similar to: random between two values

I would raise x,y and z in a loop but I won't raise of 1. I tried this but it doesn't work mydata=matrix(nrow=1500,ncol=3) i=1 for(x in 0:10){ for(y in 0:20){ for(z in 0:10){ mydata[i,]=c(x,y,z) i=i+1 z=z+2} y=y+4} x=x+2} And I would have something like that x y z 0 0 0 0 0 2 0 0 4 0 0 6 0 0 8 0 0 10 0 4 0 0 4 2 ... Could anybody help me? I

Hi, I would know how to plot two variograms on a same graph. I can plot one by one but I would draw both on the same one. Is it possible? Do i need any special package? Thanks! Cordialement Damien Landais

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Hi all, I need to compute some "occurence matrix": given a zero matrix and a set of paired indexes, I want to store the number of occurences of each paired index in a matrix. The paired indexes are stores as an index matrix. I prefere not to use loops for performances purpose. Here follows a dummy example: > occurence <- matrix(0, 2, 2); data [,1] [,2] [1,] 0 0

Hi I'm using R(2.9.0) and gstat package under Windows to plot sample variograms. When I want to fit them, I don't have the possibility to choose Cauchy functions. Under Mathematica for example, we have it and it seems to be the best one to fit the variograms I have I tested the others functions, they can fit but I would,if possible, use the Cauchy one. If anybody knows something about

Dear Rsync Users, Please can I have a bit of rsync advice? I am trying to rsync a file called. 'Draft text - with Holley comments.doc' from machine a to machine b. Unfortunately this isn't working because I think rsync recognises the - character and thinks it's an option. I have tried escaping this out as well as putting it all in " " but neither seems to work

*** APOLOGIZES FOR THOSE READING THE LIST THROUGH NABBLE THIS WAS ALREADY POSTED THERE BUT NOT FORWARDED TO THE LIST FOR SOME UNKNOWN REASON *** I have a dataset that looks like: $ V1: factor with 4 levels $ V2: factor with 4 levels $ V3: factor with 2 levels $ V4: num (summing up to 100 within V3 levels) $ V5: num (nr of cases for each unique combination of V1*V2*V3 levels) Quite new to

Hello, As the author of package cts, I hope somebody on this list can kindly help (perhaps off-list) to resolve the build/check issue with package cts for Mac. The error occurred on Mac machines only: http://cran.r-project.org/web/checks/check_results_cts.html. Here is the error message: At line 10 of file machine.f Fortran runtime error: Range error during floating point read The source

Dear R-help, Has anyone implemented sparklines in the strips of a lattice plot? What I have in mind is, say, highlighting that part of a time series that one is examining in more detail in a set of lattice plots. Regads,. Mark Difford. PS: (Andreas Loffler has implemented a simple but functional version for TeX/LaTeX: http://www.tug.org/tex-archive/help/Catalogue/entries/sparklines.html)

Dear all, I'm working on some data from an experiment on the breeding behavior of birds. In short, I have been measuring how the time spent on performing a certain task (variable 'mean_on_active') differs over time (variable 'day', 2 levels) across three experimental categories (variable 'treat'; levels 'C', 'R', 'E'). The model shows a

Hi all, I've got a data frame that has an identical column to a chr vector. I would like to use the chr vector to order the rows of the data frame to be identical to the order in the chr vector (the contents of the chr vector are completely identical to one col of the data frame), but this is proving trickier than it sounds.. Any help would be much obliged, -Ken

Full_Name: Spinu Vitalie Version: 2.9.0 OS: Windows Submission from: (NULL) (130.115.113.15) In assignment of "zero length" names to data.frame: > tdf <- data.frame(rbind(c(1, 2), c(1, 2))) > names(tdf) <- c("", "") > tdf structure(c("1", "1"), class = "AsIs") structure(c("2", "2"), class =

Hi: I have a function as follows: my.plot <- function( x, y = NULL, ... ) { plot( x, y, cex.axis=0.5, ...) } Set up the variables: x <- 1:10; y <- x; tdf <- data.frame( x, y ); main.str <- "test" I will exercise the function in two ways: > my.plot( y ~ x, tdf, main = "test" ) This works fine > my.plot( y ~ x, tdf, main = main.str ) Error in

Hi, I am fairly new at Rails, and attempting to deploy an application that''s running fine using InstantRails on my PC. On the deployment server (I use railsplayground.net), I get the following error: Processing ApplicationController#index (for 220.224.229.156 at 2008-06-25 18:49:34) [GET] Session ID: 5921e7d789ee3aaa214f2d59aa40986a Parameters: {"action"=>:index,

Hello, I am trying to find the analytical solution to this differential equation dR/dt = k1*R (1-(R/Rmax)^k2); R(0) = Ro k1, k2, and Rmax are parameters that need to fitted, while Ro is the baseline value (which can be fitted or fixed). The response (R) increases initially at an exponential rate governed by the rate constant k1. Response has a S-shaped curve as a function of time and it

Is there a command for partial matching of character strings? Specifically, I'd like to be able to calculate the mean of the values in any columns in a data frame or matrix that have identity in part of their column names. For example, columns labeled "mpw06a" and "mpw06b" match on the first five characters; their mean would be taken whereas any columns beginning with

Hi, This is a very simple question I realise, but I hope maybe someone can just help me out. I am trying to do a very simple thing, just transfer a file from machine A to machine B using rsync with ssh. This is what i'm typing: bash-2.03# rsync -avvv --rsh="ssh -l tdf" tdf@machine.niss.ac.uk:/export/home/tdf/demofile.html demofile.html This is what I get: opening connection

Dear R-Helpers, I have a data.frame (df) and the head of data.frame looks like ProbeUID ControlType ProbeName GeneName SystematicName 1665 1577 0 pSysX_50_22_1 pSysX_50 pSysX_50 5422 5147 0 pSysX_49_8_1 pSysX_49 pSysX_49 4042 3843 0 pSysX_51_18_1 pSysX_51 pSysX_51 3646 3466 0 sll1514_0_2 sll1514 sll1514

Hello, I am trying to find the analytical solution to this differential equation dR/dt = k1*(R^k2)*(1-(R/Rmax)); R(0) = Ro k1 and k2 are parameters that need to fitted, while Ro and Rmax are the baseline and max value (which can be fitted or fixed). The response (R) increases initially at an exponential rate governed by the rate constants k1 and k2. Response has a S-shaped curve as a function

I think the code is part of the RTAQ package but is not included in it, as I obtained it from https://r-forge.r-project.org/scm/viewvc.php/pkg/RTAQ/R/HAR_model.R?view=markup&root=blotter&sortby=author&pathrev=1028. It is not my code and I make no claim to other's good work, and apologize if I should even be posting it I am not sure, but in the transform function it allows to