similar to: How to convert a matrix to a dataframe and makes its first row be the column name

Displaying 20 results from an estimated 30000 matches similar to: "How to convert a matrix to a dataframe and makes its first row be the column name"

2008 Sep 23
1
How to draw arrows or segment lines in 3 dimensional graph
Hi I have a dataset which is like this: ID X1 Y1 Z1 X2 Y2 Z2 1 32 127 85 31.7 121 85 2 37.9 153 88 34.6 137 90 3 36.8 134 88 36.1 155 97 4 31.4 136 87 29 113 70 I would like draw the arrow or segment line for each ID from (x1, y1, z1) to (x2, y2, z2) Is there a way to do this kind of 3-D graph. Thank you -- View this message in context:
2009 Aug 06
2
Convert dataframe to table with counts where column names become row names
Can anyone explain how best to go from a dataframe to a table (or better yet a new dataframe) of counts, where the row names in the new table (or dataframe) are the column names of the original df. start w/ DF1 = Pos1 Pos2 Pos3 .... oligo1 G C A oligo2 U U A oligo3 G C C oligo4 C G U oligo5 A A G ..... End with DF2 =
2006 Feb 24
2
converting character matrix to a dataframe
Dear R-Help, Suppose I have a character matrix, e.g., (ch.mat <- matrix(c('a','s','*','f','w','*','k','*','*','f','i','o'), ncol=3)) When I convert 'ch.mat' to a dataframe, the columns are converted to factors: (d1 <- data.frame(ch.mat)) mode(d1[,1]) is.factor(d1[,1]) To prevent
2009 Feb 06
3
how to delete specific rows in a data frame where the first column matches any string from a list
Hi, I'm new in the mailing list but I would appreciate if you could help me with this: I have a big matrix from where I need to delete specific rows. The second entry on these rows to delete should match any string within a list (other file with just one column). Thank you so much! Laura
2008 Apr 27
1
parallel max, min, and median of dataframe columns
Hello, all, I have a dataframe of three rows and umpteen columns. I want to show the maximum, minimum, and median with a vertical line and a central dot (I'd use a boxplot, but with only three data points, that's overkill; I can't just use points, because of overlap and some of the other data plotted on the graph). This works: > boxplot(data_frame,
2009 Apr 13
3
tapply output as a dataframe
i use tapply and by often, but i always end up banging my head against the wall with the output. is there a simpler way to convert the output of the following tapply to a dataframe or matrix than what i have here: # setup data for tapply dt = data.frame(bucket=rep(1:4,25),val=rnorm(100)) fn = function(x) { ret = c(unname(quantile(x,probs=seq(.25,.75,.25),na.rm=T)),mean(x,na.rm=T)) } a =
2011 May 27
1
How to convert an ftable object to a matrix including the row names?
Dear expeRts, What's the easiest way to convert an ftable object to a matrix such that the row names of the ftable object are shown in the first couple of columns of the matrix? This is (typically) required, for example, when the final goal is to print the matrix via xtable. Below is a rather complicated example of how to do it... Cheers, Marius ## Goal: convert an ftable() to a
2008 Jun 22
5
Re move row.names column in dataframe
Hello, aa<-c(1,1,2,2,3,3,4,4,5,5,6,6) bb<-c(56,56,33,33,53,53,20,20,63,63,9,9) cc<-data.frame(aa,bb) uniquedf <- unique(cc) View(uniquedf) Why does the column "row.names" appear in the new dataframe and how do I get rid of it. "uniquedf$row.names <- NULL" does not seem to work. For what I'm doing this is a useless column and can cause confusion and/or
2008 Oct 20
2
convert matrix to dataframe with repeating row names
Hi R, I have a matrix x with repeating row names. > dim(x) [1] 862 19 zz<-matrix(0,4,4) rownames(zz)=c("a","a","b","b") data.frame(zz) (?) I need to use x in a linear regression lm(as.formula(paste("final_dat[,5]~",paste(colnames(x),collapse="+"))),x ) this gives me a error Error in
2007 Apr 16
2
Dealing with data frame column names beginning with a numeric
I wish to set up a simple function using boxplot so that it will be available to someone using R for Windows. (I myself use Linux.) The way the data is organised makes it convenient to use the boxplot function in a manner similar to this example given in the help. > mat <- cbind(Uni05 = (1:100)/21, Norm = rnorm(100), + T5 = rt(100, df = 5), Gam2 = rgamma(100, shape
2010 Feb 26
7
How to add a variable to a dataframe whose values are conditional upon the values of an existing variable
Hi everyone, I am at my wits end with what I believe would be considered simple by a more experienced R user. I want to know how to add a variable to a dataframe whose values?are conditional?on the values of an existing?variable.?I can't seem to make an ifelse statement work?for my situation.?The existing variable?in my dataframe is?a character variable named DOW which contains abbreviated
2009 Jan 07
1
Re moving Numeric,0 from dataframe
I realize i am breaking the posting rules by not posting sample code but i tried building some sample test code for this problem based on my working code and it wasnt producing what i wanted so hopefully a brief explanation and my result will allow you guys enough information to offer some advice. My result: allTAZprobs TAZS [1,] Numeric,0 640 [2,] 0.4385542 641 [3,] 0.2876207 642 [4,]
2013 Mar 07
2
Copying a dataframe
Hi, I am trying to create a data frame using the dimensions of another data frame that I have input. This is the code I am using: tab is the data frame that is input. c.leng<-length(tab[,1]); r.leng<-length(tab[1,]); opdf<-data.frame(ncol=c.leng, nrow=r.leng); a<-1; while(a<=c.leng) { opdf[[1]][a]<-tab[[1]][a]; a<-a+1; } This is the error message I am getting: Error in
2009 Mar 11
3
Converting a dataframe to a matrix
If I have a dataframe which is organized like this: name color likes? 1 sally red 0 2 sally blue 1 3 sally green 1 4 jake red 0 5 jake blue 1 6 jake green 1 7 tom red 1 8 tom blue 0 9 tom green 0 And I want to create a matrix in the form: red blue green sally 0 1 1 jake 0 1 1 tom 1 0 0 Are there any built-in
2018 May 22
0
remove rows of a matrix by part of its row name
Hello, Use grep to get the row indices and then subset with a *negative* index to remove those rows. rn <- scan(what = character(), text = " 70/556 71.1/280 72.1/556 72.1/343 73.1/390 73.1/556 ") mat <- matrix(rnorm(6*6), nrow = 6) row.names(mat) <- rn inx <- grep("73\\.", row.names(mat)) new_mat <- mat[-inx, ] new_mat Hope this helps, Rui Barradas On
2018 May 22
4
remove rows of a matrix by part of its row name
Dear R-experts, How can I remove a certain feature or observation by a part of its name. To be clear, I have a matrix with 766 observations as a rows. The row names are like this 70/556 71.1/280 72.1/556 72.1/343 73.1/390 73.1/556 Now I would like to remove all the rows that contain the text 73.1 Any ideas or suggestion please ? Regards ********************** Ahmed Serag Analytical
2007 Mar 10
2
read a irregular text file data into dataframe()
I am using R2.4.1 calling a text file contains the following data structure: when i call the file into R using tData<-read.table("c:\\test.txt") it gave me Error saying, irregular column in the data set however i need to use the below type of data Is there any alternative in R? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 0010 0028 0061 0088 0010 0042 0084 0004 0010 0055 0010 0018 0040 0042
2006 Aug 14
3
column to row
Dear mailing list I have a data in two columns and how can i convert it to one row . thank you in advance inpute 1 2 3 4 5 6 7 8 9 1 out put 1 2 3 4 5 6 7 8 9 1 [[alternative HTML version deleted]]
2006 Sep 17
2
Excluding columns from dataframe and selecting row records
Dear R-friends, I have to simple questions. First I would like to exclude some columns from a dataframe and after I need select rows that satisfy some conditions. My data frame looks like Region Species Bodysize Weigth Age Africa Sp1 10.2 20 2 Africa Sp2 12.2 12 2 Africa Sp3 15.3 18 3 Africa Sp4 11.5 40 4 Brazil Sp1 10.2 40 3 Brazil Sp2 22.2 32 2 Brazil Sp3 12.3
2012 Sep 17
2
How to divide each column with its own value
Hi, I have a matrix as below: mat= [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 What I want to do is, I would like to divide each column with its own value, in order to get value 1. Is there any simple script for that? [[alternative HTML version deleted]]