similar to: Concatenating two vectors into one

Hello list, i am trying to plot a continous variable y against a "date" variable, both in one dataframe named "df", using a code like this library(lattice) plot1<-xyplot(y~date, data=df, type="b") "date" is of class "Date", of course, format="%d.%m.%Y", and spans two calendar years. The problem is that the x-axis is labeled with

Dear all, I want to concatenate the elements of two vectors such as a<-c("a1","a2") b<-c("b1","b2") and obtain "a1b1", "a1b2","a2b1","a2b2" I tried the paste and paste0 functions, but they yielded elementwise concatenation such as "a1b1","a2b2" I am wondering that is there an efficient

Dear R users, i am using the following code to produce barcharts with lattice: Compound<-c("Glutamine", "Arginine", "Glutamate", "Glycine", "Serine", "Glucose", "Fructose", "Raffinose", "Glycerol", "Galacglycerol", "Threitol", "Galactinol", "Galactitol")

Dear list, i am using the following code to produce  a lattice xyplot, but the axis.break-function is seemingly not executed. Date<-seq(as.Date("2006-08-29"), as.Date("2007-08-28"), by="2 weeks") Period<- var1<-rnorm(27, 90000000, 30000000) var2<-rnorm(27, 500000000,250000000) var3<-rnorm(27, 1000000,500000) var4<-rnorm(27, 600000,300000)

Dear list, using the packages Hmisc and lattice i produced some nice xYplots. However, since the data range of the conditioning variable is very big, i need to define more than one y-scale for the plot (in some panels you just see a flat line of data points very close to the x-axis), e.g. different y-axis scales for the different rows of the plot. Is there a way to do so? Thanks, Henning

Dear users, i just installed the lastest version of R, 2.8.1 on my computer (OS Windows XP). Then i tried to update the packages copied from my old R version by >update.packages(ask=F) However i get the following warning: "Warning: unable to access index for repository http://cran.ch.r-project.org/bin/windows/contrib/2.8 Warning: unable to access index for repository

Dear list, for a data structure like in df: set.seed(100) Treatment<-rep(c("Nitrogen","Carbon", "Sulfur"),each=9) week<-rep(c(1,5,9),3,each=3) genes<-rep(c("18s", "EF1b", "NR"),9) copies<-rnorm(27, 1000000,400000) df<-data.frame(Treatment,week,genes,copies) i wrote this code for a xyplot: library(lattice)

Colleagues, I want to create the following array: "A1", "A2", "A3", "B1", "B2", "B3", "C1", "C2", "C3" I recall that there is a trick using "c" or "paste" permitting me to form all combinations of c("A", "B", "C") and 1:3. But, I can't recall the

Hi, I have a three dimensional array, e.g., my.array = array(0, dim=c(2,3,4), dimnames=list( d1=c("A1","A2"), d2=c("B1","B2","B3"), d3=c("C1","C2","C3","C4")) ) what I would like to get is then a dataframe: d1 d2 d3 value A1 B1 C1 0 A2 B1 C1 0 . . . A2 B3 C4 0 I'm sure there is one function to do

Hi, I am trying to aggregate the sum of my test data.frame as follow: testDF <- data.frame(v1 = c("a", "a", "a", "a", "a", "b", "b", "b", "b", "b", "c", "c", "c", "c", "c", "d", "d", "d", "d",

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I have a dataset that is basically structureless. Its dimension varies from row to row and sep(s) are a mixture of tab and semi colon (;) and example is HEADER1 HEADER2 HEADER3 HEADER3 A1 B1 C1 X11;X12;X13 A2 B2 C2 X21;X22;X23;X24;X25 A3 B3 C3 A4 B4 C4 X41;X42;X43 A5 B5 C5 X51 etc., say. Note that a blank

Dear all: I have this: A1 B1 C1 D1 E1 A2 B2 C2 D2 E2 A3 B3 C3 D3 E3 And I want this A1 E1 B1 E1 C1 E1 D1 E1 A2 E2 B2 E2 C2 E2 D2 E2 A3 E3 B3 E3 C3 E3 D3 E3 Example: m<- matrix(1:15,nrow=3,byrow=T) m v<- unlist(list(t(m[,1:4]))) u<- rep(c(5,10,15),c(4,4,4)) data.frame(v,u) This is the result I want but I would like to learn a simpler way to do it. Any clue?

Dear R-help readers, I'm sure this problem has been answered but I can't find the solution. I have two vectors v1 <- c("a","b") v2 <- c(1,2,3) I want an easy way to produce every possible combination of v1, v2 elements Ie I want to produce c("a1","a2","a3", "b1","b2","b3") regards Desmond Desmond

Dear R-users, i encountered some problems when trying to adjust the line width of the axes and stripes in a plot created with ggplot2. I use the "barley" dataset of the lattice package to illustrate my problem: library(ggplot2) library(lattice) barley[["SD"]] <- 5 limits <- aes(ymax=barley$yield + barley$SD,ymin=barley$yield - barley$SD) p1 <-

Hi all, I frequently encounter datasets that require me to repeat the same calculation across many variables. For example, given a dataset with total employment variables and manufacturing employment variables for the years 1990-2010, I might have to calculate manufacturing's share of total employment in each year. I find it cumbersome to have to manually define a share for each year and

See if the following helps: > m <- outer(letters[1:5], 1:4, paste, sep="") > m [,1] [,2] [,3] [,4] [1,] "a1" "a2" "a3" "a4" [2,] "b1" "b2" "b3" "b4" [3,] "c1" "c2" "c3" "c4" [4,] "d1" "d2" "d3" "d4" [5,]

There are function which does have optimization opportunities but because of may-alias memory dependencies sometimes optimization is not effective. May be runtime checks kills the gains of optimization. For such cases aiming to do interprocedural function specialization optimization where in the clone function version no-alias assumption can be assumed and the original function version will hold

Friends I am extracting sub-sets of the rows of a matrix. Generally the result is a matrix. But there is a special case. When the result returned is a single row it is returned as a vector (in the example below an integer vector). If there are 0, or more than 1 rows returned the result is a matrix. I am doing this in a function and I cannot be sure how many rows I am removing. How can I do

Dear R-gurus, being very new to R, (as well as lazy and not too smart !) I have some problems (and get lost in the docs) trying to write something to find the 9 values (A1,B1,C1,A2,B2,C2....C3) which are solutions of a 12 equations system of the form : > x1-(A1/(A1+B1+C1)) = 0 > y1-(B1/(A1+B1+C1))= 0 > z1-(C1/(A1+B1+C1)) = 0 > 3 same equations with subscript 2 > 3 same