similar to: inserting into data frame gives "invalid factor level, NAs generated"

Displaying 20 results from an estimated 2000 matches similar to: "inserting into data frame gives "invalid factor level, NAs generated""

2000 Nov 25
2
assigning to data frames with whole columns of NAs
I suppose this could be described as a feature (it seems to be similar in S-Plus), but it looks to me more like a bug. Why can't the assignment below to a row of "emptyframe" (or "anotherframe") be made? This with R --vanilla (version info below). Regards -- David David Firth Phone +44 1865 278544 Nuffield College Fax +44 1865
2020 Aug 11
2
clarifying the handling of responses for virtio-rpmb
Hi, The specification lists a number of commands that have responses: The operation of a virtio RPMB device is driven by the requests placed on the virtqueue. The type of request can be program key (VIRTIO_RPMB_REQ_PROGRAM_KEY), get write counter (VIRTIO_RPMB_REQ_GET_WRITE_COUNTER), write (VIRTIO_RPMB_REQ_DATA_WRITE), and read (VIRTIO_RPMB_REQ_DATA_READ). A program key or write
2008 Feb 18
3
tabulation on dataframe question
I have a data frame with data similar to this: NameA GrpA NameB GrpB Dist A Alpha B Alpha 0.2 A Alpha C Beta 0.2 A Alpha D Beta 0.4 B Alpha C Beta 0.2 B Alpha D Beta 0.1 C Beta D Beta 0.3 Dist is a distance measure between two entities. The table displays all to all distances, but the
2007 Oct 01
3
"continuous" boxplot?
I have two vectors x and y, which I would like to plot against each other. I am also displaying other data in this plot. However, I have about 1 million points to plot, and just plotting them x againt y is not very informative. What I'd like to do is to do sort of a continuous box plot. My x values goes from -1 to 1 and my y values from 0 to 1, so I?d like to plot the median and quantiles,
2012 Aug 27
3
Changing entries of column of type "factor"/Adding a new level to a factor
What is a smart way to change an entry inside a column of a dataframe or matrix which is of type "factor"? Here is my script incl. input data: > #set working directory: > setwd("K:/R") > > #read in data: > input<-read.table("Exampleinput.txt", sep="\t", header=TRUE) > > #check data: > input Ind M1 M2 M3 1 1
2009 Apr 15
1
performing function on data frame
Hi! First, pardon me if this is a faq. I think I should be using some sort of apply, but I am not managing to figure those out. I have a data frame similar to this: > d <- data.frame(x = LETTERS[1:5], y = rnorm(5), z = rnorm(5)) > d x y z 1 A 0.1605464 -0.2719820 2 B -0.9258660 1.2623117 3 C -0.3602656 1.5470351 4 D 1.2621797 1.2996500 5 E 0.6021728 0.5027095
2011 Mar 29
3
producing histogram-like plot
Hi! I have a dataset that looks like this: 0.0 14 0.0 3 0.9 12 0.73 15 0.78 2 1.0 15 0.3 2 0.32 8 ...and so on. I.e. a value between 0 and 1, and a number I would like to plot this in a histogram-like manner. I would like to have a set of bins, each 0.1 wide, and plot the sum of values in column 2 that falls within each bin. I.e, in this case I would like the first bin, 0.0, to have the
2008 May 21
1
problems with data frames, factors and lists
I have a function that creates a list based on some clustered data: mix <- function(Y, pid) { hc = gethc(Y,pid) maxheight = max(hc$height) noingrp = processhc(hc) one = noingrp$one two = noingrp$two twoisone = "one" if (two != 1) twoisone = "more" out = list(pid = pid,one = noingrp$one, two = noingrp$two, diff = maxheight, noseqs = length(hc$labels), twogrp = twoisone)
2007 Sep 19
2
function on factors - how best to proceed
Sorry about this one being long, and I apologise beforehand if there is something obvious here that I have missed. I am new to creating my own functions in R, and I am uncertain of how they work. I have a data set that I have read into a data frame: > gctable[1:5,] refseq geometry X60_origin X60_terminus length kingdom 1 NC_009484 cir 1790000 773000 3389227 Bacteria 2
2005 Jun 23
1
Stop Warnings for Invalid Factor Level, NAs generated?
How can I stop the following warning from occuring? invalid factor level, NAs generated in: "[<-.factor"(`*tmp*`, iseq, value = structure(1, .Label = "12", class = "factor")) The Label messages are for "5", "8", "12" and "46". I want the NAs to be generated as needed. Is this causing R to slow down by generating the warning
2008 Feb 26
1
combine vector and data frame on field?
I have managed to create a data frame like this: > tsus_same_mean[1:10,] PID Grp Dist PercAln PercId 1 12638 Acidobacteria 0.000000000 1.0000000 1.0000000 2 87 Actinobacteria 0.000000000 0.9700000 0.9700000 3 92 Actinobacteria 0.008902000 1.0000000 0.9910000 4 94 Actinobacteria 0.000000000 1.0000000 1.0000000 5 189 Actinobacteria 0.005876733
2008 Mar 10
1
hclust graphics - plotting many points
Hello. I have a distance matrix with lots of distances that I use hclust to organise. I then plot the results using the plot method of hclust. However, the plot itself takes around 20 mins to make due to there being ~700 things in the matrix that I have distances for. I thus would like to dump this to some graphics format which will let me examine this further. I tried dumping it to postscript:
2007 Oct 11
1
creating summary functions for data frame
I have a data frame that looks like this: > gctablechromonly[1:5,] refseq geometry gccontent X60_origin X60_terminus length kingdom 1 NC_009484 cir 0.6799 1790000 773000 3389227 Bacteria 2 NC_009484 cir 0.6799 1790000 773000 3389227 Bacteria 3 NC_009484 cir 0.6799 1790000 773000 3389227 Bacteria 4 NC_009484 cir 0.6799
2010 Nov 10
1
plotting histograms/density plots in a triangular layout?
Hi! I have a set of 49 pairwise comparisons that I have done. From this I would like to plot either histograms or the density plots of the values I get. Now, I can plot one histogram per comparison, but I have problems getting the output I want. When plotting like I normally would do: histogram(~percid | orgA_orgB, data = alldata) I get the histograms next to eachother in a boxlike shape.
2008 Jun 05
5
vector comparison
I know this is fairly basic, but I must have somehow missed it in the manuals. I have two vectors, often of unequal length. I would like to compare them for identity. Order of elements do not matter, but they should contain the same. I.e: I want this kind of comparison: > if (1==1) show("yes") else show("blah") [1] "yes" > if (1==2) show("yes") else
2008 Jun 21
2
using the stepfun to plot histogram outline.
Hello list:) I have lots of values which I would like to get a histogram outline out of. An example of what I am talking about: testdata = runif(100) bbb = seq(0,1, by = 0.01) hist(testdata, breaks = bbb) I would like to get the outline of the resulting histogram. Now, I think that I can do this using the stepfun function. However, I am uncertain of how to get to the data the stepfun function
2008 Aug 05
1
xyplot key issue - line colors
I have a problem regarding the colors assigned to the lines in the key to an xy plot. I specify the plot like this: xyplot(numbers~sqrt(breaks)|moltype+disttype, groups = type, data = alldata, layout = c(3,2), type = "l" , lwd = 2, col = c("gray", "skyblue"), key = simpleKey(levels(alldata$type), points = FALSE, lines = TRUE, columns = 2, lwd = 2,
2011 Apr 12
2
Assign Character Value to Data Frame
Dear R Helpers, I am trying to write a character value to the row of a data frame and am running into a problem that I don't have when I do this for numeric arguments. For example, the following works just fine: > test<-data.frame(number=numeric(1)) > test[1,]<-.5 > test number 1 0.5 But the following bombs out: > hold<-data.frame(symbol=character(1)) >
2018 Apr 18
3
How to replace numeric value in the column contains Text (Factor)?
Hi R user, Would you mind to help me on how I can change a value in a specific column and row in a big table? but the column of the table is a factor (not numeric). Here is an example. I want to change dat[4:5,3]<-"20" but it generated NA> do you have any suggestions for me? dat<-structure(list(Sites = structure(1:5, .Label = c("Site1", "Site2",
2005 Jul 07
1
manupulating a data frame column
Could someone tell me how to fix the following error? It looks like that the reason is that df$x is of the class "factor". Thanks! > x1<-LETTERS[1:8]; x2<-letters[1:8]; x1[2]<-NA; x1[4]<-NA; > df<-data.frame(x1=x1, x2=x2) > idx<-which(is.na(df$x1)) > df[idx,1]<-df[idx,2] Warning message: invalid factor level, NAs generated in: