Displaying 20 results from an estimated 600 matches similar to: "what is 'class.ind' here?"
2009 May 24
2
accuracy of a neural net
Hi. I started with a file which was a sparse 982x923 matrix and where the
last column was a variable to be predicted. I did principle component
analysis on it and arrived at a new 982x923 matrix.
Then I ran the code below to get a neural network using nnet and then wanted
to get a confusion matrix or at least know how accurate the neural net was.
I used the first 22 principle components only for
2009 Nov 02
1
modifying predict.nnet() to function with errorest()
Greetings,
I am having trouble calculating artificial neural network 
misclassification errors using errorest() from the ipred package. 
I have had no problems estimating the values with randomForest() 
or svm(), but can't seem to get it to work with nnet(). I believe 
this is due to the output of the predict.nnet() function within 
cv.factor(). Below is a quick example of the problem I'm
2013 May 20
0
Neural network: Amore adaptative vs batch why the results are so different?
I am using the iris example came with nnet package to test AMORE. I can see
the outcomes are similar to nnet with adaptative gradient descent. However,
when I changed the method in the newff to the batch gradient descent, even
by setting the epoch numbers very large, I still found all the iris
expected class=2 being classified as class=3. In addition, all those
records in the outcomes (y) are the
2005 Jul 27
1
how to get actual value from predict in nnet?
Dear All,
After followed the help of nnet, I could get the networks trained and, excitedly, get the prediction for other samples. It is a two classes data set, I used "N" and "P" to label the two. My question is, how do I get the predicted numerical value for each sample? Not just give me the label(either "N" or "P")?  Thanks!
FYI: The nnet example I
2011 Oct 05
1
Require Information
Hi there!
 
I would like to ask kindly for some further information concerning Rsync
software.
What I am planning to do is to replicate data (database) at certain
intervals.
My first question is, can I do this with Rsync?
To be more specific I have a mysql database at a point and I want this
database to be replicated to a remote side at real-time.
In other words I need to setup a backup
2009 Jul 20
0
No subject
faced this exact same problem a few times on more than one servers and it
was 1) dialplan issue which was not hanging up the zap channels correctly 2)
using more than 8 spans on a server. Asterisk can't handle more than 96 zap
channels on T1s. FXO/FXS combinations can vary the number of spans but if
you know what I mean by spans, in production don't use more than 6 spans.
On 2010-03-17
2013 Oct 31
0
[LLVMdev] loop vectorizer
>> What needs to be done (on a high level) in order to have the auto vectorizer succeed on the test function as given erlier?
> Maybe you could rewrite the loop in a way that will expose contiguous memory accesses. Is this something you could do ?
>
Hi Nadav,
the only option I see is to unroll the loop by hand. Since the array 
access is consecutive over 4 loop iterations I gave it a
2004 Jan 09
3
ipred and lda
Dear all,
can anybody help me with the program below? The function predict.lda
seems to be defined but cannot be used by errortest.
The R version is 1.7.1
Thanks in advance,
	Stefan
----------------
library("MASS");
library("ipred");
data(iris3);
tr <- sample(1:50, 25);
train <- rbind(iris3[tr,,1], iris3[tr,,2], iris3[tr,,3]);
test <- rbind(iris3[-tr,,1],
2013 Oct 31
2
[LLVMdev] loop vectorizer
On Oct 30, 2013, at 6:10 PM, Frank Winter <fwinter at jlab.org> wrote:
> the only option I see is to unroll the loop by hand. Since the array access is consecutive over 4 loop iterations I gave it a try and unrolled the loop by a factor of 4.  Which gives the following array accesses:
> 
> loop iter 0:
> index_0 = 0   index_1 = 4
> index_0 = 1   index_1 = 5
> index_0 = 2  
2002 Mar 17
3
apply problem
> data(iris)
# iris3 is first 3 rows of iris
> iris3 <- iris[1:3,]
# z compares row 1 to each row of iris3 and is correctly 
computed
> z <- c(F,F,F)
> for(i in seq(z)) z[i] <- identical(iris3[1,],iris3[i,])
> z
[1]  TRUE FALSE FALSE
# this should do the same but is incorrect
> apply(iris3,1,function(x)identical(x,iris3[1,]))
    1     2     3 
FALSE FALSE FALSE 
2013 Oct 31
0
[LLVMdev] loop vectorizer
I tried the following on the hand-unrolled loop:
       const std::uint64_t ir0 = i*8+0; // working
       const std::uint64_t ir0 = i%4+0; // working
       const std::uint64_t ir0 = (i+0)%4;  // not working
'+0' means +1,+2,+3 in the unrolled iterations.
'Working' means the SLP vectorizer succeeded.
Thus, when working 'towards' the correct index function, auto 
2000 Mar 08
3
Reading data for discriminant analysis
Dear R users,
I want to do discriminant analysis on my data. I have
successfully followed the discriminant analysis in V & R on
the iris data:
> ir <- rbind (iris3[,,1],iris3[,,2],iris3[,,3])
> ir.species <- c(rep("s",50),rep("c",50),rep("v",50))
> a <- lda(log(ir),ir.species)
> a$svd^2/sum(a$svd^2)
[1] 0.996498601 0.003501399
> a.x <-
2004 Mar 29
1
Interpreting knn Results
Maybe you should show your colleague how to access help pages in R?  Right
in ?knn, it says:
    prob: If this is true, the proportion of the votes for the winning
          class are returned as attribute 'prob'. 
so 1.0 mean all three NNs are of the `winning'; i.e., predicted, class, and
0.66667 means 2 out of the 3 NNs are of the winning class, etc.  
Andy
> From: Ko-Kang
2004 Nov 02
2
lda
Hi !!
I am trying to analyze some of my data using  linear discriminant analysis.
I worked out the following example code in Venables and Ripley
It does not seem to be happy with it.
============================
library(MASS)
library(stats)
data(iris3)
ir<-rbind(iris3[,,1],iris3[,,2],iris3[,,3])
ir.species<-factor(c(rep("s",50),rep("c",50),rep("v",50)))
2011 Mar 11
1
[Bug 704] Issue with "iptables -A OUTPUT -m string"
http://bugzilla.netfilter.org/show_bug.cgi?id=704
CZ <huangj at qualcomm.com> changed:
           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|RESOLVED                    |REOPENED
         Resolution|FIXED                       |
--- Comment #4 from CZ <huangj at qualcomm.com> 
2013 Oct 30
0
[LLVMdev] loop vectorizer
Well, they are not directly consecutive. They are consecutive with a 
constant offset or stride:
ir1 = ir0 + 4
If I rewrite the function in this form
void bar(std::uint64_t start, std::uint64_t end, float * __restrict__  
c, float * __restrict__ a, float * __restrict__ b)
{
   const std::uint64_t inner = 4;
   for (std::uint64_t i = start ; i < end ; ++i ) {
     const std::uint64_t ir0 = (
2009 Nov 17
1
Error running lda example: Session Info
>
> library(MASS)
> Iris <- data.frame(rbind(iris3[,,1], iris3[,,2], iris3[,,3]),
+                    Sp = rep(c("s","c","v"), rep(50,3)))
> train <- sample(1:150, 75)
> table(Iris$Sp[train])
 c  s  v
22 23 30
> z <- lda(Sp ~ ., Iris, prior = c(1,1,1)/3, subset = train)
Error in if (targetlist[i] == stringname) { : argument is of length
2010 Sep 07
2
[LLVMdev] Complex regalloc contraints
Hi all,
The machine I am targeting has some special requirements for some
operations, say:
ADD or1, ir1, r5
would add ir1 (input reg 1) and r5 and put the result in or1 (output reg
1). The point id that input and output regs have to go paired (this
meaning an addition of ir1 with whatever always goes to or1, or an in
general irX + whatever goes to orX).
AFAIK, InstrInfo.td only allow
2013 Oct 30
0
[LLVMdev] loop vectorizer
Hi Frank, 
The access pattern to arrays a and b is non-linear.  Unrolled loops are usually handled by the SLP-vectorizer.  Are ir0 and ir1 consecutive for all values for i ?
 
Thanks,
Nadav
On Oct 30, 2013, at 9:05 AM, Frank Winter <fwinter at jlab.org> wrote:
> The loop vectorizer seems to be not able to vectorize the following code:
> 
> void bar(std::uint64_t start,
2014 Mar 03
0
Re: 'virsh capabilities' on Debian Wheezy-amd64 reports different cpu to Wheezy-i386 (on same hardware)
On Mon, Mar 03, 2014 at 02:15:43PM +0000, Struan Bartlett wrote:
>
>
> On 03/03/2014 13:42, Martin Kletzander wrote:
> > On Mon, Mar 03, 2014 at 11:15:51AM +0000, Struan Bartlett wrote:
> >> On 03/03/2014 10:55, Martin Kletzander wrote:
> >>> On Mon, Mar 03, 2014 at 10:47:03AM +0000, Struan Bartlett wrote:
> >>>> On 03/03/2014 10:44, Martin