Displaying 20 results from an estimated 900 matches similar to: "novice question regarding R archives"
2012 Nov 19
2
Performing gage R&R study in R w/more than 2 factors
Hi everyone,
I'm fairly new to R, and I don't have a background in statistics, so
please bear with me. ;-)
I'm dealing with 2^k factorial designs, and I was just wondering if
there's any way to analyze more than two factors of a gage R&R study in
R. For example, Minitab has an "expanded gage R&R" function that lets
you include up to eight additional factors
2009 Mar 24
3
CentOS 5.3 Release Notes Chinese translation
Dear all,
I would like to help translate the CentOS 5.3 Release Notes into
Chinese. Can you create the Manuals/ReleaseNotes/CentOS5.3/Chinese page?
My user name is TimothyLee on the wiki.
Regards,
Timothy Lee
1997 Sep 02
1
R-alpha: Re: What are objects?
[I do think
this discussion belongs to R-devel rather than anywhere else .. MM]
>>>>> "Kurt" == Kurt Hornik <Kurt.Hornik@ci.tuwien.ac.at> writes:
>>>>> Peter Dalgaard BSA writes:
>> Kurt Hornik <Kurt.Hornik@ci.tuwien.ac.at> writes:
KH>>> While trying to write documentation for data.class(), I came
2009 May 18
4
MAC OSX vs Win XP: Different stats test results!
Hi all,
I wondered whether anyone has some advice on a stats-related 'sanity check',
as I ran a nonparametric multivariate test (mulrank function as decribed by
R. Wilcox, 2005) on both systems, but got different results (please see
below for the system-specific outputs)! The functions I used are attached as
well. Any advice would be much appreciated! Thanks in advance for getting
back to
2009 Nov 09
1
Quickly generate all possible combinations of 2 groups
Hi all,
I suspect the answer to this query will be the tongue-in-cheek "use a
quantum computer", but I thought my understanding might be
sufficiently limited that I'm missing a simpler option.
I'm looking for a way to cycle through all possible combinations of 2
groups of data. For 10 data points, that's 2^10 combinations, for 20
data points it's 2^20, etc. combn() from
2010 Aug 31
1
ez version 2.0
The ez package was developed to aid those that are new to statistical
programming. Over the course of several years of helping colleagues
and students learn R, I observed that folks are often initially turned
off R because they have difficulty obtaining SPSS-like results quickly
(SPSS is the dominant environment in my field, psychology). ez
attempts to fill this gap, providing quick and easy
2010 Aug 31
1
ez version 2.0
The ez package was developed to aid those that are new to statistical
programming. Over the course of several years of helping colleagues
and students learn R, I observed that folks are often initially turned
off R because they have difficulty obtaining SPSS-like results quickly
(SPSS is the dominant environment in my field, psychology). ez
attempts to fill this gap, providing quick and easy
2009 Apr 18
2
Welcome to the "R-help" mailing list
Hi all,
I'm a newbie R developer, am trying to dotplot a few graphs using a for
loop.
The following code works fine but once I wanna plot inside a loop, nothing
happens.
> for(i in 1:1){dotplot(y~x)}
> y <- c(1,2,3)
> x <- c('a','b','c')
> dotplot(y~x)
> for (i in 1:3) {dotplot(y~x)} (y and x depends on I in actual case)
Nothing happens.
I
2009 Jun 05
3
Fitting a Weibull Distribution
How do you fit a Weibull distribution in R?
2009 Apr 23
1
boxplot of two variables
Hello !
I have a dataframe with 6 variables (A1,A2,B1,B2,C1,C2) and 1 factor (F).
I would like to produce a graph consisting of 3 boxplots sets, one for every
two variables (i.e A1 &A2) by the factor (F).
I was looking around and I cannot figure it out, any suggestions?
Best Regards,
Gabriel
[[alternative HTML version deleted]]
2009 Apr 27
1
plot estimates and their 95% confidence intervals
Hi, there:
I have a dataset with 50 states and for each state, I have its associated mean estimate (for some parameters) and the lower and upper bound of the 95% CI. The data look like below:
state ami_mean ami_low ami_up
1 MS -0.58630 -0.90720 -0.29580
2 KY -0.48100 -0.75990 -0.19470
3 FL -0.47900 -0.62930 -0.32130
I would like to have a plot the 95% CI (characterized by
2009 May 12
2
Kumaraswamy distribution
Dear R users,
Does anyone know how to write function for Kumaraswamy distribution in R? Since I cannot write dkumar, pkumar, etc. in R.
Please help.
Thanks a lot,
Debbie
_________________________________________________________________
[[elided Hotmail spam]]
[[alternative HTML version deleted]]
2009 May 12
1
Two-way Anova
Hello,
I'm trying to do a comparsion on a large scale say 10L bottle of liquid and a small scale bottle of liquid 0.5L, I have 5 different samples from each and they are measured over the space of 8 days as % viability and the % viability decreases over time. However not all 10 samples got measured every day. How would I do a two-way anova on this in R?
Thanks for any help.
Regards,
Al
2009 Jun 02
1
help on understanding a code
Dear R user,
I am trying to understand this following code. Basically it's using a
permutation method to calculate p value. But I would like to know exactly
how the permutation works.
#calculates null statistics
tt0 <- 0
set.seed(123)
B <- 100
for(i in 1:B) {
v <- sample(y)
tt0 <- c(tt0,ttest(dat,v)$tt)
}
tt0 <- tt0[-1]
#form p-values
att <- abs(tt)
att0 <- abs(tt0)
v
2009 Apr 14
4
cbind
I have a list of numbers with NAs as below:
> A[,1]
[1] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA
NA
[19] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA
NA
[37] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA
NA
[55] NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA NA
NA
[73] NA NA NA 62 78 98
2009 May 24
2
help with replacing factors
Hi,
In the example dataset below - how can I cahnge "gray20", to "blue"
# data
black <- rep(c("black","red"),10)
gray <- rep(c("gray10","gray20"),10)
black_gray <- data.frame(black,gray)
# none of this desperate things works
# replace(black_gray$gray, gray=="gray20","red")
#
2009 Jun 10
2
Creating a specific skewed distribution
All,
Can someone help me create a skewed distribution, mean = 30, with
probability of selecting a random number from the distribution greater
than or equal 60 equal to 10%?
I need the probability density function to equal zero at zero, and
have a maximum height at or near 30.
Is this possible?
And if it is possible, how can I adjust the distribution so that the
probability of selecting a
2009 May 25
4
How to create all pairs
Hi,
I have:
i = c(1,2,3)
j = c(4,5,6)
How do I create a matrix of all pairs?
i.e.
1,4
1,5
1,6
2,4
:
Thanks!
--
View this message in context: http://www.nabble.com/How-to-create-all-pairs-tp23714659p23714659.html
Sent from the R help mailing list archive at Nabble.com.
2009 Nov 09
1
Getting Sphericity Tests for Within Subject Repeated Measure Anova (using "car" package)
Hello everyone,
I am trying to do within subjects repeated measures anova followed by the
test of sphericity (sample dataset below).
I am able to get either mixed model or linear model anova and TukeyHSD, but
have no luck with Repeated-Measures Assuming Sphericity or Separate
Sphericity Tests.
I am trying to follow example from "car" package, but it seems that I am not
getting something
2009 May 13
11
Simulation
Dear R users,
Can anyone please tell me how to generate a large number of samples in R, given certain distribution and size.
For example, if I want to generate 1000 samples of size n=100, with a N(0,1) distribution, how should I proceed?
(Since I dont want to do "rnorm(100,0,1)" in R for 1000 times)
Thanks for help
Debbie