similar to: vector size: Fixed

Hi, I have a data of size 981.1MB(1028707715) and I intend to calculate the length of the data using tapply function in R. I was able to read the data into R but when I tried to use the factor function, I had an error message "Error: cannot allocate vector of size 2.0 Gb". Can anybody tell me what to do? I have tried to increase the size of the memory but I am not sure if R recognizes it

?s 01:43 de 29/03/2024, Ogbos Okike escreveu: > Dear Rui, > Thanks again for resolving this. I have already started using the version > that works for me. > > But to clarify the second part, please let me paste the what I did and the > error message: > >> set.seed(2024) >> data <- data.frame( > + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1

--- On Mon, 1/17/11, Raymond Wong <raywong365@yahoo.ca> wrote: From: Raymond Wong <raywong365@yahoo.ca> Subject: Re: [R] help in calculating ar on ranked vector To: "Uwe Ligges" <ligges@statistik.tu-dortmund.de> Received: Monday, January 17, 2011, 11:56 AM Thanks Uwe:   Here is my code. the first set of print statements work, but not the second.   #

Dear Rui, Thanks again for resolving this. I have already started using the version that works for me. But to clarify the second part, please let me paste the what I did and the error message: > set.seed(2024) > data <- data.frame( + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1 days"), 100L, + TRUE), + count = sample(10L, 100L, TRUE) + ) > > # coerce

Hi Ogbos, Here is your sample data plotted in roughly the same way as the image. You can get the hours to start at the bottom, but it will require more code. swe$hour<-as.numeric(sapply(strsplit(swe$time,":"),"[",1)) swe$FD<-sample(1:2,nrow(swe),TRUE) library(plotrix) clock24.plot(swe$count,swe$hour,rp.type="s",radial.lim=c(3000,4010),

Dear All, This problem is over. Clock24.plot did the job. Thanks to all those who assisted me. Ogbos On Apr 22, 2016 8:34 PM, "Ogbos Okike" <giftedlife2014 at gmail.com> wrote: > Dear All, > One hand. Many thanks!! The code run as soon as I loaded lubridate. > > Please can you guide me on how to relate this code to my actual data. > My actual data is looking like:

Good day all. This is to thank all those who have helped in fixing this problem. Starting with a text book was indeed a problem, however, that gave me a clue of what I was looking for. This, with your contributions added to other materials I got on the net, put me on the right track. Thank you so much. Warmest regards Ogbos On 31 January 2010 14:07, S Ellison <S.Ellison@lgc.co.uk> wrote:

Dear All, Many thanks for bailing me out. Ogbos On Apr 18, 2016 9:07 PM, "David Winsemius" <dwinsemius at comcast.net> wrote: > > > On Apr 18, 2016, at 10:44 AM, Ogbos Okike <giftedlife2014 at gmail.com> > wrote: > > > > Dear ALL, > > Thank you so much for your contributions. > > I have made some progress. Below is a simple script I

Hi David, ----- Original Message ----- > From: "David Smith" <davidsmi at microsoft.com> > To: "Dan Tenenbaum" <dtenenba at fredhutch.org>, "Uwe Ligges" <ligges at statistik.tu-dortmund.de>, "Elliot Waingold" > <Elliot.Waingold at microsoft.com> > Cc: "R-devel at r-project.org" <r-devel at r-project.org>

Great stuff! Both plotrix and plotCI do the same but what count most here is the idea of assigning NA to some of the ciw values. Following your code, I assign "ciw[c(1,2,4,5,6,7,9,11)]<-NA" and that left me with the three error bars I wanted to display. Many thanks and warmest regards Ogbos On 7 April 2010 00:28, Jim Lemon <jim@bitwrit.com.au> wrote: > On 04/07/2010 03:49

Hi Peter, Many thanks. It worked. Regards Ogbos On 1 August 2011 14:05, Peter Ehlers <ehlers@ucalgary.ca> wrote: > On 2011-08-01 03:32, ogbos okike wrote: > >> Dear All, >> I am trying to put 10^-8 st km^-2day^-1 on x-axis of my plot. I tried >> using >> : ylab = expression(paste("st / ", plain(km)^2, " / day")) to see if I can >> at

Hey, Thanks for your great inputs. While "index = apply(mat == 0, MARGIN = 1, any)" gives you an idea of the rows containing zero(s), "index<-data[!apply(data==0,MARGIN=1,any),]" does the actual job of removing the rows with zeros. Kind regards Ogbos On 9 March 2010 15:12, Paul Hiemstra <p.hiemstra@geo.uu.nl> wrote: > Dimitris Rizopoulos wrote: > >>

2017-06-22 20:31 GMT+02:00 Uwe Ligges <ligges at statistik.tu-dortmund.de>: > > > On 22.06.2017 20:09, I?aki ?car wrote: >> >> 2017-06-22 19:49 GMT+02:00 Uwe Ligges <ligges at statistik.tu-dortmund.de>: >>> >>> On 22.06.2017 17:11, Bernd Funovits wrote: >>>> >>>> >>>> Hello, >>>> >>>> I

On Wed, 28 Jul 2004 09:53:08 +0200 Uwe Ligges <ligges at statistik.uni-dortmund.de> wrote: > > If your data is numeric, you will need roughly > > 1220 * 20000 * 8 / 1024 / 1024 ~~ 200 MB > > just to store one copy in memory. If you need more than two copies, your > machine with its 512MB will start to use swap space ..... > Hence either use a machine with more

In order not to forget it (I have not got any answer so far) ... Uwe Ligges -------- Original Message -------- Subject: plotmath in underlined style; was: Re: [R] Underline in expression(). Date: Sun, 26 Sep 2004 18:50:02 +0200 From: Uwe Ligges <ligges@statistik.uni-dortmund.de> Organization: Fachbereich Statistik, Universitaet Dortmund To: John Janmaat <jajanmaat@netscape.net>,

Kurt, Uwe suggested I write to you as maintainer of chron ... at the start of is.weekend, in the check on the argument type, maybe just change chron() to as.chron()? This would ensure as.chron.POSIXt gets called on POSIXt arguments, and (I think) fixes the problem. I tested and it seems ok. No warning/error required. > is.weekend function(x) { if(!inherits(x, "dates"))

Here's a fairly minimal-case example in which the saved EPS does not match the screen. The error comes when using bquote(.(i)) instead of bquote(1), as demonstrated by the two minimally different cases below. Very strange. Any clues as to why? #---------------- begin ------------------- # Version A. X axis labels have subscripts as constants. EPS is correct. windows() layout( matrix( 1:2 ,

Hey Duncan, Thank so much for the site. Quite helpful. Containing everything and informing me that raster has got no older version. I have also installed the new R version and I am fine. Regards Ogbos On 5 October 2010 15:11, Duncan Murdoch <murdoch.duncan@gmail.com> wrote: > On 05/10/2010 9:00 AM, ogbos okike wrote: > >> Hello, >> The R version on my system is R version

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

[Resend the stuff below since initial one has been blocked from R-help.] I have moved the "old" Matrix_0.98-7.zip to the main repository for the meantime. Best, Uwe Ligges -------- Original Message -------- Subject: Re: [R] no package 'Matrix' at the repositories Date: Fri, 11 Nov 2005 15:45:19 +0100 From: Uwe Ligges <ligges at statistik.uni-dortmund.de> Organization: