Displaying 20 results from an estimated 1000 matches similar to: "problem in as.date"
2009 May 04
4
Splitting a vector into equal groups
Hi All,
I have vector of length 52, say, x=sample(30,52,replace=T). I want to
sort x and split into five *nearly equal groups*. Note that the
observations are repeated in x so in case of a tie I want both the
observations to fall in same group.
This seems a very common task to do, but still I couldn't find an R
function to do this. Any help would be highly appreciated.
Regards
Utkarsh
2009 Jun 30
4
R version-2.9.1 for Linux
Hi All,
I am currently using R version 2.8.1 on linux cent os 4.4 (i386) and
want to upgrade to version 2.9.1. It seems to me that version-2.9.1 is
it not for my OS.
Am I right?
Regards
Utkarsh
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2010 Dec 17
1
[Fwd: adding more columns in big.matrix object of bigmemory package]
Hi,
With reference to the mail below, I have large datasets, coming from various
different sources, which I can read into filebacked big.matrix using library
bigmemory. I want to merge them all into one 'big.matrix' object. (Later, I
want to run regression using library 'biglm').
I am unsuccessfully trying to do this from quite some time now. Can you
please
2009 May 18
2
intermediate iterations of stepwise regression
Hi all,
I am performing a stepwise regression by running the "step" function on
an "lm" object. Now I want to save the intermediate iterations. I know
the argument trace=T will print it on the console, but I rather want to
assign it to some R object or may be output it in a CSV or text file.
Any help will be appreciated.
Regards
Utkarsh
2009 Nov 23
3
FUN argument to return a vector in aggregate function
Hi All,
I am currently doing the following to compute summary statistics of
aggregated data:
a = aggregate(warpbreaks$breaks, warpbreaks[,-1], mean)
b = aggregate(warpbreaks$breaks, warpbreaks[,-1], sum)
c = aggregate(warpbreaks$breaks, warpbreaks[,-1], length)
ans = cbind(a, b[,3], c[,3])
This seems unnecessarily complex to me so I tried
> aggregate(warpbreaks$breaks, warpbreaks[,-1],
2009 Jun 02
2
bigmemory - extracting submatrix from big.matrix object
I am using the library(bigmemory) to handle large datasets, say 1 GB,
and facing following problems. Any hints from anybody can be helpful.
_Problem-1:
_
I am using "read.big.matrix" function to create a filebacked big matrix
of my data and get the following warning:
> x =
read.big.matrix("/home/utkarsh.s/data.csv",header=T,type="double",shared=T,backingfile
2011 May 14
2
calling "exists" function inside another function is not working
Hi all,
I want to define a function such that one of its argument if passed do one
thing and if not passed do the second thing. So basically, I have to check
whether the argument is passed or not inside the function. I am trying to
use 'exists' function to do this.
> f = function(a,b){exists("b")}
> f(a=3, b=4)
[1] TRUE
This is working as expected.
2011 May 14
2
calling "exists" function inside another function is not working
Hi all,
I want to define a function such that one of its argument if passed do one
thing and if not passed do the second thing. So basically, I have to check
whether the argument is passed or not inside the function. I am trying to
use 'exists' function to do this.
> f = function(a,b){exists("b")}
> f(a=3, b=4)
[1] TRUE
This is working as expected.
2009 May 27
3
Defining functions - an interesting problem
I define the following function:
(Please don't wonder about the use of this function, this is just a
simplified version of my actual function. And please don't spend your
time in finding an alternate way of doing the same as the following does
not exactly represent my function. I am only interested in a good
explanation)
> f1 =
2009 Sep 14
1
setting plotting device
Hi All,
I have recently *re*-installed R-2.9.1 in my Linux machine. Since then,
I am unable to plot using the usual interactive device.
> plot(1:10)
This plots in a pdf file "Rplots.pdf" in my working directory.
> sessionInfo()
R version 2.9.1 (2009-06-26)
i686-pc-linux-gnu
locale:
2009 Jun 16
1
Testing if all elements are equal in a vector/matrix
Hi All,
There are several replies to the question below, but I think there must
exist a better way of doing so.
I just want to check whether all the elements of a vector are same. My
vector has one million elements and it is highly likely that there are
distinct elements in the first few itself. For example:
> x = c(1,2,rep(1,100000))
I want the answer as FALSE, which is clear from the
2009 Jul 03
2
bigglm() results different from glm()
Hi Sir,
Thanks for making package available to us. I am facing few problems if
you can give some hints:
Problem-1:
The model summary and residual deviance matched (in the mail below) but
I didn't understand why AIC is still different.
> AIC(m1)
[1] 532965
> AIC(m1big_longer)
[1] 101442.9
Problem-2:
chunksize argument is there in bigglm but not in biglm, consequently,
2001 Jan 03
1
package/ date/ download problem
Colleagues
I want to download the package "date" from CRAN <http://cran.r-
project.org/> to get the R-scripts (for version 1.2.0)
*** date/INDEX ***
as.date Coerce Data to Dates
date.ddmmmyy Format a Julian date
date.mdy Convert from Julian Dates to Month, Day, and Year
date.mmddyy Format a Julian date
date.mmddyyyy Format a Julian date
date.object Date Objects
mdy.date
2000 Jan 03
1
Rounding in date.mdy from library(date)
The date library contains a function date.mdy that converts a number
D to the date (month,date,year as a list) at D days after 1 Jan 1960.
This a convention that fits in with SASs.
The logic would be that the result was the date at D days after
1 Jan 1960 00:00:00 (which is a POINT in time as opposed to a date which
is an interval), so that any D with 2<=D<3 was rounded to 3 Jan 1960
and
2009 Oct 26
3
as.POSIXct month problem
Hi everybody
When I try example of strptime
x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960")
z <- strptime(x, "%d%b%Y")
The result is;
> z
[1] NA NA NA NA
I have got the same result with complete form of month but not with numeric
form.
Any idea?
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2012 Dec 17
1
subset handling
Dear Rui and UseRs,[a text file has also been attached, in case the format of my email is difficult to get]I am extremely sorry that I am bothering you once again, but I?ll have to get to the bottom of it. The following command
sp <- lapply(split(agg, agg$st), function(x) x[order(x$year, x$month), ])
gave me an output with monthly mean of population(as under). i am not able to apply
2001 Jan 11
2
problem with strptime example (PR#811)
On Thu, 11 Jan 2001 stephen@anc.ed.ac.uk wrote:
> Hi,
>
> The help file for strptime has the following code which doesn't work
> for me:
>
> ## read in date info in format `ddmmmyyyy'
> x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960")
> z <- strptime(x, "%d%b%Y")
> > z
> [1]
2006 May 20
2
Function as.Date leading to error implying that strptime requires 3 arguments
I'm using R V 2.2.1. When I try an example from the as.Date help page,
I get an error.
> x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960")
> z <- as.Date(x, "%d%b%Y")
Error in strptime(x, format) : 2 arguments passed to 'strptime' which
requires 3
>
Any suggestions would be appreciated.
Thanks,
Rob
2001 Oct 01
2
problem with strptime example (PR#811)
Hello,
strptime is still not working correctly in my computer
(Windows 98 and R Version 1.3.1)
From
x <- c("1jan1960", "2jan1960", "31mar1960", "30jul1960")
strptime(x, "%d%b%Y")
I obtain
[1] "NA" "NA" "NA" "NA"
while
x <- c("01011960", "02011960", "3131960",
2009 Dec 24
3
help in merging
Hi All,
I want to "merge" two datasets by column "ID" and I don't want the result to
be sorted by "ID". I am doing the following:
> z = merge(x, y, by = "ID", sort=F)
The result is not sorted by "ID". But (as oppose to what I expected) it is
not even in the original order of either "x" or "y".
Can