similar to: custom sort?

Why when I assign 0 to an element of an integer vector does the type change to numeric? Here is a particularly perplexing example: > v <- 0:10 > v [1] 0 1 2 3 4 5 6 7 8 9 10 > class(v) [1] "integer" > v[1] <- 0 > class(v) [1] "numeric" #!! > -- View this message in context:

Why when I assign 0 to an element of an integer vector does the type change to numeric? Here is a particularly perplexing example: > v <- 0:10 > v [1] 0 1 2 3 4 5 6 7 8 9 10 > class(v) [1] "integer" > v[1] <- 0 > class(v) [1] "numeric" #!! > -- View this message in context:

I'd like to write some objects (eg arrays) to a log file. cat() flattens them out. I'd like them formatted as in 'print' but print only writes to stdout. Is there a simple way to achieve this result? Thanks -- View this message in context: http://www.nabble.com/print%28%29-to-file--tp24397445p24397445.html Sent from the R help mailing list archive at Nabble.com.

Suppose I have an n-diml array A and I want to extract the first "row" -- ie all elements A[1, ...] Interactively if I know 'n' I can write A[1,,,,,] with (n-1) commas. How do I do the same more generally, eg in a script? (I can think of doing this by converting A to a vector then extracting the approp elements then reshaping it to an array, but I wonder if there isn't a

I've asked about custom sorting before and it appears that -- in terms of a user-defined order -- it can only be done either by defining a custom class or using various tricks with "order" Just wondering if anyone has a clever way to order "vintages" of the form 2002, 2003H1, 2003H2, 2004, 2005Q1, 2005Q2, etc some have H1 or H2, some have Q1,Q2,Q3,Q4, some are just plain

When I do dev.new(), the resulting window comes to the front and grabs the focus. Is there a way to prevent this so I can continue working in other windows while the graphics are being produced? Thanks -- View this message in context: http://www.nabble.com/X-window-graphics----preventing-window-coming-to-front--tp24167763p24167763.html Sent from the R help mailing list archive at Nabble.com.

Hi. I'm maintaining a package that creates an object that is essentially a classed version of numeric. I updated recently from 2.7.1 to 2.9.0, and merges involving my class suddenly took a huge performance hit. I've traced the problem to something near rank(). From NEWS, it seems rank() etc. changed in 2.8.0. Methods for xtfrm() are supposed to help, but I've had no success. There

I've got a matrix with 2 columns and n rows. I need to sort it first by the values in column 1 ascending. Then for values which are the same in column 1, sort by column 2 decending. For example: 2 .5 1 .3 1 .5 3 .2 Goes to: 1 .5 1 .3 2 .5 3 .2 This is easy to do in spreadsheet programs but I can't seem to work out how to do it in R and haven't been able to find a solution anywhere.

Dear all, I have a large vector (lets call it myVector) and I want to plot its value with the logic below yaxis<-myVector[1] yaxis<-c(xaxis,mean(myvector[2:3]) yaxis<-c(xaxis,mean(myvector[4:8]) yaxis<c(xaxis,mean(myvector[9:16]) yaxis<c(xaxis,mean(myvector[17:32]) this has to stop when the new ..... yaxis<c(xaxis,mean(myvector[1024:2048]) will not find the correspondent number

Hi, set.seed(29) myVector<- rnorm(100) ?seq(1,100,by=2) # [1]? 1? 3? 5? 7? 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 #[26] 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 myVector[seq(1,100,by=2)] rev(myVector) ?sum(myVector>0) #[1] 46 #or ?table(myVector>0) # #FALSE? TRUE ?#? 54??? 46 A.K. Hey guys, this is my first week

>From: Johannes Graumann <johannes_graumann at web.de> >Date: 2007/12/18 Tue PM 04:40:37 CST >To: r-help at stat.math.ethz.ch >Subject: [R] All anchored series from a vector? lapply(1:length(myvector) function(.length) { c(myvector[1}:myvector[.length]) }) but test it because i didn't. >Hi all, > >What may be a smart, efficient way to get the following result:

Yes, I am a newbie. I have a data.frame (MyTable) of 1445846 rows and 15 columns with character data. And a character vector (MyVector) of 473491 elements. I want simply to get a data.frame with the count of how many times each element of MyVector appears in MyTable. I've tried a loop with : for (i in 1 : length (myvector)) sum (MyTable== i) but it crashes my computer. I've also

? Fri, 12 Jul 2024 17:35:19 +0200 Hilmar Berger via R-devel <r-devel at r-project.org> ?????: > This can be finally traced to base::rank() (called from > xtfrm.default), where I found that > > "NB: rank is not itself generic but xtfrm is, and rank(xtfrm(x), ....) > will have the desired result if there is a xtfrm method. Otherwise, > rank will make use of ==, >,

Good evening, I recently have observed slow merges when combining multiple data frames derived from DataFrame and base::data.frame. I observed that the index column of intermediate tables was of class <AsIs> (automatically converted from character). The problem occurred mainly when using the sorted = T option in base::merge. This can be traced to xtfrm.AsIs being more than 100 times slower

Hi, all I didn't get any response from swig for my question. see if I can get some help here Thanks ---------- Forwarded message ---------- From: charlie <charlie.xia.fdu@gmail.com> Date: Tue, Nov 4, 2008 at 1:55 PM Subject: SWIG with R and C++ STL To: swig-user@lists.sourceforge.net Hi all, I am new to SWIG. I encountered some problem when I try to SWIG to R some C++ modules. Here

I have two objects, one matrix and one vector. I want to use my vector to subset certain values out of my matrix. For example: I want to tell R, to select out all rows in myMatrix into a new myMatrix2 IF that corresponding row is less than a 0.5 in myVector. So: myMatrix = a matrix of 8000 by 20 myVector = vector of 8000 myMatrix2 = a matrix of < 8000 by 20 (based on selection criteria in

Hello, Let's assume I have a vector of integers : > myvector <- c(1, 2, 3, 2, 1, 3, 5) My purpose is to obtain the cumulative distribution of these numerical data, i.e. something like : value nb_occur. <=1 2 <=2 4 <=3 6 <=4 6 <=5 7 For this, I create a table with ; > mytable <- table(myvector) 1 2 3 5 2 2 2 1 However, table() returns an array

I have been trying to write a new class that reimplements the vector class. As a test of my overloading I decided to try and and call t.test on two vectors which were objects of my class rather than the default class. The overloaded length I wrote seems to work correctly. I used setMethod("length", "myvector", ...) setMethod("mean", "myvector", ...)

Dear all, I have a vector with number that some of them are part of the   seq(1,800,4). How can I check which of the numbers belong to the seq(1,800,4)   LEt's say that is called myvector the vector with the numbers. Is there in R something like this? is.member(myvector,seq(1,800,4))   I would like to thank you in advance for your help   B.R Alex [[alternative HTML version deleted]]

Hello, I have an expression that I want to substitute for something else. myvector<-c("ajkhfkiuwe","Variable(kg/min)") if I use the following code to extract "variable(kg/min)" and substitute it for "va" gsub(myvector[grep("var", myvector, ignore=T)], "va", myvector) grep identifies the element of the vector that matches my