similar to: How to separate a function by 2 probabilities

I am new in R and i am having trouble here. I?ve already searched in the list but hasn?t helped When i run this script above i get the message "Error in gen[j, i] : incorrect number of dimensions". However gen is 1000x200 (ind x loc) and so is g could anybody help me for (i in 1 : loc) { #loc=200 for (j in 1 : ind) { #ind=1000 g1 <= function ( gen ) matrix ( if (gen[j, i]

Thank you for the suggestion, Bill. The result is not quite what I would like. Here's sample code for you or anyone else who may be interested: Al1 = c('A','C','C','C') Al2 = c('G','G','G','T') Freq1 = c(0.0078,0.0567,0.9434,0.9908) MAF = c(0.0078,0.0567,0.0566,0.0092) m1 = data.frame(Al1=Al1,

Hey, I have a dataset and I want to identify the records by groups for further use in ggplot. Here is a sample data: ID Value AL1 1 AL2 2 CA1 3 CA4 4 I want to identify all the records that in the same state (AL1 AND A2), group them as "AL", and do the same for CA1 and CA4. How can I have an output like: ID Value State AL1 1 AL AL2 2 AL CA1 3 CA CA4 4

Hello, All! How might one accomplish this using the by() function? m1 is a data frame. # populate column "m1$major_allele" for ( i in 1:length(m1$major_allele)) { if ( m1$Freq1[i] == m1$MAF[i]){ m1$major_allele[i] = m1$Al1[i] } else{ m1$major_allele[i] = m1$Al2[i] } } Jim [[alternative HTML version deleted]]

Is there a way to combine two columns within a data frame? Example data: id snp AL1 AL2 1500 30 A B 1510 30 A A 1520 30 A B This is what I would like: indv snp AL1AL2 1500 30 AB 1510 30 AA 1520 30 AB Any help is greatly appreciated. Alysta

Hi John, Thank-you very much for replying, - in answer to your questions: *"As I understand what you wrote, all factors but linelabel are crossed, with linelabel nested within all the other factors?" That's exactly it, *" What is in the highest order cells? Single observations, or multiple scores?" I would say "single observations" - but i have to

Hello All, I have a toy dataframe like this. It has 8 columns separated by tab. Name SampleID Al1 Al2 X Y R Th rs191191 A1 A B 0.999 0.09 0.78 0.090 abc928291 A1 B J 0.3838 0.3839 0.028 0.888 abcnab A1 H K 0.3939 0.939 0.3939 0.77 rx82922 B1 J K 0.3838 0.393

Deal R Users, I'm trying to find out how can I compute probabilities on a Bayesian Network using R. The Bayesian Network I modelled is shown at http://www.dsr.inpe.br/~mello/1727/BNgrapmodel.png and I'd like to know how can I proceed (commands on R) to answer questions like: (1) what is the probability of S=T given C=T, L=T, R=F, H=F and D=F; or (2) what is the probability of S=T

Hello, I have a matrix with the numbers 0,1 and 9 I would like to write a function that could sum each line skiping everytime a number 9 appears for example [0 1 0 1 1 9 1] the sum would be 4. However I cannot replace 9 by 0 otherwise after the sum is done I wouldn?t be able to distiguish which ones were real zeros and which ones were nines replaced by zero just to sum. Thank you very much --

I have a matrix 700x2000 which is sampled in each cycle from another matrix 788x2000 with the numbers 0,1 and 9 There is one specific collumn of this matrix, dart[,1977], that usually, after the samplimg procedure has only 1 and 9 (because the zero frequency in this collumn is low). However, when this happens, I want to include an IF conditional in my code. so basically what i wanted to do was to

Greetings: I would like comments on this example and after fixing it up, I need help from someone who has access to insert this in R's help page for plotmath. I uploaded a drawing http://pj.freefaculty.org/R/Normal-2009.pdf that is created by the following code http://pj.freefaculty.org/R/Normal1_2009_plotmathExample.R This will be a good addition to the plotmath help page/example.

hello guys, I need to do a BLUP in the simplest model y = Xm + Zg + e however I have missing data in the analysis which I can?t consider as 0(zero). So I need to generate the matrix X'Z, Z'X and Z'Z step by step; I can?t use crossprod(x) #neither X'X <- t(x)%*%x because I should skip the elements with missing data in the matrix I?ll try to be more clear, supposing a matrix x

Hi, I hope you're all right. I describe below the scenario where the problem occurs. I'm trying to activate a master user [1] to be able to access all the boxes of all users by imap. I have configured the dovecot-master-users [2] file with the appropriate permissions. When I try to access, for example with roundcube, through user at mydomain.com*my_master_user at not-exist.com I see in the

After I run my script I save all my output e.g. write.table(d, file = "C:/PINEheight.txt) write.table(v, file = "C:/PINEvolume.txt) write.table(v, file = "C:/PINEdiameter.txt) write.table(v, file = "C:/PINEdensity.txt) and then I would like to run again with another tree and save again e.g write.table(d, file = "C:/POPULUSheight.txt) Is there anyhow I can define a

I would like to divide a vector in 9 groups in a way that each number is present in only one group. In a vector of 783 I would like to divide in 9 different groups of 87 Example <- matrix(c(1:783),ncol = 1) s1 <- as.matrix(sample(Example,87, re = FALSE)) Example <- Example[-s1] s2 <- as.matrix(sample(Example,87, re = FALSE)) #however I don?t know how to remove the second group from

Hi guys, I am still learning R, and not well familiar with all the apply functions. I am trying to find faster alternatives to replace the for cycle. Is there a faster way to do the example below? nm <- 1000 b <- matrix (rnorm (5000, 0, 1), nrow = 500, ncol = nm) a <- matrix (0, nm, nm) for (i in 1 : nm) { for (j in 1 : nm) { if ( j == i) { next } a[i, j] <- t (b [, i]) %*% b[, j] } }

#Mdarts is a matrix 2343x788 #frequencia is a vector 2343x1 # 9 in Mdarts[fri,frj] stands for my missing values which i want to replace by the value in the vector frequencia Mdarts<-t(matrix(scan("C:/GWS/CNB/dartg.txt"),ncol=nindT,nrow=nm, byrow=T)) frequencia <- matrix(scan("C:/GWS/CNB/freq.txt"),ncol=1) for (fri in 1:nindT){ for (frj in 1:nm){ Mdarts[fri,frj] <- if

Hi, I set up a samba 4 in Debian 9.9 as a Domain member server, but authentication is not working as follows: root at srv-proxy:/etc/samba# wbinfo -a marcio at EMPRESA.COM.BR Enter marcio at EMPRESA.COM.BR's password: plaintext password authentication succeeded Enter marcio at EMPRESA.COM.BR's password: challenge/response password authentication failed wbcAuthenticateUserEx(+marcio at

People, I have one PDC and a BDC on the matrix side and two BDCs on the branch office. I don't know if it is a problem. Anybody could help me? PDC # net rpc testjoin get_schannel_session_key: could not fetch trust account password for domain 'DOMAIN_NAME' net_rpc_join_ok: failed to get schannel session key from server PDC for domain DOMAIN_NAME. Error was

Senhores, bom dia! Tem como instalar o Samba 4 com o antivirus ClamAV? Achei v?rios artigos, mas n?o consegui fazer funcionar o ClamAV. Desde, j? agrade?o a aten??o de todos. Atenciosamente, Marcio Fiorette