similar to: How do I get removed from this mailing list?

given what ?identical says, i find the following odd: x = 1:10 y = 1:10 all.equal(x,y) [1] TRUE identical(x,y) [1] TRUE y[11] = 11 y = y[1:10] all.equal(x,y) [1] TRUE identical(x,y) [1] FALSE y [1] 1 2 3 4 5 6 7 8 9 10 length(y) [1] 10 looks like a bug. platform i686-pc-linux-gnu arch i686 os linux-gnu system

the following is a trivialized version of some functional code i tried to use in r: (funcs = lapply(1:5, function(i) function() i)) # a list of no-parameter functions, each with its own closure environment, # each supposed to return the corresponding index when applied to no arguments sapply(funcs, function(func) func()) # supposed to return c(1,2,3,4,5) there is absolutely nothing unusual in

m = matrix(1:4, 2) apply(m, 1, cat, '\n') # 1 2 # 3 4 # NULL why the null? vQ

Following Duncan's suggestion, I forward the below to R-devel. vQ -------- Original Message -------- Subject: Re: [R] Randomly remove condition-selected rows from a matrix Date: Fri, 02 Jan 2009 10:34:52 -0500 From: Duncan Murdoch <murdoch at stats.uwo.ca> To: Wacek Kusnierczyk <Waclaw.Marcin.Kusnierczyk at idi.ntnu.no> CC: R help <R-help at stat.math.ethz.ch>

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to

I was wondering why the following doesn't work: > a=c(1,2) > names(a)=c("one","two") > a one two 1 2 > > names(a[2]) [1] "two" > > names(a[2])="too" > names(a) [1] "one" "two" > a one two 1 2 I must not be understanding some basic concept here. Why doesn't the 2nd name change to

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48242 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (80.202.30.36) The following raises an error: if (as.raw(1)) 1 # error: unimplemented type 'raw' in 'asLogical' However, ?'if' says: " Arguments: cond: A length-one logical vector that is not 'NA'. Conditions of length

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48365 OS: Ubuntu 8.04 Linux 32bit Submission from: (NULL) (129.241.110.141) sprintf has a documented limit on strings included in the output using the format '%s'. It appears that there is a limit on the length of strings included with, e.g., the format '%d' beyond which surprising things happen (output modified for conciseness):

It was recently pointed out by Wacek Kusnierczyk that although one is prevented from doing FALSE <- TRUE one *can* do assign("FALSE",TRUE) and have an object named ``FALSE'' with value TRUE in one's workspace. This apparently has no deleterious effects; e.g. doing sample(1:7,replace=FALSE) gives a random permutation of 1:7 as expected and desired. I.e. the local

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48269 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.199.164) In the following example (and many other cases): quote(a=1) # 1 the argument matching is apparently incorrect wrt. the documentation (The R Language Definition, v 2.8.1, sec. 4.3.2, p. 23), which specifies the following algorithm for argument matching: 1. Attempt to

Dear R Gurus: How do I find the functions which are primitives, please? Thanks, Edna Bell

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48242 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.110.161) In the following code: duplicated(data.frame(), incomparables=NA) # Error in if (!is.logical(incomparables) || incomparables) .NotYetUsed("incomparables != FALSE") : # missing value where TRUE/FALSE needed the raised error is clearly not the

Hello! I have the problem that in my function the passed variable is not used, but the variable name of the dataframe itself?- difficult to explain, but an easy example: TestFunc<-function(df, group) { ??? print(names(subset(df, select=group))) } df1<-data.frame(group="G1", visit="V1", value=0.9) TestFunc(df1, c("group", "visit")) Result: [1]

Dear all, let's assume I have a vector of character strings: x <- c("abcdef", "defabc", "qwerty") What I would like to find is the following: all elements where the word 'abc' does not appear (i.e. 3 in this case of 'x'). Since I am not really experienced with regular expressions, I started slowly and thought I find all word were

Hi all I have the following regular expression problem: I want to find complete elements of a vector that end in a repeated character but where the repetition doesn't make up the whole word. That is, for the vector vec: vec<-c("aaaa", "baaa", "bbaa", "bbba", "baamm", "aa") I would like to get "baaa" "bbaa"

Dear R Gurus: I read somewhere that functions are considered vectors. Is this true, please? thanks Edna Bell

i wonder about the following examples showing incoherence in how type conversions are done in r: x = TRUE x[2] = as.raw(1) # Error in x[2] = as.raw(1) : # incompatible types (from raw to logical) in subassignment type fix it seems that there is an attempt to coerce the raw value to logical here, which fails, even though as.logical(as.raw(1)) # TRUE likewise, x[2]

i wonder about the following examples showing incoherence in how type conversions are done in r: x = TRUE x[2] = as.raw(1) # Error in x[2] = as.raw(1) : # incompatible types (from raw to logical) in subassignment type fix it seems that there is an attempt to coerce the raw value to logical here, which fails, even though as.logical(as.raw(1)) # TRUE likewise, x[2]

the man page for relational operators (see, e.g., ?'<') says: " Binary operators which allow the comparison of values in atomic vectors. Arguments: x, y: atomic vectors, symbols, calls, or other objects for which methods have been written. " it is somewhat surprizing that the following works: '<'(1) # logical(0) '<'() #

the man page for relational operators (see, e.g., ?'<') says: " Binary operators which allow the comparison of values in atomic vectors. Arguments: x, y: atomic vectors, symbols, calls, or other objects for which methods have been written. " it is somewhat surprizing that the following works: '<'(1) # logical(0) '<'() #