similar to: novice question regarding R archives

Displaying 20 results from an estimated 900 matches similar to: "novice question regarding R archives"

2012 Nov 19
2
Performing gage R&R study in R w/more than 2 factors
Hi everyone, I'm fairly new to R, and I don't have a background in statistics, so please bear with me. ;-) I'm dealing with 2^k factorial designs, and I was just wondering if there's any way to analyze more than two factors of a gage R&R study in R. For example, Minitab has an "expanded gage R&R" function that lets you include up to eight additional factors
2009 Mar 24
3
CentOS 5.3 Release Notes Chinese translation
Dear all, I would like to help translate the CentOS 5.3 Release Notes into Chinese. Can you create the Manuals/ReleaseNotes/CentOS5.3/Chinese page? My user name is TimothyLee on the wiki. Regards, Timothy Lee
1997 Sep 02
1
R-alpha: Re: What are objects?
[I do think this discussion belongs to R-devel rather than anywhere else .. MM] >>>>> "Kurt" == Kurt Hornik <Kurt.Hornik@ci.tuwien.ac.at> writes: >>>>> Peter Dalgaard BSA writes: >> Kurt Hornik <Kurt.Hornik@ci.tuwien.ac.at> writes: KH>>> While trying to write documentation for data.class(), I came
2009 May 18
4
MAC OSX vs Win XP: Different stats test results!
Hi all, I wondered whether anyone has some advice on a stats-related 'sanity check', as I ran a nonparametric multivariate test (mulrank function as decribed by R. Wilcox, 2005) on both systems, but got different results (please see below for the system-specific outputs)! The functions I used are attached as well. Any advice would be much appreciated! Thanks in advance for getting back to
2009 Nov 09
1
Quickly generate all possible combinations of 2 groups
Hi all, I suspect the answer to this query will be the tongue-in-cheek "use a quantum computer", but I thought my understanding might be sufficiently limited that I'm missing a simpler option. I'm looking for a way to cycle through all possible combinations of 2 groups of data. For 10 data points, that's 2^10 combinations, for 20 data points it's 2^20, etc. combn() from
2010 Aug 31
1
ez version 2.0
The ez package was developed to aid those that are new to statistical programming. Over the course of several years of helping colleagues and students learn R, I observed that folks are often initially turned off R because they have difficulty obtaining SPSS-like results quickly (SPSS is the dominant environment in my field, psychology). ez attempts to fill this gap, providing quick and easy
2010 Aug 31
1
ez version 2.0
The ez package was developed to aid those that are new to statistical programming. Over the course of several years of helping colleagues and students learn R, I observed that folks are often initially turned off R because they have difficulty obtaining SPSS-like results quickly (SPSS is the dominant environment in my field, psychology). ez attempts to fill this gap, providing quick and easy
2009 Apr 18
2
Welcome to the "R-help" mailing list
Hi all, I'm a newbie R developer, am trying to dotplot a few graphs using a for loop. The following code works fine but once I wanna plot inside a loop, nothing happens. > for(i in 1:1){dotplot(y~x)} > y <- c(1,2,3) > x <- c('a','b','c') > dotplot(y~x) > for (i in 1:3) {dotplot(y~x)} (y and x depends on I in actual case) Nothing happens. I
2009 Jun 05
3
Fitting a Weibull Distribution
How do you fit a Weibull distribution in R?
2009 Apr 23
1
boxplot of two variables
Hello ! I have a dataframe with 6 variables (A1,A2,B1,B2,C1,C2) and 1 factor (F). I would like to produce a graph consisting of 3 boxplots sets, one for every two variables (i.e A1 &A2) by the factor (F). I was looking around and I cannot figure it out, any suggestions? Best Regards, Gabriel [[alternative HTML version deleted]]
2009 Apr 27
1
plot estimates and their 95% confidence intervals
Hi, there: I have a dataset with 50 states and for each state, I have its associated mean estimate (for some parameters) and the lower and upper bound of the 95% CI. The data look like below: state ami_mean ami_low ami_up 1 MS -0.58630 -0.90720 -0.29580 2 KY -0.48100 -0.75990 -0.19470 3 FL -0.47900 -0.62930 -0.32130 I would like to have a plot the 95% CI (characterized by
2009 May 12
2
Kumaraswamy distribution
Dear R users, Does anyone know how to write function for Kumaraswamy distribution in R? Since I cannot write dkumar, pkumar, etc. in R. Please help. Thanks a lot, Debbie _________________________________________________________________ [[elided Hotmail spam]] [[alternative HTML version deleted]]
2009 May 12
1
Two-way Anova
Hello, I'm trying to do a comparsion on a large scale say 10L bottle of liquid and a small scale bottle of liquid 0.5L, I have 5 different samples from each and they are measured over the space of 8 days as % viability and the % viability decreases over time. However not all 10 samples got measured every day. How would I do a two-way anova on this in R? Thanks for any help. Regards, Al
2009 Jun 02
1
help on understanding a code
Dear R user, I am trying to understand this following code. Basically it's using a permutation method to calculate p value. But I would like to know exactly how the permutation works. #calculates null statistics tt0 <- 0 set.seed(123) B <- 100 for(i in 1:B) { v <- sample(y) tt0 <- c(tt0,ttest(dat,v)$tt) } tt0 <- tt0[-1] #form p-values att <- abs(tt) att0 <- abs(tt0) v
2009 Apr 14
4
cbind
I have a list of numbers with NAs as below: > A[,1] [1] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [19] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [37] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [55] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA [73] NA NA NA 62 78 98
2009 May 24
2
help with replacing factors
Hi, In the example dataset below - how can I cahnge "gray20", to "blue" # data black <- rep(c("black","red"),10) gray <- rep(c("gray10","gray20"),10) black_gray <- data.frame(black,gray) # none of this desperate things works # replace(black_gray$gray, gray=="gray20","red") #
2009 Jun 10
2
Creating a specific skewed distribution
All, Can someone help me create a skewed distribution, mean = 30, with probability of selecting a random number from the distribution greater than or equal 60 equal to 10%? I need the probability density function to equal zero at zero, and have a maximum height at or near 30. Is this possible? And if it is possible, how can I adjust the distribution so that the probability of selecting a
2009 May 25
4
How to create all pairs
Hi, I have: i = c(1,2,3) j = c(4,5,6) How do I create a matrix of all pairs? i.e. 1,4 1,5 1,6 2,4 : Thanks! -- View this message in context: http://www.nabble.com/How-to-create-all-pairs-tp23714659p23714659.html Sent from the R help mailing list archive at Nabble.com.
2009 Nov 09
1
Getting Sphericity Tests for Within Subject Repeated Measure Anova (using "car" package)
Hello everyone, I am trying to do within subjects repeated measures anova followed by the test of sphericity (sample dataset below). I am able to get either mixed model or linear model anova and TukeyHSD, but have no luck with Repeated-Measures Assuming Sphericity or Separate Sphericity Tests. I am trying to follow example from "car" package, but it seems that I am not getting something
2009 May 13
11
Simulation
Dear R users, Can anyone please tell me how to generate a large number of samples in R, given certain distribution and size. For example, if I want to generate 1000 samples of size n=100, with a N(0,1) distribution, how should I proceed? (Since I dont want to do "rnorm(100,0,1)" in R for 1000 times) Thanks for help Debbie