similar to: how to calculate time interval between dates

Hello, I have a set of data that has a Date column looks like this: 12/9/2007 12/16/2007 1/1/2008 1/3/2008 1/12/2008 etc. I'd like the date to look something like the follow (so that I could sort by date easily). 20071209 20071216 20080101 20080103 20080112 How to do it? Thank you very much Julia -- View this message in context:

Hello, I have a data set that looks like this. ID value 111 5 111 6 111 2 178 7 178 3 138 3 138 8 138 7 138 6 . . . I'd like to calculate the mean and var for each object identified by the ID. I can in theory just loop through the whole thing..., but is there a easier way/command which let me calculate the mean/var by ID? Thanks, Julia -- View this

Dear R users, I am building a hierarchical model on a large data set. It can take quite some time to finish one fit, I was just wondering whether it is possible to store the fit object (the result) to a file for later (offline) analysis. thanks Julia -- View this message in context: http://www.nabble.com/how-to-store-lme-lmer-fit-result-tp19910951p19910951.html Sent from the R help mailing

Hello, I have a data file (.csv) that has a size of about 2.6 GB. I am not able to read in the whole data set because of the memory limit. I actually only need some columns (3 columns) of the data set, is there a way to read in specified columns? I am using windows. Thanks, Julia -- View this message in context:

Dear R users: I have a data set that looks something like this: ID time y 1 2/01/2008 4 1 2/09/2008 12 1 9/01/2008 8 2 1/06/2008 3 2 3/01/2008 4 2 3/09/2008 9 2 6/03/2008 4 3 1/02/2008 3 3 1/10/2008 8 3 2/02/2008 7 3 2/10/2008 3 I'd like to sum up the weekly data to the monthly level, so that it looks something

Hello, I have a vector: x <- c("A", "A", "A", "B", "A", "A", "C") I'd like to compare each of elements of vector x from its previous element (except for the 1st element which does not have previous element). So I'd like to get a vector y (of same length) that looks something like (0, 0, 0, 1, 1, 0, 1) or (F, F, F,

Hello, I have a time series plot drawn using 3 different colored lines, each line corresponds to different category group. I'd like to put legends on the plot. I am using "legend" to do this, however, I can either specify lty or col in legend. Will I be able to do the following in the legend box: a solid black line then g1, a solid red line then g2, a solid blue line then g3?

Dear R users: I am running lmer(), and I had the following warning message: "In mer_finalize(ans): iteration limit reached without convergence (9) What is the default limit for lmer()? And how do I increase the limit? Many thanks, Julia -- View this message in context: http://www.nabble.com/How-to-increase-iteration-limit-for-lmer%28%29--tp20252974p20252974.html Sent from the R help

Dear R users, I need to compare two scatter plots, plot(x1, y1) plot(x2, y2) and would like to plot them in the same figure. How do I do it? Thank you. -- View this message in context: http://www.nabble.com/two-scatter-plots-in-one-tp21963375p21963375.html Sent from the R help mailing list archive at Nabble.com.

It seems that you have load the "survival" package date.mdy is a function from this one. In this function the "origin" of the time is the first day of 1970 in the base package the origin is the first day of 1960 it's very curious... Benjamin Esterni France From: "Vegard Andersen" <vegard.andersen@ism.uit.no> Subject: [R] Date conversion problem using

Hello! I have a dataset with the dates and positions - Lat and Long columns How do I make a scatter plot? Do I have to cbind to combine the Lat and Long columns? Any suggestions will be much appreciated! Thank you Julia [[alternative HTML version deleted]]

Why is R recognizing dates like this? Chris Buddenhagen, Botany Department, Charles Darwin Research Station, Santa Cruz,Galapagos. Mail: Charles Darwin Foundation, Casilla 17-01-3891 Avenida 6 de Diciembre N36-109 y Pasaje California Quito, ECUADOR ______________________________________________________________________ EL CONTENIDO DE ESTE MENSAJE ES DE ABSOLUTA RESPONSABILIDAD DEL

Dear R users, I am running lmer() and having memory problem: "reached total allocation of 1535Mb". The lmer() function was successful (no errors or warnings). However when I do "summary(fit.lmer), I got this "Error: cannot allocate vector of size 19.5 Mb). I used memory.size() and got 1880. I used memory.limit(2500) to increase the memory size to 2500Mb, however I still get

Dear R users, Suppose I have a vector that consists of characters like ABC, A02, RCA, etc., and there are about 700 of possible characters. For example, x <- c("ABC", "ABC", "ABC", "A02", "ABC", "RCA", "ABC", "ABC") I'd like to get a frequency matrix that looks something like this: ABC 6 A02 1 RCA 1 I

Dear R users, I would like to test the randomness in a series of N values (N>=2). I know that runs.test works for dichotomous factor only: x <- rep(c(1,2), 50) runs.test(factor(x)) However it doesn't work for series that can take any N values (N>2): x <- rep(c(1,2,5,4),50) runs.test(factor(x)) Error in runs.test(factor(x)) : x does not contain dichotomous data Are there any R

Dear R users, I have this vector that consists numeric numbers. Is there a command that detects the repeated numbers in a vector and returns the index of the repeated numbers (or the actual numbers)? For example, v <- c(3,4,5,7,4). The command would return me index 2 and 5 (or the repeated number, 4). Thank you very much, Julia -- View this message in context:

hi, Is there an easy way of calculating the difference in months between two dates in a controller. thanks -- Posted via http://www.ruby-forum.com/.

Hello, I would like to be able to calculate the age of someone at a particular date. Both dates are date objects. Here is what I have come up with: floor(as.numeric(sampleInfo$Date.of.DIAGNOSIS-sampleInfo$Date.of.birth)/365.25) Is this the best approach? or is there an inbuilt function? I have looked at difftime but that does not seem to allow output in years. Many thanks Dan --

Hi I'm having a problem using the zoo library and I can't see what I'm doing wrong. For example setting up the data > t1 = zoo (matrix (1:12, nrow = 3), order.by = as.Date (c("2008-08-01","2008-08-02","2008-08-03"))) > colnames (t1) = c ("A", "B", "C", "D") > t2 = zoo (matrix (1:12, nrow = 3), order.by =

Dear list, I have two data columns (part of big data frame) containing dates presenting the dates when two measurements (M1 and M2) were taken. The data consists of 73 individuals divided in different groups. Each group was examined at different time points (see M1 date),but the measurements (M1 and M2) within each group should be taken in the same day but due to some practical issues,