similar to: Conditional sorting

Hello guys, I have a list L1 of matrix. I have another list L2 with the same number of elements representing the row of the L matrix that I want to delete (L1[[i]][-L2[[i]],]) but I can't do this with lapply as it iterates through L1 (first argument) and not L2. Any idea? ----- Anna Lippel -- View this message in context:

hello list! I'm sorry, I just stumbled over this strange behaviour (at least I am not able to explain the behaviour, therefore I assume it to be a strange behaviour): attach(water) # I know, this is not recommended names(water[3:10]) [1] "temp" "pH" "DO" "BOD" "COD" "no3" "no2" "po4" for (i in

Hi r-users,   I hope somebody can help me to understand the error message.  Here is my code; ## Newton iteration newton_gam <- function(z) { n   <- length(z)   r   <- runif(n)   tol <- 1E-6   cdf <- vector(length=n, mode="numeric")   fprime <- vector(length=n, mode="numeric")   f   <- vector(length=n, mode="numeric")     for (i in 1:1000)   {

Estimados Al dirigir la lectura de un folder tYA1.csv me da este error y no me percato del motivo, adjunto archivo. Espero su ayuda Saludos Jos? > setwd("D:/Public/Documents/R/bioimpedancia") > a<-read.csv("tYA1.csv",header=TRUE, sep=",", dec=".") Error in read.table(file = file, header = header, sep = sep, quote = quote, : more

hello, I'd like know how to sort a data frame in R for example how I should do to sort by Catholic with swiss data frame like below thanks Fertility Agriculture Examination Education Catholic Infant.Mortality Courtelary 80.2 17.0 15 12 9.96 22.2 Delemont 83.1 45.1 6 9 84.84 22.2

rpm-4.3.2 rpm-build-4.3.2-21 [root at tarkus i386]# rpm -ivh * error: Failed dependencies: compat-libstdc++-33-3.2.3-47.3 is needed by opennms-1.3.0-0.20050413.0_centos4.i386 [root at tarkus i386]# rpm -q compat-libstdc++-33-3.2.3-47.3 compat-libstdc++-33-3.2.3-47.3 Any idea on how to deal with this? This is with rpms build from opennms head. Regards, Ted

Dear Community, I have been using two types of survival programs to analyse a data set. The first one is an R function called aftreg. The second one an STATA function called streg. Both of them include the same analyisis with a weibull distribution. Yet, results are very different. Shouldn't the results be the same? Kind regards, J -- View this message in context:

Hi - I am not R expert and I would appreciate your time if you can help me about my xyplot question. I would like to add text (p-value) in a 4 panels xyplot. I thought panel = function{} should work but I am not sure where I did it wrong. The error message from the following code is "Argument subscripts is missing with no default values" xyplot(GLG ~ PD | factor(TRT) , groups =

Hi, While executing the make after successful configuration (./configure --with-readline=no --without-iconv), the following error occurs: mbf2n11s (Regatta) /saswork/R/R-2.7.0$ make Target "R" is up to date. Target "R" is up to date. Target "R" is up to date. Target "R" is up to date. Target "Makedeps" is up to date. Target "libbz2.a"

On 2019/7/20 0:13, Michael S. Tsirkin wrote: > On Fri, Jul 19, 2019 at 03:31:29PM +0000, ? jiang wrote: >> On 2019/7/19 22:29, Jiang wrote: >>> On 2019/7/19 10:36, Jason Wang wrote: >>>> On 2019/7/18 ??10:43, Michael S. Tsirkin wrote: >>>>> On Thu, Jul 18, 2019 at 10:42:47AM -0400, Michael S. Tsirkin wrote: >>>>>> On Thu, Jul 18, 2019

On 2019/7/20 0:13, Michael S. Tsirkin wrote: > On Fri, Jul 19, 2019 at 03:31:29PM +0000, ? jiang wrote: >> On 2019/7/19 22:29, Jiang wrote: >>> On 2019/7/19 10:36, Jason Wang wrote: >>>> On 2019/7/18 ??10:43, Michael S. Tsirkin wrote: >>>>> On Thu, Jul 18, 2019 at 10:42:47AM -0400, Michael S. Tsirkin wrote: >>>>>> On Thu, Jul 18, 2019

On 2019/7/19 22:29, Jiang wrote: > > On 2019/7/19 10:36, Jason Wang wrote: >> >> On 2019/7/18 ??10:43, Michael S. Tsirkin wrote: >>> On Thu, Jul 18, 2019 at 10:42:47AM -0400, Michael S. Tsirkin wrote: >>>> On Thu, Jul 18, 2019 at 10:01:05PM +0800, Jason Wang wrote: >>>>> On 2019/7/18 ??9:04, Michael S. Tsirkin wrote: >>>>>> On

http://www.nabble.com/file/p20332968/spe.dat spe.dat Hi, i have a problem in sorting out some command in R and i am really hoping some expert can help me out please! i have the spe.dat file which i upload here, and when u read into R u got something like this: A5 <- read.table('spe.dat' ,header=TRUE) A5 EXPEND ECAB MET GROW YOUNG OLD WEST STATE 1 256 85.5 19.7 6.9 29.6

Hello all! I've been struggling with is for many hours today; I'm close to getting what I want, but not close enough... I have a dataframe consisting of two date-time columns followed by two numeric columns. what I need is the max value (in the first numeric column) based on the 2nd date-time column, which is essentially a factor. But, I want the result to provide both date-time values

Hi Jeff, Thank you for the suggestions -- I appreciate your help. Unfortunately, the result2 has two problems... (1) there are now 3 date columns (it looks like 2 cols are merged into 1 col) (2) the output rows should not have any of the basistime dates repeated (maybe I misstated the problem); I need the max fcst value by basistime, but also list the date value for that row; for example:

Hi All, I''ve just built an 8 disk zfs storage box, and I''m in the testing phase before I put it into production. I''ve run into some unusual results, and I was hoping the community could offer some suggestions. I''ve bascially made the switch to Solaris on the promises of ZFS alone (yes I''m that excited about it!), so naturally I''m looking

Dear R users, A have a dataframe (matrix) with two collumns (plot, and diameter (d)). I want all diameters values for different combination of plots. For example I want all d values for all posible combination, 100C2 (all d values for plot 1 with all d values in the plot 2.......with all d values from plot 1 with all d values from plot 100, ...... with all d values from plot 99 with all d values

Hi R-users, I'm not sure what's wrong and how do I check the error? I have 3 sets of data > aug_dt1  [1]  22.8  49.6  77.9  67.6  91.2  48.9 124.6  54.6  85.8  62.8  63.3 174.7  32.3  22.7  99.9 123.2   4.8 149.0  66.0 [20]  73.9  37.4  22.4  69.5  87.3  66.9  87.2  81.5 109.1  47.4  22.8  92.4  60.9  77.5  91.3  91.9  78.2  39.4 107.5 [39]  57.9  65.5  76.0  47.2 145.5  95.9 106.0

On Thu, 26 Oct 2017, Thomas Adams wrote: > Hi Jeff, > > Thank you for the suggestions -- I appreciate your help. Unfortunately, the > result2 has two problems... > > (1) there are now 3 date columns (it looks like 2 cols are merged into 1 > col) No, there are two date columns. Result2 includes the grouping value as a row name (pulled from the names of the dta2list items

Hi, I am trying to run an analysis of variance using R. in my data table "x" is a continuous variable lengthof 200 and "p" is a categorical variable also of length 200 and p is anyone of three categories 1,2 or ,3. if I run summary(aov(x~p,data=test)) I get Response: x Df Sum Sq Mean Sq F value Pr(>F) p 1 3174.7 3174.7 42.749 5.175e-10 ***