similar to: extending strsplit to handle missing text that doesn't have the target on which to split

strsplit() is a convenient way to get a list of items from a string when you have a regular expression for what is not an item. E.g., > strsplit("1.2, 34, 1.7e-2", split="[ ,] *") [[1]]: [1] "1.2" "34" "1.7e-2" However, sometimes is it more convenient to give a pattern for the items you do want. E.g., suppose you want to pull

Any ideas what is wrong? > strsplit("a.b", ".") # generates empty strings with split="." [[1]] [1] "" "" "" > strsplit("a b", " ") # seems to work fine with split=" ", and other characters... [[1]] [1] "a" "b" > > R.Version() $platform [1]

*I'm still a R noob, just had a couple of lectures about it in our research master. There is a Deal or no deal experiment where I have to write some code for. Someone wrote a website to gather the data and write it in a .xlsx file. These are seperate files for seperate participants so first I have to import the seperate datafiles. I do that like this: # Merge the xlsx files into one dataframe

I successfully combined my data frames, and am now on my next hurdle. I had combined the data and quarter, and used tapply to count the entries for each unique date/quarter pair. ar= tapply(ewrgnd$gw, list(ewrgnd$dq), sum) #for each date/quarter combination sums the gw (which are all 1) dq=row.names(ar) spl=strsplit(dq) But I need to split them back into the separate date and quarter. So I used

Hi there, I have a problem about lapply, strsplit, and accessing list elements, which I don't understand or cannot solve: I have e.g. a character vector with three elements: x = c("349/077,349/074,349/100,349/117", "340/384.2,340/513,367/139,455/128,D13/168", "600/437,128/903,128/904") The task I want to perform, is to generate a list,

Dear Mao Jianfeng, "r-help-owner" is not the place for help, but: r-help at r-project.org (CC-ed here) In any case, strsplit() does the job, i.e.: > unlist(strsplit("BCPy01-01", "-")) [1] "BCPy01" "01" You can work with the whole variable, like: splitpop <- strsplit(df1$popcode, "-") then access the first part with >

Hi, A pared down version of the dataset I'm working with: edm<-read.table(textConnection("WELLID X_GRID Y_GRID LAYER ROW COLUMN SPECIES CALCULATED OBSERVED w301_3 4428. 1389 2 6 18 1 3558 6490. w304_12 4836. 6627 2 27 20 1 3509 3228. 02_10_12080 3.6125E+04 13875 1 56 145 1

Dear R People: I have the following set of data > Block[1:5] [1] "5600-5699" "6100-6199" "9700-9799" "9400-9499" "8300-8399" and I want to split at the - > strsplit(Block[1:5],"-") [[1]] [1] "5600" "5699" [[2]] [1] "6100" "6199" [[3]] [1] "9700" "9799" [[4]] [1]

Hi, I find this behavior unexpected: --8<---------------cut here---------------start------------->8--- > strsplit(c("a,b;c","d;e,f"),c(",",";")) [[1]] [1] "a" "b;c" [[2]] [1] "d" "e,f" --8<---------------cut here---------------end--------------->8--- I thought that it should be identical to this:

Dear all, I'm having a problem understanding why a split does not occur with in the 2nd use of the function strsplit below: # text strings > txt <- c("sales to 23 August 2008 published 29 August", + "sales to 6 September 2008 published?11 September") # first use > strsplit(txt, 'published', fixed=TRUE) [[1]] [1] "sales to 23 August 2008 "

Hello, I am attempting to manipulate strings in which there are differing amounts of whitespace before and after each element taht I want to keep (any word, letter, or number). However, after strsplit and unlist, I know how to select specific elements with "[ ]", but I want to select instead all elements that are not missing. That is, do not select any elements that are simply

Hi folks, Suppose I create the character vector charvec by > charvec<-c("a1.b1","a2.b2") > charvec [1] "a1.b1" "a2.b2" and then I use strsplit on charvec as follows: > splitlist<-strsplit(charvec,split=".",fixed=TRUE) > splitlist [[1]] [1] "a1" "b1" [[2]] [1] "a2" "b2" I was wondering

Hi, if I have this string: "a.b.c.d" and I use this function: unlist(strsplit("a.b.c.d", "\\.")), I get this as my output: "a", "b", "c", and "d". Is there a way to just split on the first period so I obtain only two pieces like: "a" and "b.c.d"? Anyways, thanks in advance! -- View this message in context:

Hello there, I was wondering if you could help me with a quick R issue. I have a data set where one of the columns has both date and time in it, e.g. "12/31/11 23:45" in one cell. I want to use R to split this column into two new columns: date and time. One of the problems with splitting here is that when the dates go into single digits there are no 0's in front of months

I am trying split a string and use one part of it to label graphs. I am using strsplit for that. While I am able to split it, how do I access the separated parts. > filName<-"chrI_2223" >part<- strsplit(filName,"\\_") > part [[1]] [1] "chrI" "2223" > part[1] [[1]] [1] "chrI" "2223" I looked up the help archive but did

\b is word boundary. But, unexpectedly, strsplit("dia ma", "\\b") splits character by character. > strsplit("dia ma", "\\b") [[1]] [1] "d" "i" "a" " " "m" "a" > strsplit("dia ma", "\\b", perl=TRUE) [[1]] [1] "d" "i" "a" " "

Dear Researchers, I have several files as this example: Myfile_MyArea1_sample1.txt i wish to split in "Myfile", "MyArea1", "sample1", and "txt", becasue i need to use "sample1" label. I try to use "strsplit" but I am able just to split as "Myfile_MyArea1_sample1" and "txt" OR "Myfile", "MyArea1",

Hello List, ? I have a dataset consisting of strings that I want to split while saving the delimiter. ? Some example data: ?leucocyten + gramnegatieve staven +++ grampositieve staven ++? ?leucocyten ? grampositieve coccen +? ? I want to split the strings such that I get the following result: c(?leucocyten +?, ??gramnegatieve staven +++?, ??grampositieve staven ++?) c(?leucocyten ??, ?grampositieve

DeaR list, I'm a bit lost in the behavior of substitute and co. I often use fairly long axis labels in my graphs (long to write, that is). Typically, they would contain some greek letters and units with exponents, as in: > xlab=expression(paste("text ", alpha, " / ", V,".", m^{-3}, ".", > kg^{-2}, ".", l^{4})) To make this a

I am using the following code but I do not know the debug and run for correct errors library (tcltk) file <-tclvalue (tkgetOpenFile ()) if (nchar (file)) { tkmessageBox ("Select the file") } else { tkmessageBox (message = paste ("Was select file", file)) Dataset <- read.table (file, header = FALSE, sep = "", na.strings =