similar to: matching period with perl regular expression

Hello, I have two time series objects, 1 is yearly (population) and the other is quarterly (bankruptcy statistics). I would like to produce a quarterly time series object that consists of bankruptcy/population. Is there a pre-built function to intelligently divide these time series: br.ts = ts(data=br.df[,-1], frequency = 4, start=c(2001,1), end=c(2008,2)) distPop.ts = ts(data=distPop.df[,-1],

Hello, I am working on a data set (already as a plm.data object) located here: http://econsteve.com/arch/plmWithDensity.Robj With the following R session: > library(plm) ... >load("plmWithDensity.Robj") >model <- plm(RATE ~ density08, data=plmWithDensity) Error: subscript out of bounds I am not understanding the "subscript out of bounds" error, as this is a

Hello, I am trying to use Sweave to write up a report, and I have used the plm package to do some panel models. I am trying to use xtable to make a nice table for my regression objects (returned by the plm command), but I am getting the error: Error in UseMethod("xtable") : no applicable method for "xtable" It seems like I would want to have xtable treat plm objects exactly

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Hi folks, Can anyone enlighten me as to why I get the following when I search for ".csv" at the end of a string? > grep("\.csv$","Blah.csv",value=TRUE) [1] "Blah.csv" Warning messages: 1: '\.' is an unrecognized escape in a character string 2: unrecognized escape removed from "[\.]csv$" R reference for regular expressions says

Here is my interaction with R: > sub(x='>|t|',pattern = '|t',replacement='zz') [1] "zz>|t|" So I say to myself "Clearly the | signs need to be escaped, so let's try this" > sub(x='>|t|',pattern = '\|t',replacement='zz') [1] "zz>|t|" Warning messages: 1: '\|' is an unrecognized escape in a

Hello, I would like to create a matrix with one of the columns named $\delta$. I have also created columns $\beta_1$ , $\beta_2$, etc. However, it seems like \d is an escape sequence which gets automatically removed. (Using these names such that they work right in xtable -> latex) colnames(simpleReg.mat) <- c("$\beta_1$","$SE(\beta_1)$", "$\beta_2$",

I thought that I can use metacharacters such as \w to match word characters with one backslash. But for some reason, I need to include two backslashes. > grepl(pattern='\w', x="what") Error: '\w' is an unrecognized escape in character string starting "\w" > grepl(pattern='\\w', x="what") [1] TRUE I can't find the reason for this

I am working with Sweave and would like to print out into my latex document the result of the R command version$platform So what I first tried in my .Rnw document was \Sexpr{print(version$platform)}. However, the output from this command is the string "x86_64-apple-darwin10.8.0" (without the quotes). This contains an underscore, which is a special character in tex and so I get an error

Hello, I have a simple question. I am trying to load data into a zoo object. I have the data in CSV format as follows SYMBOL DATE TIME PRICE XX YYYYMMDD HH:MM:SS n.nn and there are multiple symbols in this one data frame. My question is, do I need to merge DATE and TIME before loading them or can I specify multiple index.column or index.name fields?

Hello, Can anyone help on gsub() in R? I have a string like something below, and wanted to delete all the strings with leading backslash, including "\xa0On", "\023, "\xab", and many others. How should I write a regular expression pattern in gsub()? I don't care how many characters following backslash. txt <- "Is This Thing\xa0On? http://bit.ly/jAbKem

What's really the problem with: > regexpr( '\.odt$', "xxxxYodt", perl=TRUE ) Warning: '\.' is an unrecognized escape in a character string Warning: unrecognized escape removed from "\.odt$" [1] 5 attr(,"match.length") [1] 4 I know that I could use: > regexpr( '[.]odt$', "xxxxYodt", perl=TRUE ) But it seems to me that

How do I remove a "$" character from a string sub() and gsub() with "$" or "\$" as pattern do not work. > sub("$","","ABC$DEF") [1] "ABC$DEF" > sub("\$","","ABC$DEF") Error: '\$' is an unrecognized escape in character string starting "\$" >

Full_Name: FAN Version: 2.4.0 OS: Windows Submission from: (NULL) (159.50.101.9) These are expected: > grep("[\-|c]", c("a-a","b")) [1] 1 > gsub("[\-|c]", "&", c("a-a","b")) [1] "a&a" "b" but these are strange: > grep("[d|\-|c]", c("a-a","b")) integer(0)

If I run cvec<-c("test.f", "test.sf", "try.g","try.res", "try.f") print(cvec) indx<-grep('\.f',cvec,perl=TRUE) fset<-cvec[indx] print(fset) I get > cvec<-c("test.f", "test.sf", "try.g","try.res", "try.f") > print(cvec) [1] "test.f" "test.sf"

Hi R-users and R-experts, I am having a hard time in figuring out how to tackle regex questions where the "backslash" character is an integral part of the string. Let me explain how I?came across?this problem : I wanted to clearly see all the components in the windows environmental path variable. This is a long string.?For easy readability, I wanted to split up this string so that each

I'm having trouble achieving the results I want using a regular expression. I want to eliminate all characters that fall within square brackets as well as the brackets themselves, returning an "". I'm not sure if it's R's use of double slash escapes or something else that is tripping me up. If I only use one slash I get 1: '\[' is an unrecognized escape in a

How do I get output with "\color{blue}", i.e. with only one backslash??? > "\color{blue}" [1] "color{blue}" Warning messages: 1: '\c' is an unrecognized escape in a character string 2: unrecognized escape removed from "\color{blue}" > "\\color{blue}" [1] "\\color{blue}" > Any help greatly appreciated. Best regards,

Hello again, I am having a problem on Regular expression. Let say I have following code: > gsub("[',]", "", "'asd'f") [1] "asdf" This is perfect. However I am having problem if I include "" (i.e. the double quote) in the first argument as the pattern search: > gsub("[',"]", "",

I'm trying to write a gsub() call that takes a string and escapes all the unescaped quote marks in it. So the string \" would be left unchanged, but \\" would be changed to \\\" because the double backslash doesn't act as an escape for the quote, the first just escapes the second. I have the usual problems of writing regular expressions involving backslashes which