similar to: Combining matrices

Say I have a dataframe like this: df <- data.frame(cbind(c(1,0,0,1),c(0,1,0,0),c(0,0,1,0))) names(df) <- c('a','b','c') I would like to create a factor in a new column, where the factor values are taken from the column names, like this: > df2 a b c f 1 1 0 0 a 2 0 1 0 b 3 0 0 1 c 4 1 0 0 a How would I do this? Thanks, Dan Daniel Nordlund Bothell, WA USA

Dear Daniel and Jorge, Thank you very much and it does help. If I have a string "ABCD", how can I access the second element of the string "B"? Thanks, Miao 2012/7/27 Daniel Nordlund <djnordlund@frontier.com> > > -----Original Message----- > > From: r-help-bounces@r-project.org [mailto:r-help-bounces@r-project.org] > > On Behalf Of jpm miao

Hi, The page http://cran.r-project.org/bin/windows/base/rtest.html has a link to: http://cran.r-project.org/bin/windows/base/R-2.15.0rc-win.exe However, clicking on that link gives a 404 "Object not found' error. FYI. Dan

Has anyone heard whether Revolution Analytics is going to release this capability to the R community? http://www.businesswire.com/news/home/20110201005852/en/Revolution-Analytics-Unlocks-SAS-Data Dan Daniel Nordlund Bothell, WA USA

I am using R-2.10.1 binary from CRAN on a WinXP Pro system. I also use SAS v9.2 on the same box. I just started using the SAS ODBC driver that comes with version 9 of SAS. I have been able to set up an ODBC source for SAS datasets using the driver, and then with RODBC I am able to read a sample SAS dataset. > library(RODBC) > ch <- odbcConnect('sasodbc', believeNRows=FALSE)

Hello! I have a data set: set.seed(123) y<-data.frame(week=seq(as.Date("2010-01-03"), as.Date("2011-01-31"),by="week")) y$var1<-c(1,2,3,round(rnorm(54),1)) y$var2<-c(10,20,30,round(rnorm(54),1)) # All I need is to create lagged variables for var1 and var2. I looked around a bit and found several ways of doing it. They all seem quite complicated - while in

Hello all Is there a method/package in R in which I can do regressions for more than 50 independent variables ? Regards The woods are lovely, dark and deep But I have promises to keep And miles before I go to sleep And miles before I go to sleep ----- [[alternative HTML version deleted]]

R users, I am trying to generate a randomized weekday survey schedule that ensures even coverage of weekdays in the sample, where the distribution of variable DOW is random with respect to WEEK. To accomplish this I need to randomly sample without replacement two weekdays per week for each of 27 weeks (only 5 are shown). However, I need to sample from a sequence (3:7) that needs to be

Dear all I'm using Xubuntu Lucid and I keep getting the same random numbers whenever I start a new session of R. For example, I keep getting > sample(1:1000, 1) [1] 87 or > rnorm(1:10) [1] -1.3618103 0.4241701 1.0720076 0.2208145 -0.5375314 -0.4846588 [7] 0.7576768 0.6527407 -0.6868786 0.8718527 I expected that some set.seed() instruction woudl be present in a config file in

Heja, I hope someone is still there to help me: How can I somehow merge/combine matrices to get such a result: Matrix A A B x1 1 0 x2 1 1 Matrix B C D x3 1 0 x4 0 1 Resulting Matrix? A B C D x1 1 0 0 0 x2 1 1 0 0 x3 0 0 1 0 x4 0 0 0 1 Does anyone see this probably obvious solution with R how to do this? Sorry if this question is silly...it's too hot here to think properly ;O)

Hey everyone, I am at best, an amateur user of R, but I am stuck on how to set-up the following situation. I am trying to select a random sample of numbers from 0 to 10 and insert them into the first column of a matrix (which will used later in a loop). However, I need to have those numbers add up to 10. How can I set those conditions? So far I have: n<-matrix(0,nr=5,ncol=10) for(i in

Hello, I am trying to learn how to perform Multiple Regression Analysis in R. I decided to take a simple example given in this PDF: http://www.utdallas.edu/~herve/abdi-prc-pretty.pdf I created a small CSV called, students.csv that contains the following data: s1 14 4 1 s2 23 4 2 s3 30 7 2 s4 50 7 4 s5 39 10 3 s6 67 10 6 Col headers: Student id, Memory span(Y), age(X1), speech rate(X2) Now

Could someone please suggest a more clever solution to the following problem than my loop below? Given X a 2xN matrix X, and I a k-subset of N, Generate the (2^k)xN matrix Y with columns not in I all zero and the other columns with all choices of an entry from the first or second row of X. For example, with X <- matrix(1:8, nrow=2) I <- c(1,3) X is 1 3 5 7 2 4 6 8 and Y should be 1 0 5

Hi, I have a dataframe (say myData) and want to get a list (say myList) that contains a matrix for each row of the dataframe myData. These matrices are calculated based on the corresponding row of myData. Using a for()-loop to do this is very slow. Thus, I tried to use apply(). However, afaik apply() does only return a list if the matrices have different dimensions, while my matrices have

I am trying to work my way through the book "Singer, JD and Willett, JB, Applied Longitudinal Data Analysis. Oxford University Press, 2003" using R. I have the SAS code and S-Plus code from the UCLA site (doesn't include chapter 8 or later problems). In chapter 8, there is a structural equation/path model which can be specified for the sem package as follows S <- cov(al2)

Hi, I need to compare two matrices with each other. If you can get one of them out of the other one by resorting the rows and/or the columns, then both of them are equal, otherwise they're not. A matrix could look like this: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 0 1 1 1 0 1 1 0 [2,] 1 1 0 0 0 1 0 1 [3,] 1 0 1 0 0

Hello, I wanted to ask help about importing sas datasets. 1)I tried with some functions as read.ssd (foreign package), but it doesn't import the file if the length of the variables' names are longer than 8 bite (it has to conform to the 6 version). 2)I then tried with the sas.get function (Hmisc package) but with the command: c<- sas.get(lib="c:\\ghan",

Hi everyone. Newbie to statistics. I have 40 matrices of ~400 values. how may I determine whether the distribution follows zips law? response <-sample (1:20,400*4, replace= TRUE) Thank you vry much. -- View this message in context: http://r.789695.n4.nabble.com/A-introductory-question-about-Zips-law-Newbie-to-statistics-tp4521190p4521190.html Sent from the R help mailing list archive at

Dear all r-users, I am getting a big problem with matrix multiplication suppose I have, > weight Weight 1 1067640 2 8871500 3 42948778 4 127583735 5 22000000 6 44000000 7 56850000 8 23805662 and, > s a b c d e f g h a 402493.18 -133931.62 461483.3 -94042.86 674493.8

Hi, I wish to create a series of plots with the same x-axis range and the same placement of tick marks. In addition I want to force the tick marks to be at specific locations. For example, if I wish to have an x-axis which goes from 40 to 110, with tick marks at 40, 50, 60, ... , How can I accomplish that? The various parameters I have tried changing just seem to be suggestions for