, but

Dear R Users, I'm trying to use the 'cast' function in the 'reshape' package to convert column-format data to gridded-format data. A sample of my dataset is as follows: head(finalframe) Latitude Longitude Temperature OrigLat p-value Blaney 1 -90 -38.75 NA -87.75 17.10167 NA 2 -90 135.75 NA -87.75 17.10167 NA 3 -90 80.25

Dear List, why does this not work? df <- data.frame(var1 = c(3,2,1), var2 = c(6,5,4), var3 = c(9,8,7), fac = c('A', 'A', 'B')) tapply(cbind(df$var1, df$var2, df$var3), df$fac, mean) Thank you, Stefan

Dear list, I have a multi(3)dimensional table, which is printed as two tables: > table.a , , = female not at all a little medium heavy no 53 27 8 6 yes 30 67 61 66 , , = male not at all a little medium heavy no 31 20 11 5 yes 5 19 34 25 How can I access (manipulate)

Hi all, I prepared a few charts with ggplot2, and was happy with the results as displayed on screen. I tried to draw them with a PNG driver instead. But I ran into several problems while trying to increase the resolution of the picture. Mainly, when I increased the picture size (e.g png(width=1024, height=768) ), the texts (title, labels, etc...) where too small. I tried to set the

Hi List, I have start and end times of events structure(list(start = c("15:00", "15:00", "15:00", "11:00", "14:00", "14:00", "15:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00",

Dear List, I am writing a function in R with the facility to store models for later use in scoring. It would be very useful if I could include in the name of the file stored the name of the model object being stored, this name being chosen by the user in the function call. A simple function to store the name of an object as a character string would fit the bill, but I have not found one. name()

Dear List, I have this column/vector: vec <- c("function", "missing", "string") and want to compute a second column/vector: - value if the pattern "unc" is found: 1 - value if the pattern "iss" is found: 2 - value if none of the patterns is found: 0 This should be the result: > vec2 [1] 1 2 0 Any help? Tried it with grep, but the output