similar to: Simulating data (stupid question)

Sorry about the subject --- On Thu, 24/9/09, KABELI MEFANE <kabelimefane@yahoo.co.uk> wrote: From: KABELI MEFANE <kabelimefane@yahoo.co.uk> Subject: Re: [R] Multiply Normal Curves To: R-help@r-project.org Date: Thursday, 24 September, 2009, 11:48 AM R -helpers   i have been trying to do this problem without must success,i managed to do a graph for x, but it is not what i want to

R helpers   Please help me combine the simulated data to a form of table where: Hypermarket have 10 rows, supermarket have 15 rows,......., spazashops with 35 rows.   Hypermarket <- rnorm(10, mean=20000, sd=7000) Supermarket <- rnorm(15, mean=12000, sd=4000) Minimarket   <- rnorm(20, mean=10000, sd=4000) Cornershop  <- rnorm(20, mean= 8000, sd=3000) Spazashop   <- rnorm(35, mean=

Dear Helpers   I have a sample frame and i have sampled from it using three methods and now i want to calculate the statistics but i only get the population parameters.   H <- matrix(rnorm(100, mean=50000, sd=5000)) sampleframe=data.frame(type=c(rep("H",100)),value=c(H)) sampleframe   str=strata(sampleframe,c("type"),size=c(20,), method="srswor")

 Dear All   let me go one step further by asking you if you could help me show that the distribution of this data in normal.  have a little idea (by trial and error) but i seem to not fully understand how its done.   H<-rnorm(100, mean=50000, sd=3000) par(las=1) hist(H, breaks=seq(40000, 60000, 1000), freq=F) f<- function(x) exp(-(x-5000)^2/18000000)/sqrt(18000000*pi)  x<- seq(40000,

R -helpers   i have been trying to do this problem without must success,i managed to do a graph for x, but it is not what i want to define. I have also been able to do simple rendom sample. If possible can someone help here is the code for the graph pleae help   data.frame(ID=c(1,2,3),mu=c(10000,34000,50000),sigma=c(2000,3000,5000)) curve(dnorm(x,mean=parms$mu[1],sd=parms$sigma[1]),from=2000,

R-list   I am sorry for asking this stupid question, but i have been running in circles. I want to randomly generate a scaling point of between 1 and 10, for say hundred entries, where the first 10% percent is has rates between 2 and 7, the next 15% 3 and 7, 20% between 3 and 9, 20% between 3 and  10, 35% between 5 and 10. The problem is that i can only generate the usual 100 using runif function

Dear All   I know that you do not have to help me (as this is not a pure R problem) but please do, i am new to R as a CPI compiler, i just need to do a sample to see which sampling method best works in different situations, therefore since this is for practice purposes nobody will finance a real project thats why i need you to help me direct me as to how simulate data (just direct me,not 100%

Dear All   I hope you can help me with this small problem. I want to draw a normal distribution line to this data: p<-rnorm(100, mean=50000, sd=3000) hist(p)   Kabeli [[alternative HTML version deleted]]

Dear All   I know that you do not have to help me (as this is not a pure R problem) but please do, i am new to R as a CPI compiler, i just need to do a sample to see which sampling method best works in different situations, therefore since this is for practice purposes nobody will finance a real project thats why i need you to help me direct me as to how simulate data (just direct me,not 100%

Dear all I'd like to make a beeping sound in R, but alarm() doesn't beep? I checked ?alarm but I couldn't find any pointers to system configuration. Any ideas? Regards Liviu > sessionInfo() R version 2.14.2 (2012-02-29) Platform: x86_64-pc-linux-gnu (64-bit) locale: [1] LC_CTYPE=en_US.UTF-8 LC_NUMERIC=C [3] LC_TIME=en_US.UTF-8 LC_COLLATE=en_US.UTF-8 [5]

Dear all, I installed the amd64 cran2deb [1] JGR binaries on a fresh Debian testing, and JGR is missbehaving. When JGR starts up, one core of the CPU goes to 100% and stays there, even though I am keeping it idle and not performing any operation. I tried JGR with both sun-java6-jdk and openjdk-6-jdk, debian-liv:/home/liviu# update-alternatives --config java There are 4 choices for the alternative

Dear all, Given the following vector: > (z <- c('R project', 'hello world', 'something Else')) [1] "R project" "hello world" "something Else" I know how to obtain all capitals or all lower case letters: > tolower(z) [1] "r project" "hello world" "something else" > toupper(z) [1] "R

Dear all This may be obvious, but I cannot get it working. I'm trying to subset & sort a data frame in one go. x <- iris x$Species1 <- as.character(x$Species) ##subsetting alone works fine with(x, x[Sepal.Length==6.7,]) ##sorting alone works fine with(x, x[order(Sepal.Length, rev(sort(Species1))),]) ##gets subsetted, but not sorted as expected with(x, x[(Sepal.Length==6.7) &

Dear R users I would like to do some spreadsheet style expansion of dates. For example, I would need to obtain a vector of months. I approached in an obviously wrong way: > paste(01:12) [1] "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11" "12" > as.Date(paste(01:12),

Dear all I'm unable to find an example of extracting the rotated scores of a principal components analysis. I can do this easily for the un-rotated version. data(mtcars) .PC <- princomp(~am+carb+cyl+disp+drat+gear+hp+mpg, cor=TRUE, data=mtcars) unclass(loadings(.PC)) # component loadings summary(.PC) # proportions of variance mtcars$PC1 <- .PC$scores[,1] # extract un-rotated scores of

Dear all Is there any R function that would perform currency conversion using up-to-date exchange rates? I would be looking for a function that allows to download recent exchange rates (say, from Yahoo!) and then use these in converting currencies (say, USD to EUR). I am not sure whether r-sig-finance would be more appropriate, but the (off-)topic feels general enough to me. Thank you Liviu --

Dear all How does one convert a "non-symmetric" list to a vector? See below: > x <- list() > x[[1]] <- letters[1:5] > x[[2]] <- letters[6:10] > x[[3]] <- letters[11:12] > x [[1]] [1] "a" "b" "c" "d" "e" [[2]] [1] "f" "g" "h" "i" "j" [[3]] [1] "k"

Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",

Hi all, I recently started learning about Forex and found this O'Reilly book in Barnes & Nobles about R. I bought it out of pure curiosity. I like what I see. However, I have a question. Has anyone tried to bring these two ideas together in a financial and trading sense? Are there any libraries or modules in R that can aid in this venture? --Yves [[alternative HTML version

Dear all I would like to start R with Rcmdr from the cli, without tweaking Rprofile.site. This has been discussed in the past [1], but I don't see a solution that (1) could be used with any working directory and (2) would avoid starting Rcmdr on every R start-up. Personally I tried the following, which starts R but not Rcmdr liv at liv-laptop:~$ R --interactive -e 'require(Rcmdr)'