Displaying 20 results from an estimated 1100 matches similar to: "I can't install dprep"
2007 Jun 20
1
Error in funcion distancia() in package dprep(v1.0) (PR#9745)
Full_Name: Kang Yousan
Version: 2.5.0
OS: Windows XP
Submission from: (NULL) (211.137.211.67)
There is a bug in function distancia() in package dprep. See the description
below.
> distancia
1 function (x, y)
2 {
3 if (class(y) == "matrix") {
4 distancia = drop(sqrt(colSums((x - t(y))^2)))
5 distancia = t(distancia)
6 }
7 else distancia =
2009 Sep 06
1
Two packages and one method
Hi!
I want to use one method "combinations" from "gtools" package but in my code
I must use also "dprep" method where is method "combinations" too. Mayby I
show you result my help function:
Help on topic 'combinations' was found in the following packages:
Package Library
dprep /usr/lib64/R/library
gtools
2007 Mar 28
0
Outlier detection with the dprep library
Hi.
The dprep library has at least three different methods for outlier
detection: baysout, mahaout, robout.
I wanted to test them on a very simple data set:
vrmat<-cbind((1:22),c(8,14,14,17,21,20,27,23,25,33,31,32,30,36,37,40,42,44,52,61,81,265))
As you can see by eyeballing this, the last point is a very good outlier
candidate, and maybe the second to last point, too. Anyway, I
2009 May 29
4
logical vector as a matrix
I have a vector like this:
h <- c(4, 6, NA, 12)
and I create the secound logical vector like this:
g <- c(TRUE, TRUE, FALSE, TRUE)
And my problem is that I would like to get a new "m" vector as a rasult "h"
and "g"( as dot-matrix printer) but with missed "NA" value, for example:
m = (4,6,12)
Do you have any idea?
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2009 Jun 08
4
seq(...) strange logical value
Do you heve any idea why I get after this instruction everywhere false?
> seq (0, 1, by=0.1) == 0.3
[1] FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE
But after different step it's ok:
> seq(0, 1, by=0.1) == 0.4
[1] FALSE FALSE FALSE FALSE TRUE FALSE FALSE FALSE FALSE FALSE FALSE
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2008 Dec 09
4
Pre-model Variable Reduction
Hello All,
I am trying to carry out variable reduction. I do not have information
about the dependent variable, and have only the X variables as it
were.
In selecting variables I wish to keep, I have considered the following criteria.
1) Percentage of missing value in each column/variable
2) Variance of each variable, with a cut-off value.
I recently came across Weka and found that there is an
2005 Feb 04
2
genetic algorithm
Hi,
I am doing some research on feature selection for classfication
problem using genetic algorithm in a wrapper approach. I am wondering
if there is some package which is already built for this purpose. I
was advised before about dprep package but I don't think it used GA
there (if I am wrong, please correct me!)
Thanks,
Ed
2009 Jun 01
2
add values inside vector
I think it's easy problem but I can't find solution.
I have a vector:
vec <- c (23.4, 3.0, 14.7, 7.7)
and I would like to add all values which are inside my vector to each
other.
as a result a want to get one value like sum all values from my vector-
sth=(23.4 + 3.0 + 14.7 + 7.7)
PS. I usually don't know how long is my vector in my function
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2009 May 14
2
I want to avioid unnecessary value
I have a database like this:
"kol1";"kol2";"kol3" ...
"2";"5";"9"
"9";"6";"6"
"4";"6";"5"...
I looking for a kod in R which let mi aviod in column unnecessary value, for
example number "9".
So, if I have:
Kol1
2
9
4
4...
after loop in R I would like to get my
2009 Apr 29
2
library which convert dates
I'm looking for library which let mi convert dates
for example like this:
00-06-05 00:00
00-08-06 00:00
00-08-16 00:00
00-05-23 00:00
00-01-14 00:00
00-10-28 00:00
and as a result I want to get a 3 levels
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2009 Jun 01
3
Editor R
Do you know any good editor R?
--
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2009 Jun 15
2
function inside ifelse
Hi,
Could you tell me, if it's possible to create ifelse and put function
inside, for example:
code{
ifelse ((is.na(vek)), call_fun_1(arguments), call_fun_2(arguments))
call_fun_1 <- function(arguments)
{ sth...
}
}
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2011 Oct 11
1
Mean or mode imputation fro missing values
Dear R experts,
I have a large database made up of mixed data types (numeric,
character, factor, ordinal factor) with missing values, and I am
looking for a package that would help me impute the missing values
using ?either the mean if numerical or the mode if character/factor.
I maybe could use replace like this:
df$var[is.na(df$var)] <- mean(df$var, na.rm = TRUE)
And go through all the many
2009 Jun 14
3
if + is.na
Hello!
I wont to use a function is.na()
I have two vectors:
> a=c(1,NA,3,3,3)
> b=c(0,0,0,0,0)
and when I use is.na function it's ok:
> is.na(a)
[1] FALSE TRUE FALSE FALSE FALSE
but I would create sth like this:
for i in 1:length(a){
if (wsp[i] == is.na(a)) {b=43}
}
or like this
if(is.na(a)) b=3 else a
[1] 1 NA 3 3 3
but I always get an error:
the condition has
2011 Oct 07
3
Re: [1.2] Trying to run MAFIA II under wine
Lukash wrote:
> Hello to everybody!
> I finally managed to launch Mafia II on my Ubuntu 10.10 64bit - Steam version thanx to Kairhos. I was not able to do so earlier.
> But, If I try to launch new game, it gets stuck. Any ideas? Thanks
Hi! I was able to launch Mafia on Windows 7 Ultimate 64-bit :)
2010 Jan 06
1
math function - MDS method
Hi,
I need math function which is used in: isoMDS, Sammon and metaMDS method.
Anybody know where I may find it? Any manual or webside?
I would be very happy
Thanks a lot !
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2009 May 31
1
Error:non-numeric argument in my function
Hello!
I have a function:
zywnoscCalosc<- function( jedzenie, n1, n2, n3, n4, d1, d2, d3, d4 ) {
ndf <- data.frame(nn1=n1,nn2=n2,nn3=n3,nn4=n4)
ddf <- data.frame(dd1=d1,dd2=d2,dd3=d3,dd4=d4)
for (i in 1:length(n1)){
wekt_n = ndf[i,]
wekt_n_ok = wekt_n[!is.na(wekt_n)]
dl_n = length(wekt_n_ok)
wynik = (1*wekt_n_ok)/(1*dl_n)
}
}
and I get an error like this:
Error in 1 * wekt_n_ok :
2009 Jun 16
1
ifelse(is.na), with function inside
Hi,
I have a vector a=c(NA, 3, 4, 4, NA, NA, 3) and I would like to use is.na(a)
function to get a vector like this:
wy=(1,2,2,2,1,1,2) - you know, this vector create 1 or 2 depends on value in
vector "a"
This is my short code but something is wrong and I don't know what...
for (i in 1:7){
a=c( NA, 3, 4, 4, NA, NA, 3)
fun1=function(x){
x=1
print(x)
}
fun2=function(x){
2007 Apr 12
2
problems in loading MASS
Hi, there:
After I upgraded my R to 2.4.1, it is my first time of trying to use
MASS and found the following error message:
> install.packages("MASS")
--- Please select a CRAN mirror for use in this session ---
trying URL 'http://cran.cnr.Berkeley.edu/bin/macosx/universal/contrib/2.4/VR_7.2-33.tgz'
Content type 'application/x-gzip' length 995260 bytes
opened URL
2009 Aug 13
1
write result in matrix using loop
Hello,
I want call my function (use my database) and write every result in matrix
"wynik" but I always get an error: Error in wynik[, i] <- dodawanie(wzorzec,
wzorzec1) :
number of items to replace is not a multiple of replacement length
I'll be very happy if sb help me
dodawanie<- function ( wzorzec, wzorzec1){
wynik1<-wzorzec + wzorzec1
wynik2<-wzorzec *