similar to: Filling matrix secondary diagonal

Hi, I have worked long and hard and looked in the manuals and am having a hard time constructing a diagonal matrix. I can get the diagonals out of a matrix but can't construct the matrix with just the diagonals. I have been on the web site and manuals and I think that it says to use: dsj <- diag (three = 1, nrow, ncol = 7) three is the name of my matrix and

Sorry if this is a stupid question but I've been stuck on how to code so that I can order rows of a matrix without paying attention to the diagonal elements. Say, for example, I have a matrix d: > d [,1] [,2] [,3] [,4] [1,] 0.000000 2.384158 2.0065682 2.2998856 [2,] 2.384158 0.000000 1.4599928 2.4333213 [3,] 2.006568 1.459993 0.0000000 0.9733285 [4,] 2.299886

hi I'm trying to use the function odiag(x) for matrix calculations. I would like to assign new values to an off-diagonal in a matrix. When I use the diag (x) function I could write something like p<-matrix(seq(1:12),ncol=4) p.new<-matrix(rep(0,12),ncol=4) diag(p.new)<-diag(p) p.new But this won't work with odiag. How can I turn odiag (x) into something like diag (x) in order

Hello, I am using Mac OS X on a power book and R 2.5.0 I try to extract a diagonal from a dissimilarity matrix made with dsvdis, with this code: diag(DiTestRR) But I get this error message: Fehler in array(0, c(n, p)) : 'dim' spezifiziert ein zu großes Array english: Error in array(0, c(n, p)) : 'dim' specifies a too big array. Is there a limit to extract diagonals? I

Hello and sorry that I still haven?t found a solution for my problem. I need to extract the lower and upper triangle from a square matrix including the diagonal. This diagonal is not zero in that special case. I tried with as.dist w<-as.dist(w, diag = TRUE) > w 1 2 3 4 5 1 0 2 2 0 3 3 8 0 4 4 9 14 0 5 5 10 15 20 0 but found no way to keep the diagonal that is in the

Dear list, is anyone aware of the following behavious of diag when used to replace diagonals (plural!) of a matrix? Small example: The following is documented and clearly to be expected: A <- matrix(0, nrow = 5, ncol = 5) diag(A) <- 1; A BUT, what about the following? When executing the code of `diag<-` line by line, it throws errors. So why does it work? diag(A[-1, ]) <- 2; A

Given an nxm matrix A I want to compute the nxm matrix B whose ij-th element is the sum of the elements of A lying on the diagonal that ends with element ij, i.e., b_ij = a_ij + a_(i-1)(j-1) + a_(i-2)(j-2) + ... In APL (which I no longer use), I would use the 'rotate' operator to derive an array whose columns are diagonals of the given array and then cumulate down columns. Is

Hi Suppose I have a matrix (cohort are rows and years are columns) [2000] [2001] [2002] [2003] [C1] 0.01 0.03 0.02 0.09 [C2] 0.06 0.05 0.07 0.11 [C3] 0.1 0.5 0.4 0.98 [C4] 0.7 0.6 0.2 0.77 I want to extracts the diagonals to get a matrix which looks like this (C1 becomes C2 in 2002, C2 becomes C3 in 2003

Dear useRs, Trying to replace the diagonal of a matrix is not working for me. I want a matrix with .6 on the diag and .4 elsewhere. The following code looks like it should work--when I lookk at mps and idx they look how I want them too--but it only replaces the first element, not each element on the diagonal. mps <- matrix(rep(.4, 3*3), nrow=n, byrow=TRUE) idx <- diag(3) mps idx mps[idx]

Hello, I am in need of help in putting histograms on the diagonal of a plot produced with splom(). The plot matrix I am trying to produce is to have standard scatterplots in the upper-left triangle, contour plots in the lower-right triangle, and histograms on the diagonal. I have a function that does the first two, but the histograms on the diagonal has been beyond my ability. Here is my

Dear R-users, I would like to know whether there is a way to extract a diagonal of an inverse matrix without computing the inverse of the matrix itself. The size of my matrices are really huge and, also using sparse matrix, computing the inverse leads to storage problems and low speed. In other words, given a square matrix A, I aim to know diag(B), where B=solve(A), without computing solve(A).

h <- structure(list(V1 = c(-0.351714766, 0.188298251, 0.042951816, -0.072490327, -0.691885485, -0.816169763, -0.7066502, -0.856286332, -0.839723411, -0.427242353, -0.372911996, 0.326707494, 0.07847893, 0.687447841, 0.516105863, 0.267076547, 0.727867663, 0.432699191, 0.258610632), V2 = c(0.256636068, -0.824072121, -0.149185618, 0.153280492, 0.01649528, 0.409410528, 0.286015324, 0.366323539,

Dear All, I have a correlation matrix of size 100 x 100 and would like to extract the diagonal matrix from it. I have used the for loop to store tha correlation values of the diagonal matrix. Is there a 'R way' of doing this? Thanks in advance. Kind regards, Ezhil

splom() doesn't complain here, but writes no names in the diagonal boxes. What am I missing? I believe that I need to add something like grid.text(x, ...) to the diagonal panel, but I don't know how to get it cycle through the column labels. And should varname.col = 'blue', varname.cex = 1 be inside the diag.panel() function? splom(szw[, n], pscales = 0, diag.panel

Dear all, seems that easy question but cannot find the function for that. How to get the elements of the minor diagonal of the matrix? Thanks a lot. [[alternative HTML version deleted]]

Hi R-Help! I am trying to find a nicer way of extracting all the "complete" diagonals of a matrix. I am working with very large matrices that have many more rows than columns. I want to be able to extract each of the diagonals that are as long as the number of columns in the matrix. I have written a rather ugly function that presently does the job. It illustrates what I am trying to

Hi r-help community, This question isn't so much a syntax/coding one, but here goes: Let's say I have matrix of arbitrary dimensions and I'd like to reorder the rows in such a way that I could maximize the sum of the entries along the diagonal. For example, for this 3x3 matrix: [,1] [,2] [,3] [1,] 3 4 13 [2,] 9 1 2 [3,] 2 11 1 rearranging the rows

The following 1460 x 1460 matrix can be throught of as 16 distinct 365 x 365 matrices. I'm trying to set off-diaganol terms in the 16 sub-matrices with indices more than +/- 5 (days) from each other to zero using some for loops. This works well for some, but not all, of the for loops. The R code I"m using follows. For some reason the third loop below zero's-out everything in the

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I'd like to be able to colour histograms along the diagonal using the colours stored in colnames(d): > d black blue brown cyan 1 0.96405751 -0.02964390 -0.060147424 -0.06460070 2 -0.03614607 0.95475444 -0.152382053 -0.07767974 3 -0.07095613 -0.05884884 -0.061289399 -0.06445973 4 -0.03708223 -0.05997624

given this example library(corrgram) corrgram(mtcars[2:6], order=TRUE, upper.panel=panel.conf, lower.panel=panel.pie, diag.panel=panel.minmax, text.panel=panel.txt) how can I change the variable names in main diagonal? (so that I can put more informative names of variables) I think to understand that this should be done by modifing the panel.txt function but