similar to: check for new files in a given directory

I want to read in a binary file using the readBin() function. In order to skip uninformative parts of the file I use the seek() function, I need to specify the number of bits to skip rather than the number of bytes to skip. E.g. seek(to.read,origin="current",blockSize) with blockSize giving the number of bits Does anybody know if this works? Any help would be highly

I've been trying to create a list of function where function[[i]] should actually return the value of i. trying: func <- vector("list",2) i <- 1 while (i <= 2) { func[[i]] <- function() { i } i <- i+1 } however only returned the last value of i for each function. Any help how to achieve the solution intended would be greatly appreciated. thanks in advance, andreas

Hi, I need to produce a standard report for several variables in Sweave and thus would need the possibility to define a TeX-command which includes R-code like \newcommand{\meansd}[1]{The mean is \Sexpr{mean(#1)} and the standard deviation is \Sexpr{sd(#1)} . } and then just write \meansd{age} in the latex code to get the whole sentence. The above does not work, since

HI all, I'm new to R. Say I have a multi-layered list called newlist. ############ > str(newlist) List of 2 $ :List of 5 ..$ : num [1:8088] NA 464 482 535 557 ... ..$ : num [1:8088, 1:2] NA 464 482 535 557 ... ..$ : num [1:8088, 1:3] NA 464 482 535 557 ... ..$ : num [1:8088, 1:4] NA 464 482 535 557 ... ..$ : num [1:8088, 1:5] NA 464 482 535 557 ... $ :List of 3 ..$ : num

This is a minor release of Shorewall. WARNING: This release introduces incompatibilities with prior releases. See http://www.shorewall.net/upgrade_issues.htm. Changes are: a) There is now a new NONE policy specifiable in /etc/shorewall/policy. This policy will cause Shorewall to assume that there will never be any traffic between the source and destination zones. b) Shorewall no longer

Hello! # I have a list with several data frames: mylist<-list(data.frame(a=1:2,b=2:3), data.frame(a=3:4,b=5:6),data.frame(a=7:8,b=9:10)) (mylist) # I want to grab only one specific column from each list element neededcolumns<-c(1,2,0) # number of the column I need from each element of the list # Below, I am doing it using a loop: newlist<-NULL for(i in 1:length(mylist) ) {

hello , i''m currently trying to set-up Traffic Shapping with Shorewall and I have strong feelings that I found a bug. I may be mistaken, but I tried everything and can''t get it to work. I''ve turned ON TC_ENABLED=Yes and CLEAR_TC=Yes when i start shorewall ( shorewall start ), i get this message : Setting up Traffic Control Rules... TC Rule "2 eth1 0.0.0.0/0 tcp

like this, the list is below, I want to remove the last one . not using newlist[-2], but using the function detect its component is numeric(0) and then remove it from the list. newlist [[1]] [1] 2 3 [[2]] [1] numeric(0) [[3]] [1] 7 [[alternative HTML version deleted]]

Hello all, Maybe I'm being thick, but I was trying to figure out a simple way to create a list with the same dimension of another list, but populated with NA values. masterlist = list( aa=list( a=matrix(rnorm(100),10,10), b=matrix(rnorm(130),13,10), c=matrix(rnorm(140),14,10)), bb=list(

my list al is as below: mylist=list(c(2,3),5,7) > mylist [[1]] [1] 2 3 [[2]] [1] 5 [[3]] [1] 7 How could I get the following FOUR lists: First one [[1]] [1] 3 [[2]] [1] 5 [[3]] [1] 7 Second one [[1]] [1] 2 [[2]] [1] 5 [[3]] [1] 7 Third One [[1]] [1] 2 3 [[2]] [1] 7 Last one [[1]] [1] 2 3 [[2]] [1] 5 Do I have to use 'for' loops? Please give me sone suggestions! Thank you

Hi, I noticed some time ago that, for instance, named vectors that are really makes str() really slow when displaying the names attribute. I don't know exactly when this started, but it wasn't the case say 1-2 years ago. Example (on a WinXP 1.8GHz): > s <- 1:1000; names(s) <- s > system.time(str(s)) Named int [1:1000] 1 2 3 4 5 6 7 8 9 10 ... - attr(*, "names")=

I have a list containing 48 objects (each with 30 rows and 4 columns, all numeric), and wish to produce 4 boxplot series (with 48 plots in each) , one for each column of each object. Basically I want a boxplot from boxplot(mylist[[]][,i]) for i in 1:4. It seems that I can create a boxplot of length 48 from the entire list, but I don't seem able to subscript to return 4 boxplots from the list

Hi all, I have the following code: set.seed(1) x1 <- matrix(sample(1:12), ncol=3) x2 <- matrix(sample(1:12), ncol=3) x3 <- matrix(sample(1:12), ncol=3) X <- list(x1,x2,x3) tt <- matrix(round(runif(5*4),2), ncol=4) Is there a way I can construct a new list where newlist[[i]] = tt[i,] %*% X[[i]] without using a for loop? Each element of newlist will be 3 x 1 vector. Thanks -- Tina

Hello, thank you all for your patience and time I am essentially trying to get disorganised data into long form for linear modelling. I have 2 dataframes "rec" and "book" Each row in "book" needs to be pasted onto the end of several of the rows of "rec" according to two variables in the row:" MRN" and "COURSE" which match. I have

I am getting the following message when Shorewall stops can anybody shed any light on this message and where I should be looking? Thanks root@bobshost:~# shorewall stop Loading /usr/share/shorewall/functions... Processing /etc/shorewall/params ... Processing /etc/shorewall/shorewall.conf... Loading Modules... Stopping Shorewall...Processing /etc/shorewall/stop ... IP Forwarding Enabled

I would like to use grep and gsub to manipulate a vector to make the names used consistent, i.e. reduce a level or two. However, here is what I found when I attempted to use grep and gsub: > tmp_test<-c("House 1 Plot Plus +100","House 2 Plot Plus +100","House 3 Plot Plus -100","House 4 Plot Plus -100","House 1 Plus +100","House 2

Hi, This question should be simple to answer. I am a new R user. I have a data.frame called appended. I would like to break it into 7 smaller datasets based on the value of a categorical variable dp (which has values 1:7). I would like to name the smaller datasets set1, set2, set3,....,set7. I don't know how to refer to the variable in the for loop, when naming the output datasets. In STATA

Hi all, There are matrices with same column names but arranged in different orders and I desire columns of these matrices to have same order. For example, below are 2 arbitrary data sets with columns arranged in different order. I require columns of these to have same order as specified in "columns" object and the results stored in the original object names. I know this can be done

Dear R users, I wish to utilise processed and saved objects as arguments of a function. Specifically, I have created objects using *"assign"* & *"paste"* functions with an incremental index i, the names of the objects are: fund1, fund2, fund3,....., fund80,..... (where the numerical value increments according to the index i & class of these objects are

I have the following code: list1 <- list() for (i in list.files(pattern="filename1")){ x <- read.table(i) list1[[i]] <- x } list2 <- list() for (i in list.files(pattern="filename2*")){ x <- read.table(i) list2[[i]] <- x } anslist <- vector('list', length(list1)) for(i in 1:length(list1)) if (list1[[i]] & list2[[i]] >1)