similar to: Factor

Good day to you all, I have lightning data containing date, time, latitude and longitude. I hope that distribution of latitude and longitude will give number of lightning occurrence in a region. I have used factor function to sum up the number of events on latitude and longitude axis and saved as x and y. But when I tried to plot the two, I had and error message ( Error in image.default(x, y, z) :

Dear All, I have a script that draws longitude and latitude of lightning occurrence. This script was running fine before. But when I changed my system and do a fresh install on another laptop, this error persist. source("script") Error in eval(expr, envir, enclos) : could not find function "pointsToRaster" I have tried to see if there is any other package I need to install

Hi, A terrific resource for this type of issue (and pretty much anything related to R) is http://rseek.org/ I'm sure I use it at least daily. Check out ... http://rseek.org/?q=pointsToRaster The first hit is about pointsToRaster() - it has been replaced by raster::rasterize() Cheers, Ben > On Apr 30, 2016, at 4:28 AM, Ogbos Okike <giftedlife2014 at gmail.com> wrote: > >

Hi everybody, I have a huge longitude and latitude data. I have used raster package to get the since of its global distribution. But I wish to display the information using a few points on the world map. The data is of the form: 95.2156 0.8312 -65.3236 -3.3851 -65.2364 -3.2696 -65.2349 -3.2679 164.7025 -17.6404 148.8214 -4.8285 -67.6568 2.6477 -73.4833 -0.2350 40.9587 -16.8655 -61.6474 8.1179

Hi Ogbos, Here is your sample data plotted in roughly the same way as the image. You can get the hours to start at the bottom, but it will require more code. swe$hour<-as.numeric(sapply(strsplit(swe$time,":"),"[",1)) swe$FD<-sample(1:2,nrow(swe),TRUE) library(plotrix) clock24.plot(swe$count,swe$hour,rp.type="s",radial.lim=c(3000,4010),

Hi all, I need a little help for construct an state's map on R. The first problem is to get the data. I have a datafile of longitude and latitude in the follow format: trajectory latitude longtude T -22.045618 -51.287056 T -22.067078 -51.265888 T -22.067039 -51.207249 T -22.059690 -48.089695 T -22.075529 -48.074608 T -22.072460 -48.044472 T -22.062767 -48.298473 T -22.077349

?s 01:43 de 29/03/2024, Ogbos Okike escreveu: > Dear Rui, > Thanks again for resolving this. I have already started using the version > that works for me. > > But to clarify the second part, please let me paste the what I did and the > error message: > >> set.seed(2024) >> data <- data.frame( > + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1

Dear Rui, Thanks again for resolving this. I have already started using the version that works for me. But to clarify the second part, please let me paste the what I did and the error message: > set.seed(2024) > data <- data.frame( + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1 days"), 100L, + TRUE), + count = sample(10L, 100L, TRUE) + ) > > # coerce

Hello R-helpers, I am trying to search for string that includes the caret symbol, using the following code: grepl("latitude^2",temp) And R doesn't like that. It gives me: > temp<-c("latitude^2","latitude and latitude^2","longitude^2","longitude and longitude^2") > temp [1] "latitude^2" "latitude and

Dear all, Using the code I got from the link ( http://www.phaget4.org/R/image_matrix.html), I obtained a nice plot that suits me. However, adding axes labels proved difficult for me . I have succeeded in adding a few things to the plot function so as to get what a better plot. Other things work but ylab="days" did not reflect. It will be great if somebody can advice on how to add axes

Hi list, I have a problem to solve which I believe I shoudl use the convolve to solve it, but I could not figure out how to do it. I got mydata, which is a dataframe which has 7 locations, each location has a longitude,latitude and a value. considering a step of 0.5 degree for longitudes and latitudes, I got 15 points for longitude and 15 points for latitude. Then I created a grid, mygrid, which

Dear R Users, I am using the reshape package to reformat gridded data into column format using the code shown below. However, when I display the resulting object, a single column is fomed (instead of three) and all the latitude values (which should be in either column one or two) are collected at the bottom. Also, the NA values aren't removed, despite this being requested in the code. Code:

Hi, i am using spatstat package for spatial data analysis and now i have a problem to create a point pattern. The points are in file "points.txt" (first column for Latitude and second column for Longitude ) and I imported them and separated each columns in two arrays x and y. If I plots x and y ( e.g plot(x,y) ) the result appears in square area without problems and the scale is

Hi Uwe, I am pleased to inform you that this problem has, following your hint, been resolved. I installed 64-bit version of R and I was alright. Thanks again for your time. Ogbos 2009/6/24 Uwe Ligges <ligges@statistik.tu-dortmund.de> > > > ogbos okike wrote: > >> Hi, >> I have a data of size 981.1MB(1028707715) and I intend to calculate the >> length of the

Hi Everyone, I am new to R Language and was wondering if someone could help me convert my latitude-longitude coordinates to cartesian coordiantes using geoXY() from SoDA package? I have been uploading my coordinates from a text file into R (they originate as a dataframe) and them converting them to a matrix using the data.matrix() function. But I think I'm running into trouble when I try to

Dear R-Helpers, Is there a way to draw shaded (filled) polygons in panel graphs produced by xyplot ? I made different trials (see below) with polygon() and grid.polygon() but polygons are not drawn (probably for the same reason that prevents the use of lines, points, etc. in xyplot panels). Thanks in advance, Renaud > Water id label longitude latitude 515 21 Zone inondable

I have 100 data files, which contains very huge data sets of location details ( e.g latitude, longitude, time, temp) Now I would like to save the all data of these 100 files in r object, so I can reload data any time. * Every file has different length of data latitude <- NULL longitude <- NULL time <- NULL temp <- NULL for ( i in 1:100) { data<-

Dear all, I have a grid of 720 columns by 360 rows of global population density values, and hope to convert this to column format using the 'melt' command in the 'reshape' package. I'm not receiving any errors as such, but when the code has finished running, my output looks like this: > head(PopDens.long) Latitude Longitude PopDensity 1 -84.75 V1 0 2

Dear all, I am trying to use 'merge' within a loop, however, I receive an error relating to the 'by' argument of the command, as follows: > merge_year <- 1986 > > for (i in 1:10) { # Number of file pairs + assign(paste("merged_arunfek_", merge_year, sep=""), merge(x=paste("arunoff_",start_arunoff, sep=""),

Dear everyone, as a newbie I fear I have made an easy mistake and am just too blind to see it. Can anyone help me seeing the (possibly) obvious? I have a command that creates a map of South America. In a separate txt-file I stored data about latitude and longitude of languages, and in a third column values that differ from language to language. The command should read that file and assign the