similar to: sscanf

Dear Tomas,Thank you.Regarding the "unnumbered" arguments, i.e. sprintf('%f %f', 1, 2, 3). This was the case I wanted to report, here a warning can be very useful.Regarding the "numbered" arguments, that is, sprintf('%$1f %$3f', 1, 2, 3). Here, omission of an argument might be intended, for example, in an application with support for multiple languages.

Dear Bill, All makes perfect sense (including the late evaluation). I actually discovered the problem by looking at old code which used your proposed solution. Still I find it strange (and, hnestly, I don?t like R?s behavior in this respect), and I am wondering why u is not being copied to L just before u is assigned a new value. Of course, this would require the R interpreter to track all these

Dear R developers, I am wondering if this should raise an error or a warning. > sprintf('%.f, %.f', 1, 2, 3) [1] "1, 2" I am aware that R has ?numbered? sprintf arguments (sprintf('%1$.f', ?), and in that case, omissing of specific arguments may be intended. But in the usual syntax, omission of an argument is probably a mistake. Thank you for your consideration.

Another way to avoid the problem is to not redefine variables that are arguments. E.g., > Su3 <- function(u=100, l=u, mu=0.53, sigma2=4.3^2, verbose) { if (verbose) { print(c(u, l, mu)) } uNormalized <- u/sqrt(sigma2) lNormalized <- l/sqrt(sigma2) muNormalized <- mu/sqrt(sigma2) c(uNormalized, lNormalized, muNormalized) } > Su3(verbose=TRUE)

Dear R developers, The following command produces an interaction plot with lwd=2. interaction.plot(c(1, 2, 1, 2), c(1, 1, 2, 2), 1:4, lwd=2) In the legend, however, lwd seems to be 1, which does not seem to be intended behavior. Probably the lwd is not correctly forwarded to legend: from the interaction.plot source: legend(xleg, yleg, legend = ylabs, col = col, pch = if (type %in%

Dear R developers, I would like to have R choose the limits of the y-axis semi-automatically, e.g., zero should be included, but the maximum should be chosen depending on the data. Examples: plot(1:10, 1:10) # selects min and max automatically plot(1:10, 1:10, ylim=c(1, 10)) # manual definition plot(1:10, 1:10, ylim=c(0, Inf)) # this would be a nice feature, i.e. lower y limit = 0 defined

Dear R developers, sessionInfo() below Please have a look at the following two versions of the same function: 1. Intended behavior: > Su1 = function(u=100, l=u, mu=0.53, sigma2=4.3^2) + { + print(c(u, l, mu)) # here, l is set to u?s value + u = u/sqrt(sigma2) + l = l/sqrt(sigma2) + mu = mu/sqrt(sigma2) + print(c(u, l, mu)) + } > > Su1() [1] 100.00 100.00 0.53 [1]

Hello, One way of preventing that is to use ?force. Just put force(l) right after the commented out print and before you change 'u'. Hope this helps, Rui Barradas Citando Matthias Gondan <matthias-gondan at gmx.de>: > Dear R developers, > > sessionInfo() below > > Please have a look at the following two versions of the same function: > > 1. Intended

Dear list, Is anyone aware of a library for sample size calculation in R, similar to NQuery? I have to give a course in this area, and I would like to enable the students playing around with this. Best wishes, Matthias

Dear List, I am aware this is slightly off-topic, but I am sure there are people who already had the problem and who perhaps solved it. I am running long-lasting model fits using constrOptim command. At work there is a linux computer (Quad Core, debian) on which I already have compiled R and Atlas, in the hope that things will go faster on that machine. Atlas offers the possibility to be

Dear R-Users, Is anyone aware of a significance test which allows demonstrating that one distribution dominates another? Let F(t) and G(t) be two distribution functions, the alternative hypothesis would be something like: F(t) >= G(t), for all t null hypothesis: F(t) < G(t), for some t. Best wishes, Matthias PS. This one would be ok, as well: F(t) > G(t), for all t null

Mathias, If it's any comfort, I appreciated the example; 'expected' behaviour maybe, but a very nice example for staff/student training! S Ellison > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Matthias > Gondan > Sent: 02 September 2017 18:22 > To: r-help at r-project.org > Subject: [R] Strange lazy evaluation of

Dear R experts, For a fixed seed, the first random number produced by rnorm and runif has the same rank within the distribution, which I find useful. The following ranks differ, however. > set.seed(123) > runif(4) [1] *0.2875775* 0.7883051 *0.4089769* 0.8830174 > set.seed(123) > pnorm(rnorm(4)) [1] 0.2875775 0.4089769 0.9404673 0.5281055 I noticed that rnorm seems to

sscanf can take an integer which specifies the maximum field width. In this test, the field width is 1 and the input is a negative number so the test fails. This patch increases the maximum field width to 2. Signed-off-by: Mike Pagano <mpagano at gentoo.org> --- usr/klibc/tests/sscanf.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/usr/klibc/tests/sscanf.c

Hi, Use offset variables if count occurrences of an event and you want to model the observation time. glm(count ~ predictors + offset(log(observation_time)), family=poisson) If you want to compare durations, look at library(survival), ?coxph If tnoise_sqrt is the square root of tourist noise, your example seems incorrect, because it is a predictor, not the dependent variable tnoise_sqrt ~

Dear list, I hope the topic is of sufficient interest, because it is not R-related. I have N=100 yes/no-responses from a psychophysics paradigm (say Y Yes and 100-Y No-Responses). I want to see whether these yes-no-responses are in line with a model predicting a certain amount p of yes-responses. Standard procedure would be a one-sample binomial test for the observed proportion, chi?(1 df) =

--- p2v/ssh.c | 11 ++++++++++- 1 file changed, 10 insertions(+), 1 deletion(-) diff --git a/p2v/ssh.c b/p2v/ssh.c index 1e9b05c..ff906df 100644 --- a/p2v/ssh.c +++ b/p2v/ssh.c @@ -505,7 +505,16 @@ open_data_connection (struct config *config, int *local_port, int *remote_port) }, ovector, ovecsize)) { case 100: /* Ephemeral port. */ port_str =

Dear R developers, I want to draw an arrow in a figure with lty=2. The lty argument also affects the edge of the arrow, which is unfortunate. Feature or bug? Is there some way to draw an arrow with intact edge, still with lty=2? Example code: plot(1:10) arrows(4, 5, 6, 7, lty=2) Best wishes, Matthias --

Use %d to parse them as int (since the variables for them as int) instead of %u, even if they both need to be at least > 0. --smp was already checked to be >= 1 while --memsize not, so check that the specified memory size is not < 128 (which is semi-arbitrary, but enough as a minimum threshold). --- rescue/rescue.c | 12 ++++++++++-- 1 file changed, 10 insertions(+), 2 deletions(-)

Dear R developers, A great R feature is that elements of vectors, lists and dataframes can have names: vx = c(a=1, b=2) lx = list(a=1, b=2) Accessing element "a" of vx: vx['a'] Accessing element "a" of lx: lx[['a']] or lx$a Might be a matter of taste, but I like the $ very much. Unfortunately, vx$a is not functional. Would it break existing compatibility