similar to: Searching 1st number within a ch. string

Hi all, is there any function to find some words in a character-string? For example suppose the string is : "gdfsa-sdhchc-88", now I want to find whether this string contains "sdhch". Is there any R function to do that? Regards, -- View this message in context: http://www.nabble.com/Searching-within-a-ch.-string-tp23484010p23484010.html Sent from the R help mailing list

I was trying to dw data from Economagic [http://www.economagic.com/em-cgi/data.exe/libor/day-ussnon], using following code : library(fimport) dat2 = economagicSeries("libor/day-ussnon", frequency = "daily") Here I see that data is not complete, downloaded data starts from "2007-12-31 ", whereas actual data is available from 2001. secondly, how I convert that data

I need to solve a equation like this : a = b/(1+x) + c/(1+x)^2 + d/(1+x)^3 where a,b,c,d are known constant. Is there any R-way to do that? Thanks in advance -- View this message in context: http://www.nabble.com/How-to-solve-following-equation--tp20785063p20785063.html Sent from the R help mailing list archive at Nabble.com.

Hi, suppose I have following codes : library(zoo); library(ggplot2) dat <- matrix(rnorm(500*2), 500); dat <- zooreg(dat, start = as.Date("01/01/01", "%m/%d/%y"), frequency=1); plot(dat) head(dat); month.no <- format(index(dat), "%m"); dat1 <- cbind(coredata(dat), as.numeric(month.no)) x <- dat1[,1]; y <- dat1[,2]; z <- dat1[,3] Now I draw a

Hi, I want find all roots for the following polynomial : a <- c(-0.07, 0.17); b <- c(1, -4); cc <- matrix(c(0.24, 0.00, -0.08, -0.31), 2); d <- matrix(c(0, 0, -0.13, -0.37), 2); e <- matrix(c(0.2, 0, -0.06, -0.34), 2) A1 <- diag(2) + a %*% t(b) + cc; A2 <- -cc + d; A3 <- -d + e; A4 <- -e fn <- function(z) { y <- diag(2) - A1*z - A2*z^2 - A3*z^3 - A4*z^4

Hi everyone, I have this kind of raw dataset : - <Temp diffgr:id="Temp14" msdata:rowOrder="13"> <Date>2005-01-17T00:00:00+05:30</Date> <SecurityID>10149</SecurityID> <PriceClose>1288.40002</PriceClose> </Temp> - <Temp diffgr:id="Temp15" msdata:rowOrder="14">

I have a vector of letters like c("a", "B", "c"). Is there any R function to force all elements to lower-cap ? Thanks, -- View this message in context: http://old.nabble.com/How-to-make-all-elements-all-elements-lower-cap---tp26365794p26365794.html Sent from the R help mailing list archive at Nabble.com.

I want to draw following plot, given here http://www.2shared.com/file/4327128/830b82c4/pic.html for the following data : dat <- cbind(rnorm(100), sample(c(1:4), 1000, T)) colnames(dat) <- c("data","level") Here x-axis should be on "data" and y-axis is for "level" and z-axis should be to display the frequency of "data" for a particular

Hi, I am looking for a way to search a file for position of some expression, from within R. My current code: sha1Pos = gregexpr("<sha1>", readChar(filename, file.info(filename)$size))[[1]] Works fine for small files, but text files I will be working with might get up to Gb range, so I was trying to accomplish the same without loading the whole file into R. I realize this is

Hi all I am analyzing bird song element sequences. I would like to know how can I get how many times a given subsequence is found in single string sequence. For example: If I have this single sequence: ABCABAABABABCAB I am looking for the subsequence "ABC". Want I need to get here is that the subsequence is found twice. Any idea how can I do this? Thanks

Last one for you guys: The command: length(gregexpr('cus','hocus pocus')[[1]]) [1] 2 returns the number of times the substring 'cus' appears in 'hocus pocus' (which is two) It's returning the number of **disjoint** matches. So: length(gregexpr('aa','aaa')[[1]]) [1] 1 returns 1. **What I want to do:** I'm looking for a way to count

I have a date-like-vector like : > date_file "10-02-2008" "10-03-2008" "10-06-2008" "10-07-2008" "10-09-2008" "10-10-2008" "10-13-2008" "10-14-2008" "10-15-2008" "10-16-2008" "10-17-2008" "10-20-2008" "10-21-2008" "10-22-2008" "10-23-2008"

I have two variables (x,y) : x : it takes all integer values from 0 to y and, y : takes all values from 0, 10 I am looking for some R code to find all possible pairs of (x,y). Can anyone please help me? New Email addresses available on Yahoo! Get the Email name you&#39;ve always wanted on the new @ymail and @rocketmail. Hurry before someone else does! [[alternative HTML version

Dear all R gurus, I have following syntax: y = c(1:10) chippy <- function(x) { y[5] = x sin(cos(t(y)%*%y)*exp(-t(y)%*%y/2)) } curve(chippy, 1, 20, n=200) But I am getting error while executing : Error in xy.coords(x, y, xlabel, ylabel, log) : 'x' and 'y' lengths differ In addition: Warning message: number of items to

Hi, Let say I have a date variable: > ?asd <- as.Date("2012-01-03") > asd [1] "2012-01-03" Now, I want to express this date like 3/1/2012. can somebody help me how to achieve that? Thanks,

Sorry to be off-topic. Can somebody please explain me what is Portmanteau test? Why it's name is like that? When I would say, a particular test is portmanteau test? I did some googling but got no satisfactory answer at all. Please anybody help for understanding that? Regards, -- View this message in context:

Is there any function in R to clear values from all variables stored in current and previous sessions? R site search do not give the desired result at all, all results are about to clear screen only not variables. Thanks, -- View this message in context: http://www.nabble.com/How-to-Clear-all-variables-stored-in-current-and-previous-sessions-tp20604724p20604724.html Sent from the R help mailing

Hi, Suppose I have following dataset : mat <- matrix(rnorm(100), 50) Now I want to put 2nd column in the place of 1st and 1st column in the place of 2nd. Is there any "quick" way to do that? Thanks and regards, -- View this message in context: http://www.nabble.com/Altering-columns-tp24099597p24099597.html Sent from the R help mailing list archive at Nabble.com.

Hi all, can anyone please tell me what is the key-word to clear the screen? I am aware of the "cont+L", however I need some R-syntax, that can be typed into the console to clear the screen.   Thanks [[alternative HTML version deleted]]

Please consider the following : > expand.grid(rep(list(c(1:3)), 3)) Var1 Var2 Var3 1 1 1 1 2 2 1 1 3 3 1 1 4 1 2 1 5 2 2 1 6 3 2 1 7 1 3 1 8 2 3 1 9 3 3 1 10 1 1 2 11 2 1 2 12 3 1 2 13 1 2 2 14 2 2 2 15 3 2 2 16 1 3 2 17 2 3 2 18