similar to: as.POSIXct(as.Date()) independent of timezone

The return value of Sys.time() today with a timezone of US/Eastern is unchanged between 4.0.3-patched and devel, but on devel the following test fails all.equal(x, as.POSIXlt(x)) with x = Sys.time() This means that devel does not complete make tests (failure on tests/reg-tests-2.R) It is entirely possible that it is an error on my end, I use export TZ="US/Eastern" but I have been

I am using POSIXct objects to store my date/time information. If I am plotting less that 2 days worth of data, I get the correct tick marks on the x-axis which is showing the 'day HH:MM' and these line up with the data points. If the data spans more than 2 days, the tick marks are now off. In the data below, I am creating some sample data and plotting the points. I am in the Eastern

I have some questions and comments on timezones. Problem 1. # get current time in current time zone > (now <- Sys.time()) [1] "2003-07-29 18:23:58 Eastern Daylight Time" # convert this to GMT > (now.gmt <- as.POSIXlt(now,tz="GMT")) [1] "2003-07-29 22:23:58 GMT" # take difference > now-now.gmt Time difference of -5 hours Note that the difference

Yes, the potential issue I see is that make check fails when I explicitly set TZ. However, I set it to be the same as what the system reports when I login. Details: The system (RHEL) I am working on has $ strings /etc/localtime | tail -n 1 EST5EDT,M3.2.0,M11.1.0 $ date +%Z EDT $ echo $TZ US/Eastern On Fri, Oct 2, 2020 at 9:48 AM Sebastian Meyer <seb.meyer at fau.de> wrote: > Thank

Newbie here~ I've spent a ton of time on this, but have to admit I am stuck. I've tried various combinations of strptime and the package CHRON, but still can't get there. My simple task is that I want to plot salinity (S1 or S2) on y-axis and time on x-axis, but I want to use a lay-understandable representation of time (not Julian). If I use the following command, I can make a

Running under Windows XP 64 bit, as.POSIXlt()/as.POSIXct() seem to think that US time zones (EST5EDT, MST7MDT) switched from daylight savings back to standard time on Oct 28, 2007, whereas the switch is actually on Sun Nov 04, 2007. Examples: > Sys.timezone() [1] "Mountain Daylight Time" > as.POSIXct("2007-10-30 12:38:47") [1] "2007-10-30 12:38:47 Mountain

Hi, For a project I try to keep everything in normal time, not daylight saving time, to prevent problem when instruments collected data during the nights when we go from DST to normal time. But sometimes R tricks me and I do not know how to prevent it. This is one example: lights_on = as.POSIXct(c("2011-05-06 04:09:26", "2011-05-07 04:07:53", "2011-05-08

I'm having difficulties with daylight saving times in US time zones. (Apologies for the long post, but the problem seems subtle and complex, unless I'm doing something completely wrong, in which case it should be evident from the first 10 lines below.) This is what I see, using a (slightly modified) example from ?as.POSIXlt : > as.POSIXlt((d <- Sys.time()), "EST5EDT") #

R 3.5.0 Is it intended that the Date method of as.POSIXct does not respect the tz parameter? I suggest changing as.POSIXct.Date to this: function (x, tz = "", ...) .POSIXct(unclass(x) * 86400, tz = tz) Currently, the best workaround seems to be using the character method if one doesn't want the default timezone (which is often an annoying DST timezone). This came up on

Full_Name: Erich Neuwirth Version: 2.3.1 OS: Windows XP, Linux Submission from: (NULL) (131.130.135.167) Converting Sys.Date() to a POSIX compliant time type in different ways produces inconsistent results: > Sys.date() [1] "2006-09-01" > as.POSIXct(Sys.Date()) [1] "2006-09-01 02:00:00 CEST" > as.POSIXlt(Sys.Date()) [1] "2006-09-01" >

When I do the date +%Z I get the timezone. Which currently is EDT. I am sending information to another system, that says EDT is not a valid timezone. I have no way to modify the other system. My question is - is there a way to get the non-day-lite savings time zone ? For example EST is valid - EDT is not. Just curious if there is an easy way already present to get a standard time zone. Thanks,

> Date: Wednesday, April 05, 2017 13:15:19 -0400 > From: Brian Mathis <brian.mathis+centos at betteradmin.com> > > On Tue, Apr 4, 2017 at 9:22 PM, Jerry Geis <jerry.geis at gmail.com> > wrote: > >> When I do the date +%Z I get the timezone. Which currently is EDT. >> >> I am sending information to another system, that says EDT is not a >>

There is something wrong, I think, with the date-time conversion from a numeric value if you use Central European Time (CET) as timezone. Examples from R: If I use the GMT time zone it is OK, I get the same time back from as.POSIXct as I entered > as.POSIXct(as.numeric(strptime("30/01/2012 13:00:00", format="%d/%m/%Y >

I am finding that axis.POSIXct uses the local timezone for deciding where to put tic marks, even if the data being plotted are in another time zone. The solution is to use attr() to copy from the 'x' (provided as an argument) to the 'z' (used for the 'at' locations). I have pasted my proposed solution in section 1 below (as a diff). Then, in section 2, I'll put some

I've been trying to understand the as.Date functionality and I have a date and time stamp field that looks like this: "Tue Sep 15 09:22:09 -0600 2009" and I need to turn it into an R Date object for analysis. Simple date conversions I have down, no problem: > adate = c("7/30/1959") > as.Date(adate,"%m/%d/%Y") [1] "1959-07-30" > But when it

Dear R-helpers, I have a problem converting an object made with the 'chron' function to a POSIXct object: # Make date based on DOY dat <- chron(dates=232, origin.=c(month=1, day=1, year=2008)) dat #[1] 08/20/08 # Converting to POSIXct uses current timezone (Sydney): as.POSIXct(dat) #[1] "2008-08-20 10:00:00 EST" # Setting GMT timezone has no effect? as.POSIXct(dat,

R developers, The "tzone" attribute is stripped from a POSIXct object when the subscript command is called ("[.POISXct"). This results in dates being printed in the locale specific format after a subscript operation is applied to a POSIXct object which has cause several problems for me in the past. Here is an example of this problem under R 1.9.1: > x <-

I have looked at ?as.POSIXct ?POSIXct and many of the references that are on those pages. I am bewildered with timezones. Is there a way to get what would go into tz="" for making a function that uses POSIXct to be able to be used in all of the timezones in just the united states? This is for both windows and mac... this is the function that I am wanting to use it with

Dear all, As of the current R alpha release, I'm seeing timezone-related warnings on installing any package (including the recommended ones), which I haven't seen before. For example, [~/Documents/Source/R-alpha]$ bin/R CMD INSTALL ~/git/tractor/lib/reportr * installing to library '/Users/jon/Documents/Source/R-alpha/library' * installing *source* package 'reportr' ...

Hi all; I've already send a similar e-mail to the list and Prof. Brian Ripley answered me but my doubts remain unresolved. Thanks for the clarification, but perhaps I wasn't clear enough in posting my questions. I've got a postgres database which I read into R. The first column is Timestamp with timezone, and my data are already in UTC format. An 'printed' extract of R