similar to: Help with date specification

Hello Everyone,I think this is a very simple problem, I have been struggling with it for a few days now. I have a 10-year daily data in the following format. Date A B C D E 1978-10-22 18 20.64 0.0 0.176 -1.76 1978-10-23 15 17.06 0.4 0.147 2.52 1978-10-24 3 7.588 0.0 0.068 -6.86 1978-10-25 9 11.491 0.0 0.102

Hello everyone, I am trying to use while loop to iterate a function until convergence. But I am having problem when I try to use a fixed number of iterations. Say I want to use maximum iteration of 150. If the value don't converge within maximum iteration, show warning of no convergence. Currently I don't have non- convergence problem so I think my code works fine. But in future I may

Hello everybody, I have two datasets, observed and predicted. Since my observed dataset is not in regular intervals, I need to filter my predicted dataset based on the measurement date of my observed data. Here, is an example similar to what I have library(chron);library(zoo) DATE<- seq(as.Date("2009-01-01"), as.Date("2009-05-01"), by = 1) mydat<- rnorm(length(DATE),

Hello everyone, I have a data generated in a way similar to the following library(chron);library(zoo) date<- seq(as.Date("1990-01-01"),, as.Date("2000-12-31"), by = 1) obs<- zoo(rnorm(length(date), mean = 10, sd = 2.5), order.by = date) monthly<- function(date) as.Date(as.yearmon(Date)) result<- data.frame ( Date = obs = aggregate(obs, monthly, sum)) Now, I want

Hi everyone, This might be a very petty thing but Its not working for me. I want to export an output to a txt file but without indexing. Here is what I have tried to do outfile<- function(Time, var.names, output) { var.names = c(names(para)) for(i in 1: ncol(output)){ cat(length(var.names), '\n') cat("A", "S", "C", "I", '\n')

Hello, I have a question regarding a way to control the appreance of output exported by R when I use capture.output( x, file = "Directory/file.txt") , I get a text file which when I paste to a word file looks like the first table below. The following table has its clumns spaced closely so when I paste it to a word file it looks continuous. Is there any option in R to make the outputs

Hello everyone, I am trying to solve 2D differential equations using finite difference scheme in R. I have been able to work with the equations with only one spatial dimensions but I want to extend it to the two dimensional problem. For example i can simulate one dimensional diffusion using a code like the following. But I want to write a similar code for,say, a two dimensional diffusion

Folks, I want to make the following function more efficient, by vectorizing it: getCriterionDecisionDate <- function (quarter , year) { if (length(quarter) != length(year)) stop ("Quarter and year vectors of unequal length!"); ret <- character(0); for (i in 1:length(quarter)) { currQuarter <- quarter[i]; currYear <- year[i]; if ((currQuarter < 1) |

Dear List,I am trying to use rep function in the following conditions A = c( 5, 6, 7, 11, 9, 12, 10, 15) B = c(12,15, 21, 31, 25, 27,32, *34*,13,12, 34, 33, 24, 29, 26, *28*,22,14,27,22,21,12,32, 16) I need to repeat each element of A, as many times as each element of B, for the entire length of B. for example, repeat 5, for 12 times, 6 for 15 times,........, 15 for 34 times, and then, again, 5

Dear List, I ran into some problems with time-series-Data. Imagine a data-structure where observations (x) of test attendants (i) are made a four times (q) a year (y). The data is orderd the following way: I y q x 1 2006 1 1 1 2006 3 1 1 2006 4 1 1 2007 1 1 1 2007 2 1 1 2007 3 1 1 2007 4 1 2 2006 1 1 3 2007 1 1 3 2007 2 1 I am looking for a way to count the attendants that at least have

Hi, I need to perform calculations on subsets of a data frame: DF = data.frame(read.table(textConnection(" A B C D E F 1 a 1995 0 4 1 2 a 1997 1 1 3 3 b 1995 3 7 0 4 b 1996 1 2 3 5 b 1997 1 2 3 6 b 1998 6 0 0 7 b 1999 3 7 0 8 c 1997 1 2 3 9 c 1998 1 2 3 10 c 1999 6 0 0 11 d 1999 3 7 0 12 e 1995 1 2 3 13 e 1998 1 2 3 14 e 1999 6

Hi I have a code that calculate maximisation using optimx and it is working just fine. I want to extend the code to run several colomns of R_j where j runs from 1 to 200. If I am to run the code in its current state, it means I will have to run it 200 times manually. May you help me adjust it to accomodate several rows of R_j and print the 200 results. ***Please do not get intimidated by the

Hi, I'd like to make a time series at an annual frequency. > a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993")) Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) : order.by requires an appropriate time-based object > a<-xts(x=c(2,4,5), order.by=1991:1993) Error in xts(x = c(2, 4, 5), order.by =

Hello all, First I have done extensive searches on this forum and others and nothing seems to work. So I decided to post thinking someone could point me to the write post or give me some help. I have drawn a 100 samples from a fictitious population (N=1000), and then randomly selected 25% of the 100 samples. I would like to now merge the data.frame from the 100 samples with the data.frame for

Hi All, I have a very simple question about a time series object: how to access values for a particular year and quarter (say)? Suppose, following http://www.stat.pitt.edu/stoffer/tsa2/R_time_series_quick_fix.htm I have read in data as a time series; here is how it looks. * Qtr1 Qtr2 Qtr3 Qtr4 1960 0.71 0.63 0.85 0.44 1961 0.61 0.69 0.92 0.55 . . . . .

Hello, I have two date strings, say "1972-06-30" and "2012-01-31", and I'd like to get every quarter period end date between those dates? Does anyone know how to do this? Speed is important... Here is a small sample: Two dates: "2007-01-31" "2012-01-31" And I'd like to get this: [1] "2007-03-31" "2007-06-30"

Is there any R function to calculate automatically the last day of a particular month? For example "sep2009" should be converted to last day of September of 2009? Thanks -- View this message in context: http://www.nabble.com/How-to-get-last-day-of-a-month--tp25425645p25425645.html Sent from the R help mailing list archive at Nabble.com.

I have a data set with quarterly time series for several variables. The time index is recorded in column 1 of the dataframe as a character vector "Q1 1961", "Q2 1961","Q3 1961", "Q4 1961", "Q1 1962", etc. I want to produce line plots with ggplot2, but it seems I need to convert the time index from character to date class. Is that right? If so, how

Hi Sagar, Are you getting a particular error? Because the same method should work just fine in NSD. Simply open the corresponding zone file (as configured in nsd.conf) and put that line in there. Best regards, Jeroen Koekkoek On Fri, 2023-07-21 at 09:14 +0200, Sagar Acharya via nsd-users wrote: > How do I add SRV record to my zone file? > > Eg. In pdns I have > >

I have financial data on a a set of firms, with a quarterly period (fundamental data). The data spans 10 years, and four quarters per year. The present file (.csv) reads the Date columns as "200706" for the second quarter of 2007; "199809" for the third quarter of 1997. Is there a way I can convert it to something like "2007 Q2", "1998 Q3"? I am aware of