similar to: how to word-wrap text in labels in plots?

If I combine elements into a list b <- c(22.4, 12.2, 10.9, 8.5, 9.2) my.c <- sample.int(round(2*mean(b)), 5) my.list <- list(b, my.c) the names of the elements seems to get lost in the process: > str(my.list) List of 2 $ : num [1:5] 22.4 12.2 10.9 8.5 9.2 $ : int [1:5] 11 8 6 9 20 If I explicitly name the elements at list-creation, I get what I want: my.list <- list(b=b,

Hello r-help! I have data with two kind of ratings on status of 100 occupations. The first kind of rating is on the percieved "objective" status that these occupations have in society at large, and the second kind or rating is on the status that the respondents think that these occuption *should* have. The ratings were originally integer values in the rage 1-9, but in the current data,

Hi list I have a data frame I would like to loop over. To begin with I would like crosstabulations using the first variabel in the data frame, which is called "meriter". > table(meriter[[1]], meriter[[3]]) ja nej Annan 0

foo <- rnorm(30*34*12) dim(foo) <- c(30, 34, 12) I want to make a data.frame out of this three-dimensional array. Each dimension will be a variabel (column) in the data.frame. I know how this can be done in a very slow way using for loops, like this: x <- rep(seq(from = 1, to = 30), 34) y <- as.vector(sapply(1:34, function(x) {rep(x, 30)})) month <- as.vector(sapply(1:12,

I want 100 integers. Each integer, x, can be in the range 1 =< x => 10. Does the following code give 1 and 10 the same chances to be selected as 2:8? round(runif(100, min = 1, max = 10)) -- Hans Ekbrand -------------- next part -------------- A non-text attachment was scrubbed... Name: not available Type: application/pgp-signature Size: 197 bytes Desc: Digital signature URL:

Hi r-help! Consider the following data-frame: var1 var2 var3 1 3 1 4 2 2 2 3 3 2 2 3 4 4 4 NA 5 4 3 5 6 2 2 3 7 3 4 3 How can I get R to convert this into the following? Value 1 2 3 4 5 var1 0 3 2 2 0 var2 1 3 1 2 0 var3 0 0 4 1 1 TIA, -- Hans Ekbrand (http://sociologi.cjb.net) <hans at

I must be missing something obvious here: According to the help page for read.spss, the reencode option is only active when R is run under a UTF-8 locale. read.spss can only import the SPSS file when run under a iso88591(5) locale, under a UTF-8 locale I get: Error in read.spss("wo.sav") : error reading system-file header In addition: Warning message: In read.spss("wo.sav")

Hi, I have problem. In the function below (test and test2) i want the function test not to print the variable data but i want the function test2 to use the variable test$data. This is the creation of the variable data: > matrice=c(1:10) > matrice=matrix(matrice,nrow=5,ncol=2) This is the function test: > test=function(data){ + return(list(x=5,data=data)) + } This is the function

Dear R users, I have a problem since I try to plot my datas with different colors. plot(tvar, var, xlab="zeit [s]",ylab="Variation [%]", col = ifelse(var <= varstability, 'green','red')) this works well! But since I add a type="l" to my plot, it will color all the plot with green!!! Is there any solution? I avoid to use teachingDemos. Thanks. --

Hi all Say I have a function: myname=function(dat,x=5,y=6){ res<<-x+y-dat } for various input such as myname(dat1) myname(dat2) myname(dat3) myname(dat4) myname(dat5) how should I modify the 'res' line, to have new informative variable name correspondingly, such as dat1.res dat2.res dat3.res dat4.res dat5.res stored in the workspace. This is only an example of a complex

Dear All, I am trying to install rgl on my mac notebook from the source file. I tried using: /usr/bin/R64 CMD INSTALL rgl_0.92.798.tar.gz and get the following error message: checking for X... no configure: error: X11 not found but required, configure aborted. ERROR: configuration failed for package ?rgl? * removing ?/Library/Frameworks/R.framework/Versions/2.14/Resources/library/rgl? *

Hello, I have a nasty loop that I have to do 11877 times. The only thing that slows it down really is this merge: xx1 = merge(dt,ua_rd,by.x=1,by.y= 'rt_date',all.x=T) Any ideas on how to speed it up? The output can't change materially (it works), but I'd like it to go faster. I'm looking at getting around the loop (not shown), but I'm trying to speed up the merge first.

Hi everyone. I have a long label that I would like to split. I found that I could use "strwrap" for simple text. However, this is not working with this label: str = expression(paste("< 20 ?m phytoplankton ","(cells ? ",mL^-1,")")) plot(...., ylab = strwrap(str,20),...) I suspect this is because I'm using "expression" for form my label.

For a variety of displays (mosaicplots, barplots, ...) one often wants to either abbreviate or wrap long labels, particularly when these are made up of several words. In general, it would be nice to have a function, abbreviate.or.wrap <- function(x, maxlength=10, maxlines=2, split=" ") { } that would take a character vector or a list of vectors, x, and try to abbreviate or wrap

Hello! Does anyone know of a handy way to wrap the names.arg text in a barplot? I'm creating a bar plot with rather long labels; I can adjust the margins, but I'd also like to have the text wrap to about 4cm. Thanks! Kyle H. Ambert Doctoral Candidate, Bioinformatics Oregon Health & Science University ambertk@gmail.com [[alternative HTML version deleted]]

I would like to wrap a y-axis label onto two lines. My label is an expression containing both text and math symbols. I have looked at plotmath, strsplit(), strwrap(), deparse(), do.call(), substitute() and bquote(). Based on previous posts, I can get plain text to wrap. However, when I try these methods on my label, the exact string is returned, rather than evaluating the math symbols. My

Hi: Using this dataframe with quite long column headers, how can I wrap the text so that the columns are narrower. I was trying to use strwrap without success. Thanks reportDF <- structure(list(IDDate = c("3/12/2010", "3/13/2010", "3/14/2010", "3/15/2010"), FirstRunoftheYear = c("33 (119 ? 119)", "n (0 ? 0)", "893 (110 ?

Hi list! Short version: How do I convert a whole data.frame from latin1 encoding to utf8? I get SPSS files with latin1 encoding. My OS is GNU/Linux and the locale sv_SE.utf8, and I normally interface R with Emacs/ESS. I have used the following hack to convert a data.frame in latin1 to utf8: > Sys.setlocale(category = "LC_ALL", locale = "sv_SE.iso88591") > foo <-

Dear R gurus, I want to wrap labels that are too long for a plot. I have looked at strsplit(), substr(), nchar(), and strwrap(). I think it's some combination but I'm having difficulty trying to figure out the right combo. I think I need to create some new matrix containing the labels already split, though I'm not sure if maybe there is a quick and dirty way to address this

Hi. Am brand new to R and to mailing lists - have never posted anywhere before, so hope I do this right. Am using R 2.9.1 with lattice graphics (just installed, fully up to date). Am doing trellis xyplot with y (emp=employment), x (yearmo=a time measure) and conditioning variable (indf - factor describing industry) -- i.e., (emp ~ yearmo | indf), where all three variables are in a dataframe. The