similar to: How to create all pairs

Hello, I have two data. x<-c(1, 2, 3) y<-c(4,5,6) How do i create matrix of 3 by 3 from this two, such that (1,4) (1,5) (1,6) (2,4) (2,5) (2,6) (3,4) (3,5) (3,6) I tried some thing like this: xy <- as.data.frame(c(0,0,0), dim=c(3,3)) for(i in 1:3) for(j in 1:3) xy[i][j]<-c(x[i],y[j]) but i got errors..!!!! any help would appreciate -- View this message in

Hi! Is there any easy/fast way to combine vectors with restrictions? Example: a=c(1,2,3), b=c(4,5,6), c=c(7,8,9) I want all combinations of this 3 vectors with length=2. Like this: 1,4 1,5 1,6 1,7 1,8 1,9 2,4 2,5 2,6 2,7 ... and so on. Thanks in advance. [[alternative HTML version deleted]]

hi i try to do a graph of a time series which shows in red the values > -0.05, in blue the values >0.05 and in white the values between -0.05 and 0.05 for un exemple :http://www.appinsys.com/globalwarming/enso.htm thanks !!!!! denisse -- View this message in context: http://r.789695.n4.nabble.com/how-to-do-a-graph-with-tree-different-colors-tp4635206.html Sent from the R help mailing

http://r.789695.n4.nabble.com/file/n3612530/PSC.r PSC.r Hi all, I just wrote a program in R by editing it in Microsoft Word and then pasting into the text editor of R. The above is the file. And below is what the console complains.... Why doesn't it recognise 'r'?? I have to mention that at least when I typed this first several lines into the console, the first error didn't

Hi, Try this: #mat1 is the data res<-do.call(cbind,lapply(seq_len(nrow(mat1)),function(i) {new1<-do.call(rbind,lapply(seq_len(nrow(mat1[-i,])),function(j) {x1<-rbind(mat1[i,],mat1[j,]); x2<-(abs(x1[1,1]-x1[2,1])*abs(x1[1,5]-x1[2,5]))+(abs(x1[1,2]-x1[2,2])*abs(x1[1,6]-x1[2,6]))+(abs(x1[1,3]-x1[2,3])*abs(x1[1,7]-x1[2,7]))+(abs(x1[1,4]-x1[2,4])*abs(x1[1,8]-x1[2,8]))}));new1}))

Hi all, I'm a newbie R developer, am trying to dotplot a few graphs using a for loop. The following code works fine but once I wanna plot inside a loop, nothing happens. > for(i in 1:1){dotplot(y~x)} > y <- c(1,2,3) > x <- c('a','b','c') > dotplot(y~x) > for (i in 1:3) {dotplot(y~x)} (y and x depends on I in actual case) Nothing happens. I

my data are matrix with 3 numeric columns. would like to have pairs plot with scatterplots in the upper with hist at the diag and with correlation at the lower. actually default pairs does almost what I want but looks semi awesome. Especially, i didn't find out how to remove the axes from the lower part where I do only want to display the numeric values correlations there and somehow axes

Hi. Can anyone suggest a simple way to obtain in R a list of vector coordinates of the following form? The code below is Mathematica. In[5]:= Flatten[Table[{i,j,k},{i,3},{j,4},{k,5}], 2] Out[5]= {{1,1,1},{1,1,2},{1,1,3},{1,1,4},{1,1,5},{1,2,1},{1,2,2},{1,2,3},{1 ,2,4},{1,2, 5},{1,3,1},{1,3,2},{1,3,3},{1,3,4},{1,3,5},{1,4,1},{1,4,2},{1,4,3}, {1,4,

Would someone be able to help with this question? I'm using the Gcmrec, Survrec, and Design packages to do a power analysis on simulated data. I'm receiving an error after using the Survr function that all data must have a censoring time even after using the gcmrec function: newdata<-addCenTime(olddata). My program is below. I'd greatly appreciate any help!

Dear Colleagues, I am looking for a package or previous implemented R to subgroup and exaustively divide a vector of squence into 2 groups. For example: 1, 2, 3, 4 I want to have a group of 1, (2,3,4) (1,2), (3,4) (1,3), (2,4) (1,4), (2,3) (1,2,3), 4 (2,3), (1,4) ... Can someone help me as how to implement this? I get some imaginary problem when the sequence becomes large. Thanks much in

Dear R-list members, I would like to pose a question about the use and results of the glm() function for logistic regression calculations. The question is based on an example provided on p. 229 in P. Dalgaard, Introductory Statistics with R, 2nd. edition, Springer, 2008. By means of this example, I was trying to practice the different ways of entering data in glm(). In his book, Dalgaard

Dear R experts, Suppose I have an data frame likes this: > example <- data.frame(age=c(1,2,3, 4,5,6), height=c(100,110,120,130,140,150), disease=c(TRUE, TRUE, TRUE, FALSE, FALSE, FALSE)) > example age height disease 1 1 100 TRUE 2 2 110 TRUE 3 3 120 TRUE 4 4 130 FALSE 5 5 140 FALSE 6 6 150 FALSE Is there anyway to compare the age and

several errno.h for no good reasons. cleanup losesetup which is not using getopt_long, thus doesn't need getopt.h included. Move stdarg.h include up in losesetup to more proper place. Signed-off-by: maximilian attems <max at stro.at> --- usr/utils/dmesg.c | 1 - usr/utils/losetup.c | 4 +--- usr/utils/mkfifo.c | 1 - usr/utils/nuke.c | 1 - usr/utils/umount.c | 1

Hi, I am trying to write a simulation of the movements of four animals between six patches. The movement between patches is based on a first-order Markov chain so that the next patch they visit depends on the patch they were in before. I have written code that allows me to simulate the movement of one animal but when I add more there seems to be a problem and all chains come back as N/A. I can

Hi, this is probably a very trivial question but I can't figure out the right terms to find the solution in the list archive. I have a matrix or a data.frame or the like: > m <- matrix(ncol=3,seq(1,9)) > m [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 and now I wonder if one can provide somehow two vectors, one containing row numbers, the other

I've the following problem: The below function runs a loop with regression analysis and stores F-Stat in a matrix. When I call the matrix elements (models[i,j]) in the function I get proper results, but when I try to call the same elements outside the function the matrix appears to be empty e.g when I call compt inside the function I get: 5 but when I call it outside I get: 1. This is the

Hi, I need some help with this one: how do I check whether a vector is already present in a list of vectors. I have seen %in% recommended in a similar case but that obviously does not work here. c(1,2,3) %in% list(c(1,2,3), c(4,5,6)) returns [1] FALSE FALSE FALSE which makes sense since 1, 2 or 3 are not elements of that list. I don't really know how to move from there though. Best

R users, I am trying to generate a randomized weekday survey schedule that ensures even coverage of weekdays in the sample, where the distribution of variable DOW is random with respect to WEEK. To accomplish this I need to randomly sample without replacement two weekdays per week for each of 27 weeks (only 5 are shown). However, I need to sample from a sequence (3:7) that needs to be

Hi all, Hi this is kiran I am facing a problem to split a dataframe that is.. i have a string like: "a,b,c|1,2,3|4,5,6|7,8,8" first I have to split with respect to "|" I did it with command unlist(strsplit("a,b,c|1,2,3|4,5,6|7,8,8", "\\,")) after getting that set i made it as a dataframe and it comes like a,b,c 1,2,3 4,5,6 7,8,8 now i have to

Hi all, I am designing a study in which I am selecting a subset of college courses to be randomly assigned to one of two conditions. I would like to create matched pairs of courses, and then randomly assign them to condition within each pair. I would like to identify, for each course, the one that best matches it, and quantify how well it matches. Here is a much simpler data set for purposes of