similar to: Function question

Dear all, I have a question about how to set arguments in my own function. For example, I have a function that looks like this: my.f <- function(a = x1, b = x2) { x1 = equation 1 x2 = equation 2 x3 = equation 3 y = a + b } x1, x2, and x3 are temporary variables (intermediate results) calculated from other variables within the funciton. I want to use two of these three

Dear all: I am a new R-user and I have 2 questions about it. 1) I need to find specific sub-dataframe, and then use specific column to calculate. For example, after splitting dataframe, I find specific the sub-dataframe, such as ?A.split [1]?. But, I don?t know how to find ?time? and ?concentration? columns of ?A.split [1]?. 2) The equation used to sub-dataframe is

Dear R-users, Suppose I have an expression: expr = expression(a>0) and now I want to modify it to expression(a>0 & b>0). The following doesn't work: expr = expression(expr & b>0) What would be a good way of doing this? Thanks, Vadim ________________________________ Note: This email is for the confidential use of the named addressee(s) only and may contain

Suppose I have the first vector: c(1, 6, 8, 9) I will like to create a second vector of size 10 composed of 0 and 1's. The second vector will be composed of four 1's and six 0's. The position of the 1's will be specificed by the first vector. So essentially, I want a second vector in the form: c(1, 0, 0, 0, 0, 1, 0, 1, 1, 0) Any help is greatly appreciated! -- View this message

Hi all. Suppose I have a vector of strings ie: ["12384", "TYU123123", "AVC3939", "hhr1919", "TYU0029"] Is there an efficient method that would allow me to return a vector of the position of strings that start with "TYU"? So essentially, I would like to get back in return [2, 5]. Anyways, any help with be greatly appreciated! -- View

Dear R-experts, I have got a dataframe: data ID disease V1 V2 1 p1 1 2 p1 3 3 p3 3 4 p3 5 5 p5 1 From which I extract a usefull table: affect affect 1 3 5 p1 1 1 0 p3 0 1 1 p5 1 0 0 I want to merge this with anotherdataframe: age p1 23 p2 24 p3 23 p4 11 p5 45 If have tried as.data.frame(affect) and other solutions to get the following comment going:

Hi, I have a table of x rows and y columns. The table is huge and so i'd like to create a subset of the data containing rows where any of the y values are below a threshold, say 1e-4. Is there a simple way of doing this in R? thanks Rich

Hi All, I might misunderstood how cut works. But following behaviour surprises me. vv <- seq(150, 346, by= 4) cc <- cut(vv, 12) cc[vv == 330] Results [1] (330,346] I would have expected 330 to fall into (313,330] category. Can you please advice what do I do wrong? Many Thanks, Jussi Lehto -------------- next part -------------- Visit our website at http://www.ubs.com This message

Dear Sir/Madam, I got some problem about using R. I am a student, and need to use R a lot. But sometimes when I am working in computer lab, we can not install some particular pacakges by ourselves because of the previliges. Can the folder of Librabry of R, move to, for instance the personal folder, my documents... then we can install any specified package? Best regards,

Dear R Users, How can I create names for lists within a function where the name itself is a function of several variables ? > a<-1 > b<-2 > paste(a,b) [1] "1 2" > foo<-list(paste(a,b)=3) <<<===== DOES NOT WORK Error: unexpected '=' in "foo<-list(paste(a,b)=" > eval(paste(a,b)) [1] "1 2" >

Dear All, to produce output of several columns of a data frame, I tried to use lapply and also l_ply. In both cases, I would like to print a header line containing also the name of the respective column in the data frame. For example, I would like the following lapply(data.frame(a=1:3, b=2:4), function(x) print(deparse(substitute(x)))) to produce: [1] "a" [1] "b" and

Hi everyone, I'm trying to create an "if" conditional statement with two conditions, whereby the statement is true when condition 1 AND condition 2 are met: code structure: if ?AND? (a[x,y] <condition1>, a[x,y] <condition2>) I've trawled through the help files, but I cannot find an example of the syntax for incorporating an AND in a conditional IF statement.

http://www.nabble.com/file/p15359204/test.data.csv http://www.nabble.com/file/p15359204/test.data.csv test.data.csv Hi, I have used apply to have certian combinations, but when I try to use these combinations I get the error [Error in eval(expr, envir, enclos) : object "X.GDAXI" not found]. being a novice I donot understand that after applying combination to the data I cant access

Hi, I try to use a substitute function to generalise a equation. I have this: expression(1+2*pred+3*lat) I need to define the equation in function of x1 and x2 variables. Also I try to define who is x1 and x2. I try this: X1 <- "pred" X2 <- "lat" Now I need substitute pred and lat in equation by x1 and x2 defined on X1 and X2 above, I try this way: >

I am interested in utilizing this so called "double hurdle" model in my study. We can write the model in the following way: if (z'a + u > 0 & x'b + e > 0) y = x'b + e, else y = 0 In the model, consumption y is the (left-) censored dependent variable. e and u are the normally distributed error terms. z'a is the participation equation and x'b is the

Hi Saurav! On Sun, Jul 12, 2009 at 6:06 PM, Pathak, Saurav<s.pathak08 at imperial.ac.uk> wrote: > I am new to R, I have to do a 2 step Heckman model, my selection equation is > below which I was successful in running but I am unable to proceed further, > > > > I have so far used the following command > > glm(formula = s ~ age + gender + gemedu + gemhinc + es_gdppc +

Dear R users I am analysing data from a group of twins and their siblings. The measures that we are interested in are all correlated within families, with the correlations being stronger between twins than between non-twin siblings. The measures are all calculated from survey answers and by definition have limited ranges (e.g. -5 to +5), though within the range they are approximately normally

Is there a way to combine two columns within a data frame? Example data: id snp AL1 AL2 1500 30 A B 1510 30 A A 1520 30 A B This is what I would like: indv snp AL1AL2 1500 30 AB 1510 30 AA 1520 30 AB Any help is greatly appreciated. Alysta

I am relatively new to R, so this may be a much simpler question than it seems to me. I am trying to create a function that includes two summations, and can't figure out how. I am attaching the equation as a pdf file. This function will then be optimized over a chosen range of values, but right now I just need help with the function. Thank you. Zack Darnell Duke University -- Zack

Thanks: To Stef and Tobias Geiger for giving me the answer. I used the prio to get the order right. Don't know why I did'nt think of it myself. Compression: Another thing that might be useful to the list is the use of compression (Deflate etc.) to get better bandwidth across links. This requires a Linux router at both ends of the link. I got the idea from a product called Peribit see