similar to: How do I plot a line followed by two forecast points?

Suppose I create an R program called myTest.R with only one line like the following: type <- as.integer(readline("input type (1: type1; 2: type2)? ")) Then I'd like to run myTest.R in batch mode by constructing an input file called answers.R with the following: source("myTest.R") 1 When I ran the following at the terminal: R CMD BATCH answer.R output.Rout it failed

R-Help community, I understand that data.frames can hold elements of type double, string etc but NOT objects (such as a matrix etc). This is not convenient for me in the following situation. I have a function that takes 2 inputs and returns a vector: testfun <- function (x,y) seq(x,y,1) I have a data.frame defined as follows: testframe<-data.frame(xvalues=c(2,3),yvalues=c(4,5)) I would

1. This is an imaginary data on monthly outcomes of 2 years and I want to forecast the outcome for next 12 months of next year. data Data1; input Yr Jan Feb Mar Apr May June July Aug Sept Oct Nov Dec; datalines; 2008 12 13 12 14 13 12 11 15 10 12 12 12 2009 12 13 12 14 13 12 11 15 10 12 12 12 ; run; I converted the above data into the below format to use it in R as it was giving error: asking

Dear All, I wonderif there is a simple way to draw a regression line in the xyplot: more specifically, let: age <- c(20:30, 31:40 ) age.cut <- cut(age, breaks = 2 ) y<- rnorm(20) x <- rnorm(20,4,1) xyplot(y ~ x| age.cut, xlab="x", ylab="y") How to draw (in the plot given by xyplot) the two regression lines (y ~ x) corresponding to the two category

Hi, I am using the package "demography" from Rob Hyndman for the Lee-Carter-Model. It is an amazing powerful tool but I am struggling with one issue: I want to compute different percentiles of the survival probability distribution derived from the Lee-Carter-Forecast (e.g. the 50%tile, 60%tile, 75%tile and 99%tile) for each of the next 10 years. Is there any possibility to retrieve

panel.lmline returns intercept and slope of y ~ x subsetted to the combination of conditioning factors given to xyplot in lattice. for instance: xyplot(Xvalues ~ log(Qvalues)|Tfac, data = df7, panel = panel.lmline) I am looking to find the equivalent formulation for lm() proper. If I do this: lmcal <- lm(Xvalues ~ log(Qvalues):Tfac, data = df7) Only one value of the intercept is returned.

Hello, I am trying to alter the way in which lattice functions (specifically xyplot) print the axis labels when one uses the 'scales' parameter. I can obtain the effect I want by using scales=list(y=list(log=10, labels=expression(yvalues))) where yvalues are the values that would have been printed as the y-axis labels if the "labels" argument had not been present. To help

Hi All, I try to do a scatterplot for a bunch of variables. I plot a dependent variable against a bunch of independent variables: -- cut -- graphics::plot( v01_r01 ~ v08_01_up11, data = dataset, xlab = "Dependent", ylab = "Independent #1" ) -- cut -- It is tedious to repeat the statement for all independent variables. Found an alternative, i.e. : -- cut -- mu

Hello everyone, I would like to create a "dynamic" array to keep storing number in it for (i in c(2:length(final))){ myarray <-final[i]-final[i-1] myarray2<-2*final[i] } At the end I would like to use myarray as the x values of an array and the myarray2 as the yvalues of the same array. I tried cbind but it didnot work. Could you please help me with that? Best

Dear All, Does anyone know how to get the maximum/minimum value of a function using R, I think there should be an instruction, but i can not find it in help files Thank you in advance for your help :) [[alternative HTML version deleted]]

Hi, I try to create a vertical line in my plot, which has a xaxis comprising time formated data. This is what I tried: ---------------- y<-152833 x<-strptime(y, format="%H%M%S") abline(v=x, col="red") ---------------- for some reason, it doesn't work and no error msg is displayed... I hope someone can tell me what I do wrong, or maybe an alternative. Thanks

I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927

Hello! I used to save R-Grafics like this: postscript("file.ps"). Is there alsoa way to save them as eps? Thank you very much Claudia

Hi, I am using R on Windows XP. I am using 'arrows' funtion to plot the variance as error bar, BUT error bar goes only one side of the data point, I need to plot the error bar on both side of the data point (plot is attached), I am using following commands to plot, plot(file3$lat,file3$STotwoKm,pch=21,cex=2.5,ylim=c(-0.2,2.5),xlim=c(-50,50),xlab=NA,ylab=NA, col=1,

Hi R-users! I'm trying to create an easy Excel chart using the package RDCOMClient. The following example is working fine: #------------------------------------------------------------------- library(RDCOMClient) xlLocationAsObject <-2 xlXYScatterSmoothNoMarkers <- 73 ex <- COMCreate("Excel.Application") wb <- ex[["Workbooks"]]$Add() sh <-

Dear all, I am using the following code to write the plot to an eps format postscript(file="test.eps",horizontal=FALSE)

Dear All: I have succeeded in fitting a GAMLSS.dist model to growth data I am working with it. My aim is to create a matrix of predicted percentiles and the corresponding the fitted model's sigma mu nu by agebins. Q: How do it generate these parameters as in L M S per Cole and Green 1992? Here are my working codes. Name of fitted model is gamlssfit > Agebin<-seq(6,36,6)

Hola, Esta es una forma de hacerlo... Mira que lo primero que he modificado es el fichero "x.csv" para sustituir los espacios en los nombres por "_". Y también he quitado los acentos y las eñes... He utilizado el paquete RNNS y la función "mlp()" para ajustar la red. #------------------------------------------- > x <- read.csv("x.csv",

It''s been a few days since I posted my last two emails (of which, no one replied to) so I''ve gone ahead and coded a working slider class as well as a ''resizeable'' class that allows a user to drag and resize the element. I also linked these two together as I want to have slider behavior that can resize the resizeable element. The end result is both the

Estimados Les consulto por redes neuronales, hay diversos artículos como los siguientes (el último tienen un error actualmente). Pero mi pregunta va un poco por otro lado. http://www.r-bloggers.com/build-your-own-neural-network-classifier-in-r/ http://www.r-bloggers.com/classification-using-neural-net-in-r/ Básicamente se puede calcular un valor, por ejemplo doblar 2,4 grados a la derecha, luego 1