similar to: making scatter plot points fill semi-transparent

Dear R graphics experts, Do you know of any way of plotting semi-transparent points in R ? I face this problem any time I want to e.g. plot thousands of points that belong to two or three classes which I color code. With the default opaque colors, the plotting order matters and basically the points I plot last completely dominate the picture. I would much rather have the overlaying points

In a previous thread some people were interested in ways to sort a table. I mentioned a simple method for doing so by using links in the titles. Having actually tried to implement this strategy, I have come across several refinements that I would like to share. First... your table view should look like this... ... <table> <tr> <th><%= link_to

I have 2 mysql tables, Product and Color: Color ID ColorName 1 Red 2 Green 3 Yellow 4 Blue Products ID Color1 Color2 Color3 ProductName 1 ? ? ? Orco 2 ? ? ? Skeletor 3 ? ? ? He-Man I need to display the ColorName to

hi all, suppose I have a file with several columns, and I want to plot all points that meet a certain condition (i.e. all points in columns A and B that have a value greater than such and such in column C of the data) in a new but random color. That is, I want all these points to be colored differently but I dont care what color. The only concern is that the points will be colored as

There are a lot of ways to specify colours in R plot functions (number from the palette, by name, etc.). I'd like to pass a colour from an R function to an external function, and I'd like it to have the same flexibility. To avoid having to interpret all possible colour specifications myself, I need a function to convert a general colour specification into a standard form (e.g. r,g,b

Readers, I have entered a file into r: ,column1,column2 row1,0.1,0.2 row2,0.3,0.4 using the command: dataframe<-read.table("/path/to/file.csv",header=T,row.names=1) When I try the command: dataframe[,2] I receive the response: NULL I was expecting: row1 0.2 row2 0.4 What is my error with the syntax please? Yours, r251 mandriva2009

is there a smart way of determining the number of pairwise present data in a data matrix with missings (maybe as a by-product of some statistical function?) so far, i used several loops like: for (column1 in 1:99) { for (column2 in 2:100) { for (row in 1:500) { if (!is.na(matrix[row,column1]) & !is.na(matrix[row,column2])) { pairs[col1,col2] <- pairs[col1,col2]+1

Hello to all is there a function wich splits a data.frame (column1,column2,column3,....) into data1 <-(column1,column3....) #column2 = 1 data2 <-(column1,column3....) #column2 = 2 data3 <-(column1,column3....) #column2 = 3 ... Regards Knut

I am writing a custom function that uses an R-function from the reshape package: cast. However, my question could be applicable to any R function. Normally one writes the arguments directly into a function, e.g.: result=cast(table1, column1 + column2 + column3 ~ column4, mean) (1) I need to be able to write this statement as follows: result=cast(table1, string_with_columns ~

I am new to R, but have been using SAS for years. In this transition period, I am finding myself pulling my hair out to do some of the simplest things. An example of this is that I need to generate a new variable based on the outcome of several existing variables in a data row. In other words, if the variable in all three existing columns are "Yes", then then the new variable should

Hi, I have written boxplot commands of this form before, but I don''t quite understand why the function call is reporting a syntax error in this instance. All parameters passed to the function are strings. Thanks in advance. Payam > simplevar <- function(wframe,column1,column2) { + tframe <- get(wframe) + x1 <- which(names(wframe)==column1) + x2 <-

Apologies first, because I need to ramp up on Ruby and coding Ruby in Rails, however it''s my 3rd day with this beast :) so I''m asking : When I added protected methods to the model before it was like: protected method.................... end Would this be a valid way to write a protected method as well ?: attr_protected :column1, :column2 Perhaps this particular call

Hi ? I have a file. list.txt (two columns) ? column1??? column2 name??????? address ? ? I need to put in the letter file letter.txt eg: ? Dear: Chloe Address: CA ? Can I use this ? for i `cat list.txt` | sed 's/Chloe/$i.1; /CA/$i.2/g' $i.letter.txt ? Thank you for your help ? ? ? ? ? __________________________________________________________________ Looking for the perfect gift?

Hi, set.seed(45) test1<-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example probably similar to your actual data apply(test1,2,function(x) sprintf("%.1f",median(x))) #columnA columnB # "44.5"? "10.2" par(mfrow=c(1,2)) lapply(test1,function(x) {b<-

I am about to write general functions to read the output of simulations models. These model generate output files with different sections which I want to analyze plot etc. Since this will be used many people at the department I wanted to make sure that will do this in the best way. For instance I want to read a snippets of data from a text that look like this.

I couldn't find this in online help or the archives: Is there any R function or object giving the mapping of the colornames as given by colors() into the hsv() model? Regards -- Dr. Jens Oehlschl?gel-Akiyoshi MD FACTORY GmbH Bayerstrasse 21 80335 M?nchen Tel.: 089 545 28-27 Fax.: 089 545 28-10 http://www.mdfactory.de

I couldn't find this in online help or the archives: Is there any R function or object giving the mapping of the colornames as given by colors() into the hsv() model? Regards -- Dr. Jens Oehlschl?gel-Akiyoshi MD FACTORY GmbH Bayerstrasse 21 80335 M?nchen Tel.: 089 545 28-27 Fax.: 089 545 28-10 http://www.mdfactory.de

Hi, I have a data fram like this: date column1 column2 column3 value1 value2 value3 1-1 A B C 10 5 2 2-1 A B D 5 2 0 3-1 A B E 17 10 7 How can I reshape it to: date column1 column2 column3 v x 1-1 A B C value1 10 1-1 A B C value2 5 1-1 A B C value3 2 2-1 A B D value1 5 2-1 A B D value2 2 2-1 A B D value3 0 3-1 A B E value1 17 3-1 A B E value2 10 3-1 A B E value3 7 Thx! Regards, Richard

Hi there I have two dataframes Dataframe_1 column_1 colum_2 121 12345 145 1675 167 2765 Dataframe_2 column_1 column2 121 abc 345 lmn 167 efg I want a resulting dataframe 121 12345 abc 167 2765 efg how do i go abt it Ramya -- View this message in context: http://n4.nabble.com/Dataframe-help-tp947934p947934.html Sent from the R

Hi everyone, Hi want to separate the string(column1) for example column1 column2 column3 column4 column5 column6 bear b e a r cat c a t tiger t i g e r I know how to do this in excel where using MID function. Now I want to solve it using R. The list of strings is in