similar to: help with gsub and date pattern

I was working with the rmetrics portfolioBacktesting function and dug into the code to try to find why my formula with 113 items, i.e. A1 thru A113, was being truncated and I only get 85 items, not 113. Is it due to a string length limitation in R or is it a bug in the strsplit or gsub functions, or in my string? I'd very much appreciate any suggestions ============Input script:

Dear List, I am having problems converting a file with fractional seconds to class POSIXct. I have set my options to include digits.secs and my format to just time, but my output is the current date with my time lacking the fractions of a second. For example: options(digits.secs=3) t<-c("06:00:00.100","06:00:01.231") myt<-as.POSIXct(t,format="%H:%M:%S")

Dear List, I need some help in coming up with a function that will take two data sets, determine if a value is missing in one, find a value in the second that was taken at about the same time, and substitute the second value in for where the first should have been. My problem is from a fish tracking study. We put acoustic tags in fish and track them for several days. Location data is supposed

Dear List, I would like to create several graphs of similar data. I have x and y values for several different individuals (in this case fish). I would like to plot the x and y values for each fish separately. I can do it using a for loop, but I think I should be using "apply". Please let me know what I am doing wrong, or if there is a "better" way to do this. What I have

Hi ALL, I have very simple question regarding pattern matching. Could anyone tell me how to I can use R to retrieve string pattern from text file. for example my file contain following information SpeciesCommon=(Human);SpeciesScientific=(Homo sapiens);ReactiveCentres=(N,C,C,C,+ H,O,C,C,C,C,O,H);BondInvolved=(C-H);EzCatDBID=(S00343);BondFormed=(O-H,O-H);Bond+

Hi, I'm looking for some way to pick up the numbers which are contained and buried in a long character. For example, outtree.new="(((B:1204.25,E:1204.25):7581.11,F:8785.36):8353.85,C:17139.21);" num.char =

Hi, I have a vector like this: DF <- c("Aetna, Inc.", "Alexander's Inc.", "Allegheny Energy, Inc") For each element in the vector I would like to remove the "incorporated" info, so that my vector looks like this: DF <- c("Aetna", "Alexander's", "Allegheny Energy") That means that I have to strip: strip <-

Hi A while back I used gsub to do the following temp<-"000US00231" gsub("something here", "", temp) "00231" I think it involved the `meta characters' somehow. I do not know how to do this anymore. I know strsplit will also work but I remember gsub was much faster. In essence the question is how to delete all characters before a particular

In a string context, grep, gsub, sub are improperly treating NA (missing) as the string "NA", and returning unexpected results > grep("A", c(NA,"NA")) [1] 1 2 # expected: # [1] 2 > gsub("A", "X", c(NA,"NA")) [1] "NX" "NX" # expected # [1] NA "NX" > sub("A", "X",

Hi, I think it is not possible in R but I rather ask before giving up: What I have: I have copied "C:\Program Files\R" into my clipboard. What I want: setwd(transform("C:\Program Files\R")) where the function transform should change the "C:\Program Files\R" from my clipboard to "C:\\Program Files\\R" so that R can handle it. Is this possible? I've

Hi Guys, I am relatively new to R and was wondering if I could next my gsub command in identifying one object I have data which looks like this: <name>Taiwan_250km</name> I want it to look like this: Taiwan_250km So essentially I just want to gsub '<name>' and </name> with nothing! So far I have got this: PolyNam <-

Dear R users, my problem today deals with my ignorance on regular expressions. a matter I recently discovered. Consider the following foo <- c("V_7_101110_V", "V_7_101110_V", "V_9_101110_V", "V_9_101110_V", "V_9_s101110_V", "V_9_101110_V", "V_9_101110_V", "V_11_101110_V", "V_11_101110_V",

Hi all, Let Names a vector of chatacters. For example, > Names [1] "g 604 be-0 -p1 (602 matches)" "g 606 Phli-0 -p2 (517 matches)" [3] "g 608 alu-0 (659 matches)" I try to use gsub or grep functions for two problems : 1. First, I would like to delete all the characters between parentheses. [1] "g 604 be-0 -p1" "g 606 be-0 -p2" [3] "g

Dear List, I am trying to do model averaging for a negative binomial model using the package AICcmodavg. I need to use glm() since the package does not accept glm.nb() models. I can get glm() to work if I first run glm.nb and take theta from that model, but is there a simpler way to estimate theta for the glm model? The two models are: mod.nb<-glm.nb(mantas~site,data=mydata)

Dear R-users -- I'm using R 1.3.0 on a PC running SuSE Linux 7.1. I'm confused by the following behavior from the gsub() function. Am I doing something wrong? ## A string of characters > string<-c("q","w","e","(",")","q","w","e") ## Use gsub to replace `q' with `A' >

Hi, I perform the operations unlist,strsplit,gsub and the for loop on a lot of strings and its heavily slowing down the overall system. Is there some way for me to speeden up these operations..maybe like alternate versions that exist which use multiprocessors etc. -- Rajesh.J [[alternative HTML version deleted]]

Dear R-Users, I have two questions: a) in a directory there are 3 files: [1] "Data.~csv" "Kopie von Data.~csv" "VorlageTradefile.csv" The command "dir( fold, pattern = "\.csv" )" gives back *all* the 3 files With dir( fold, pattern = "\\.csv" ) I get back only VorlageTradefile.csv. I don't understand this behaviour,

Hi All, Is there a means to extract the "10" from "23:10:34" in one pass using strsplit (or something else)? tst <- "23:10:34" For example my attempt strsplit(as.character(tst),"^[0-9]*:") gives [[1]] [1] "" "" "34" Obviously it is matching the first two instances of [0-9]. Note that there may be only one digit

Hi, search in web for regular expressions i get the information that the line below replace all AUTO string's like AUTOBAHN ,AUTORENNEN with 1 but nothing happend. Using the [] in the pattern it works like i'm expected, but i didn't want single character replacment. Where is my mistake? bcode <- gsub("/^AUTO.*/","1",MyStringVector,ignore.case=T,extended=T)

Hi. Is there a straightforward way to convert a character string containing comma-delimited numbers to a numeric vector? In my application, I use system(executable.string, intern=TRUE) which returns a string like "[0.E-38, 2.096751179214927596171268230, 3.678944959657480671183123052, 4.976528845643001020345216157, 6.072390165503099343887569007, 7.007958550337542210168866070,