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Hi everyone,   I have got the following problem:   x1 <- rnorm(10,5,1) x2 <- runif(10,0,1) nam1 <- paste("A",1:4,sep=".") nam2 <- paste("A",6:9,sep=".") nam <- c(nam1,"A.4",nam2,"A.9") mydata <- data.frame(x1,x2) rownames(mydata) <- nam Error in `row.names<-.data.frame`(`*tmp*`, value = c("A.1",

Hi, I have gote the following data x1 <- c(rep(1,6),rep(4,7),rep(6,10)) x2 <- rnorm(length(x1),6,1) data <- data.frame(x1,x2) and I would like to compute the mean of the x2 for each individual of x1, i. e. x1=1,4 and 6? Thank you very much in advance, Amori [[alternative HTML version deleted]]

Hi gues,   Is there any function in R for boxplot with different time points? t1 <- c(rep(1,20),rep(2,20)) t2 <- c(rep(1,10),rep(2,10),rep(1,10),rep(2,10)) x <- rnorm(40,5,1) dat <- data.frame(t1,t2,x) boxplot(x~t1,t2) Many thanks, Amor [[alternative HTML version deleted]]

Hello everybody,   I wonder if there is any swap function in R that does the following: x <- seq(1,10,12) x1 <- swap(x) x1 1 8 3 4 5 6 7 2 10 Thank you very much!   Amor __________________________________________________ Schutz gegen Massenmails. [[alternative HTML version deleted]]

Dear All: I do see I have weeks of codes in my console when I check with my arrow up keys. I have been clearing them with Control L but it seems to clear it clear the screen temporally. I do see the previous codes again when I open R the next day, after quitting the session! Q: How do I clear this? Thanks; YA -- View this message in context:

Hi! In a current project, I am fitting loess models to subsets of data in order to use the loess predicitons for normalization (similar to what is done in many microarray analyses). While working on this I ran into a problem when I tried to predict from the loess models and the data contained NAs or NaNs. I tracked down the problem to the fact that predict.loess will not return a value at all

This may be asking too much, but I'm wondering if anyone has a solution (even a hack) for creating multiple (overlay) plots in an Sweave file and post-processing the overlays in beamer appropriately. For example, suppose I have a series of figure blocks in my .Rnw file: <<plot1,fig=TRUE>>= [stuff] @ <<plot2,fig=TRUE>>= [stuff] @ <<plot3,fig=TRUE>>=

Dear ExpeRts, I am trying to plot a bunch of growth curves and would like to get some more control over groups and line colors than I seem to have. Example: # make some data dat <- Orange dat$group <- ifelse(dat$Tree%in%c('1','4','5'), 'A', 'B') # plot xyplot(circumference~age, dat, groups=group) # now use lines to make the growth curve more

I have a 64-bit windows box - Intel Xeon CPU E7340 @ 2.4GHz 31.9GB of RAM I have R 2.11.1 (64bit) running on it. My csv data is 3.6 GB (with about 15 million obs, 120 variables.) ------------------------------------------------ I have successfully imported the data above into R. No problem. Now I am trying to run 'rpart' on my data. But I got the following error : Error: cannot

Dear all I have written a function to perform a very simple but useful task which I do regularly. It is designed to show how many values are missing from each variable in a data.frame. In its current form it works but is slow because I have used several loops to achieve this simple task. Can anyone see a more efficient way to get the same results? Or is there existing function which does

Hi, I have been working with R for the past couple of years; analyzing data and producing some graphics. I was just wondering if people use graphics from R straight into articles or are they always edited in some way; fonts, headers, axis, color etc? Using photoshop or some other programs? I would like to think it is possible, better and more profession to do it all in R. I tried google and

Dear ExpeRts,t I am trying to read tab delimted data produced by somewhat brain dead software that seems to think it's a good idea to have an extra tab character after the last column - except for the header line. As explained in the help page, read.delim now assumes that the first column contains the row.names (which is not even wrong) but now and all col.names get shiftet by one column.

Dear Sir/Madam; I'm not sure whether this is the correct contact for help. I've been recently working with R on my project, unfortunately It sudenly crashes! It gives me the following message: "FATAL ERROR: unable to restore saved data in .RDATA" I decided to uninstall the copy (a R2.11.0) and installed a new version (2.11.1) but I'm still receiving the same message. When I

Dear all, I've been trying to superscript the '2' in the following command (I don't want the '^' displayed), but as yet haven't had much luck. I've tried both the paste and expression commands, but neither have brought me any joy! mtext(side=2, line=5.5, "Monthly Precipitation (mm x 10^2/month)", font=2, cex=1.1) Any advice would be much appreciated,

HiI am contacting you regarding a problem with downloading R. I cannot seen to manage because my computer language is in Norwegian. DO you know if there is R that can deal with Norwegian letters? Øistein Harsem _________________________________________________________________ Show them the way! Add maps and directions to your party invites. [[alternative HTML version deleted]]

Friends I have a data frame, df that I want to extract some rows from Here is a sample of the data > head(df) TDate Expiry Underlie Strike CSettle PSettle Futures ExDate TTE 1 20080102 200801 200803 0.840 0.0000 0 0.9207 20080104 0.005479452 2 20080102 200801 200803 0.850 0.0000 0 0.9207 20080104 0.005479452 Rate Disc 1 0.0457 0.9997496 2 0.0457

Hi, Except the function postscript ('file_name.eps'), are there functions to generate an image file in eps format? thanks Carol [[alternative HTML version deleted]]

Hi, I'm experimenting with a few learners that require a matrix as their input. (Currently svmpath, vbmp, etc.) I currently have a dataframe with 50 columns and 20,000 rows. I tried using: x <- as.matrix(my_data.frame) If I then as, "is.matrix(x)", I get TRUE. However everywhere I've tried to use the matrix returns errors. Is there a step I'm missing? Thanks! -N

Hello, I have seen a few posts about changing a vector of numbers to days of the week where the numbers are 1-7. I have a similar problem with a twist. I have a vector of numbers ranging form 20 to 500. The numbers represent days since a starting point. The list is not consecutive, some numbers skipped and some numbers duplicated. I know day 1 was a Monday. I want to use this vector in a lm

Hi guys, I am trying to shift down the "ylab" of my plot but can't find how to do it. I tried to tune "mar" but it enable more room for the labels to be displayed but it does not move to "ylab" as I would like. Is there a way with "par" to shift down my "ylab" ?? Cheers -- View this message in context: