similar to: Question on qplot

I was trying to dw data from Economagic [http://www.economagic.com/em-cgi/data.exe/libor/day-ussnon], using following code : library(fimport) dat2 = economagicSeries("libor/day-ussnon", frequency = "daily") Here I see that data is not complete, downloaded data starts from "2007-12-31 ", whereas actual data is available from 2001. secondly, how I convert that data

I need to solve a equation like this : a = b/(1+x) + c/(1+x)^2 + d/(1+x)^3 where a,b,c,d are known constant. Is there any R-way to do that? Thanks in advance -- View this message in context: http://www.nabble.com/How-to-solve-following-equation--tp20785063p20785063.html Sent from the R help mailing list archive at Nabble.com.

Hi Ian, Per your suggestion, I reinstalled R 2.9.0, then I reinstalled ggplot2 on top. The problem persists. Here's the what happens after the installation: > qplot (carat, price, data = diamonds, alpha = I(1/10)) Warning message: In grid.Call.graphics("L_points", x$x, x$y, x$pch, x$size) : semi-transparency is not supported on this device: reported only once per

Hi, I want find all roots for the following polynomial : a <- c(-0.07, 0.17); b <- c(1, -4); cc <- matrix(c(0.24, 0.00, -0.08, -0.31), 2); d <- matrix(c(0, 0, -0.13, -0.37), 2); e <- matrix(c(0.2, 0, -0.06, -0.34), 2) A1 <- diag(2) + a %*% t(b) + cc; A2 <- -cc + d; A3 <- -d + e; A4 <- -e fn <- function(z) { y <- diag(2) - A1*z - A2*z^2 - A3*z^3 - A4*z^4

Hi all, Is there any process to conduct a search for a particular digit or letter in a ch. string? For example I want to make a search where 1st numeric figure appears in the string "asd123". Here the answer should be "4" Thanks, -- View this message in context: http://www.nabble.com/Searching-1st-number-within-a-ch.-string-tp25400580p25400580.html Sent from the R help

R-listers, I am using xts with a yearmon index, but am getting some inconsistent results with the date index when i drop observations (for example by using na.omit). The issue is illustrated in the example below. If I start with a monthly zooreg series starting in 2009, yearmon converts this to "Dec-2008". Not such a worry for my example, but strange. Having converted to xts, i drop

Hi all, is there any function to find some words in a character-string? For example suppose the string is : "gdfsa-sdhchc-88", now I want to find whether this string contains "sdhch". Is there any R function to do that? Regards, -- View this message in context: http://www.nabble.com/Searching-within-a-ch.-string-tp23484010p23484010.html Sent from the R help mailing list

Dear all, Please forgive me if there is a duplicate post; my previous mail perhaps didnt reach the list....... Let say I have following time series library(zoo) > dat1 <- zooreg(rnorm(10), start=as.Date("2010-01-01"), frequency=1) > dat1[c(3, 7,8)] = NA > dat1 2010-01-01 2010-01-02 2010-01-03 2010-01-04 2010-01-05 2010-01-06 2010-01-07 2010-01-08 2010-01-09

Hi everyone, I have this kind of raw dataset : - <Temp diffgr:id="Temp14" msdata:rowOrder="13"> <Date>2005-01-17T00:00:00+05:30</Date> <SecurityID>10149</SecurityID> <PriceClose>1288.40002</PriceClose> </Temp> - <Temp diffgr:id="Temp15" msdata:rowOrder="14">

I have a vector of letters like c("a", "B", "c"). Is there any R function to force all elements to lower-cap ? Thanks, -- View this message in context: http://old.nabble.com/How-to-make-all-elements-all-elements-lower-cap---tp26365794p26365794.html Sent from the R help mailing list archive at Nabble.com.

Hi, I have following codes : library(zoo); library(ggplot2); library(plyr) dat <- rnorm(306); vv <- letters[1:6]; dat1 <- data.frame(dat, vv) dat2 = zooreg(rnorm(51), as.yearmon(as.Date("2000-01-01")), frequency=12) ggplot(dat1) + geom_line(aes(y=dat, x=index(dat2), colour=vv), group=vv, size = 1.3) However I got error while plotting them :

Dear all, I have following two list object, both are basically collection of matrices : dat1 <- matrix(rnorm(25*6), ncol=6) dat1 <- split(dat1, seq(5,25,by=5)) dat1 <- lapply(dat1, matrix, ncol=6) dat2 <- matrix(rnorm(25*4), ncol=4) dat2 <- split(dat2, seq(5,25,by=5)) dat2 <- lapply(dat2, matrix, ncol=4) Now I want to replace last 4 columns of each matrix at "dat1"

Dear all, let suppose I have following vector:   > dat1 <- c(rep("asd", 5), rep("xyz", 12), rep("erd", 17)) > dat1 <- dat1[sample(1:length(dat1), length(dat1), replace=F)] > dat1  [1] "erd" "xyz" "erd" "asd" "asd" "erd" "xyz" "asd" "erd" "erd"

I am getting following strange error : library(sn) library(ggplot2) dat1 <- as.matrix(rsn(1000, 0, 1, 0))[,1] ggplot() + geom_histogram(aes(x = dat1, y = ..density.., fill = ..count..)) + xlab("Distribution") + scale_y_continuous("") Error: No data for layer Can anyone please tell me why it is coming? -- View this message in context:

I want to draw following plot, given here http://www.2shared.com/file/4327128/830b82c4/pic.html for the following data : dat <- cbind(rnorm(100), sample(c(1:4), 1000, T)) colnames(dat) <- c("data","level") Here x-axis should be on "data" and y-axis is for "level" and z-axis should be to display the frequency of "data" for a particular

I have a dynamic time series model like this: dyn$lm( y ~ lag(y,-1) + x + lag(x,-1)+lag(x,-2) ) I need to do an out of sample forecast with this model. Is there any way I can do this with R? It would be greatly appreciated if some one can give me an example. Thanks. Harry [[alternative HTML version deleted]]

Hello all, I'm stuck with a strange issue with writing jpegs of plots to a folder in a loop. This works: for (step in 1:length(steps)) { jpeg(filename=paste("frame_",sprintf("%05d",step),".jpg",sep="")) plot(steps[[step]]) dev.off() } But if I use qplot to generate the plot (which is my aim): for (step in 1:length(steps)) {

I get the following error when I run qplot() qplot(grade, read,data = hhm.long.m, geom = c("point", "smooth")) Error in smooth.construct.cr.smooth.spec(object, data, knots) : x has insufficient unique values to support 10 knots: reduce k. I am not sure how to tackle this problem. When I take a subsample (< 1000) than I am able to run that function but with my sample

Hi, I have created following "list" object : > library(zoo) > dat <- vector("list") > for (i in 1:4) dat[[i]] <- zooreg(rnorm(i*10), > start=as.Date("2000-01-01"), frequency=1) > dat[[1]] 2000-01-01 2000-01-02 2000-01-03 2000-01-04 2000-01-05 2000-01-06 2000-01-07 2000-01-08 2000-01-09 2000-01-10 -0.7023352 -0.2063284 -1.0684688 -0.5345360

R-users it appears I am leaning on your knowledge once again.  Is there any way to add a vertical line to a histogram and qplot "stacked" plot?  Here is my current attempt:   "qplot" approach attempt: qplot(Run, data = data_dataframe, breaks = breaks, fill = Temperature, main = short_title) + scale_x_continuous("Data") + scale_y_continuous("Freq")