similar to: transposing/rotating XY in a 3D array

I have what is probably a noob question, but.... I am trying to create a 3d plot to illustrate the range of values for the following simple function: A = B*(C/D) B, C, and D are independent variables whose range are equal (e.g. 1 to 3 inclusive) I figure it's not possible to map the surface of A on the 3d space defined by B, C and D but I would like to create a surface defined by the

Hi. Can anyone suggest a simple way to obtain in R a list of vector coordinates of the following form? The code below is Mathematica. In[5]:= Flatten[Table[{i,j,k},{i,3},{j,4},{k,5}], 2] Out[5]= {{1,1,1},{1,1,2},{1,1,3},{1,1,4},{1,1,5},{1,2,1},{1,2,2},{1,2,3},{1 ,2,4},{1,2, 5},{1,3,1},{1,3,2},{1,3,3},{1,3,4},{1,3,5},{1,4,1},{1,4,2},{1,4,3}, {1,4,

Dear Mailing-List, I think this is a newbie question. However, i would like to integrate a loop in the function below. So that the script calculates for each variable within the dataframe df1 the connecting data in df2. Actually it takes only the first row. I hope that's clear. My goal is to apply the function for each data in df1. Many thanks in advance. An example is as follows: df1

Dear Mailing-List, I think this is a newbie question. However, i would like to integrate a loop in the function below. So that the script calculates for each variable within the dataframe df1 the connecting data in df2. Actually it takes only the first row. I hope that's clear. My goal is to apply the function for each data in df1. Many thanks in advance. An example is as follows: df1

Dear all, > data <- data.frame(id=seq(1:10),x=runif(10)) > data id x 1 1 0.3604464 2 2 0.4813987 3 3 0.0160058 4 4 0.7165909 5 5 0.6092248 6 6 0.2413049 7 7 0.7981568 8 8 0.6093960 9 9 0.2887064 10 10 0.3485780 > selected.id <- sample(data$id,3,replace=F) > selected.id [1] 9 7 1 I want to select data with corresponding selected.id, namely >

Hello out there, im running Dovecot on "ubuntu Dapper" serving pop3 only in maildir-style, but the dove-auth-process refuses "answers" to the deliver or login-process from time to time, (several times a day), and I have no glue whats going on and why ... Debbugging password-Auth surprised me, as the transmitted password IS correct and allows an successfull authenification lots

Hi, I know we can use 1:10 to represent the 1,2,3,...,10 numbers, but the following conditions are except. Anybody knows how to represent the following two cases with similar usage of ":" or others? Usually, i will get several hundred names for them, such as a1,a2,... or f[[1]],f[[2]],... #Example data a1<-array(1:12,c(2,3,2)); a2<-array(2,c(2,3,2)); a3<-array(0,c(2,3,2))

Each row of my data frame is assigned to a class (eg country). Can you suggest how I break apart the data frame so that I create new data frames for each class eg If Class = "US" put in new dataframe dataUS Thanks in advance for your help Chris

Verified Credible Driving traffic to your website using testimonials Driving traffic to your website using Verifiedcredible.com testimonials will get you a good amount of traffic. First off many companies are looking for consumers to say good things about their products because it builds their creditability. Next when you find a good product why not say good things about it. It is a win-win for

Hello, This must be simple... Thanks a lot - Christoph # Imagine you have a list, e.g: K <- list(1:10, 2:11, 9:18) K # Transforming to dataframe... KK <- as.data.frame(K) # ... one obtaines the list elements as column. KK # But I need the list elements as rows # How can I achieve this? Is there a simple way to transpose data.frames?

I HAVE A VERY BIG DATA OF 67 COLMS AND 25000 ROWS AND WOULD LIKE TO TRANSPOSE IT THE R HELP WAS NOT ENOUGH INFORMATION BECOUSE I AM NOT A PROGRAMMER AND FIRST TIME R USER. SO CAN YOU GIVE SOME HINTS OF CODING, AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC TO AA AA AA AA AA TT TT TT TT TT GG GG GG GG GG GG GG GG GG GG CC CC CC CC CC [[alternative HTML

I am currently trying to transpose some large panel data set ie transposing multiple rows in into a single column. instead the transpose functionality transposes all rows into columns. my sample data set looks like below: ACCT_NUM ACCOUNT_NAME TRAN_AMT DATE EMPLOYER 101913 GK 7489 30-Apr-10 PENSION 101913 GK 7489 30-May-10 PENSION 101913

Dear R-user, I need help on how to transpose this column of clustering vector in R with 8768 entries derived from a PAM clustering output in a vertical  view to an excel file   Clustering vector:    [1] 1 1 2 2 1 2 1 2 1 1 2 2 1 2 2 2 2 1 1 1 1 2 2 1 2 2 1 2 2 2 2 2 2 2 2 1 2   [38] 2 1 1 2 2 2 2 2 1 2 1 2 2 2 2 1 2 1 2 2 1 2 2 2 2 2 2 1 2 1 2 2 2 1 1 2 2   [75] 2 1 2 2 2 2 2 2 2 1 1 2 1 2 2 2 2 2

Hi, I'm an R beginner and I'm struggling with what should be a rudimentary task. My data is along these lines: ID name1 name2 name3 name4 Class 0 1 0 2 Var1 A B C A Var2 B C C A Var3 C A B A etc. I'm using the following: foo <- data.frame(t(read.table("file", header=FALSE))) but of course now it's not using ID, Class, etc. as column names. As you can imagine,

Hi R, Can I transpose a data frame by a particular group variable? For example: d=data.frame(group=c(1,1,2,2,2),val=c(6,4,6,3,5)) And my output should be: data.frame(group=c(1,2),v1=c(6,6),v2=c(4,3),v3=c(NA,5)) Many thanks, Shubha This e-mail may contain confidential and/or privileged i...{{dropped:13}}

x <- read.table("LittleGarvin.csv", sep=",", header=TRUE) y <- t(x) str(y) chr [1:193, 1:288] "oligocha" "0" " 0" " 0" " 0" "0" ... - attr(*, "dimnames")=List of 2 ..$ : chr [1:193] "X" "upwd1201" "upwd0502" "upwd0702" ... ..$ : NULL x is a data frame with

Hello, I have a matrix that is a product of tapply on a larger data set. Let's assume it looks like this: X<-matrix(c(10,20,30,40,50,60),2,3) dimnames(X)<-list(c("1","2"),c("1","2","3")) (X) 1 2 3 1 10 30 50 2 20 40 60 Is there an efficient way of transforming this matrix into the following matrix: rows columns entries 1

Hello, everyone! I have a very simple task - I have a data frame (see MyData below) and I need to stack the data (see result below). I wrote the syntax below - it's very basic and it does what I need. But I am sure what I am trying to do is a very typical task and there must be a much shorter/more elegant way of doing it. Any advice? Thank you very much!

Hi. I have repeated measures data of the form where each observation is a trial, and trials are grouped by subject, and variables encode whatever level of a factor was present during that trial, and the dependent variable is response time (RT). I want to transpose the data to a form suitable for MANOVA such that there is one observation per subject and RT is recoded across many

Given: > mitest <- matrix(1:16,ncol=4) > dimnames(mitest)[[1]] <- c("a","b","c","d") > dimnames(mitest)[[2]] <- c("a","b","c","d") > mitest a b c d a 1 5 9 13 b 2 6 10 14 c 3 7 11 15 d 4 8 12 16 I can do: > mitest[cbind(c(1,2,3),c(2,3,2))] [1] 5 10 7 but using the names does not