similar to: rbind on a list

Displaying 20 results from an estimated 900 matches similar to: "rbind on a list"

2012 Jul 27
1
overlaying a set of 'grouping' lines on a plot from image()
Hi, I have a matrix that I am displaying via image. I would like to obtain an image where the columns are 'grouped' (I have a grouping variable). But I am not sure how how I can draw the lines to indicate the grouping in the margin. I realize this is essentially waht heatmap does but as I have a set of custom breaks and colors I wanted to generate this via image. I can see that it is a
2010 Feb 15
4
density estimates for fixed points
Problem: Based on a n x 2 data matrix i want a kernel estimate of the bivariate density. However, i also wish to specify wich points the density should be calculated at. I can offcourse just write the full kernel density estimate as a R-code, but surely there must already exist some package for this operation? The package density(), seems to create a new matrix (depending on n), where the
2011 Jan 28
3
sapply puzzlement
Hi, I have this data.frame with two variables in it, > z V1 V2 1 10 8 2 NA 18 3 9 7 4 3 NA 5 NA 10 6 11 12 7 13 9 8 12 11 and a vector of means, > means <- apply(z, 2, function (col) mean(na.omit(col))) > means V1 V2 9.666667 10.714286 My intention was substracting means from z, so instictively I tried > z-means V1 V2 1 0.3333333
2009 Jul 17
1
Arules questions. I need some help please
Question 2a) I am also working with arules package and I have the following problem let suppose the matrix b like: b<-matrix(c(1,1,1,1,1,1,0,0,1,1,1,1,0,0,1,1,0,1,1,1,1,1,1,1),nrow=6) rownames(b)=c("T1", "T2", "T3", "T4", "T5", "T6") colnames(b)=c("It1", "It2", "It3", "It4") bt<-as(b,
2007 Mar 28
2
Standardization Range
? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile Url: https://stat.ethz.ch/pipermail/r-help/attachments/20070328/ee4422a2/attachment.pl
2013 Mar 14
1
ggplot2 problem
Hello all! I have a problem with ggplot2 library. I want to do an heat map and the y variables are the year months. If I use the following code, he y values are in alphabetical order, but I want it in month order. The code is: library(reshape) library(ggplot2) library(scales) p <- ggplot(data.m, aes(variable, Month)) + geom_tile(aes(fill = value),
2009 Nov 05
4
collumn error when exporting to Excel
Dear all, I am attempting to export my results (data.frame) created with the help of a number of you to Excel. In the procedure my column structure is however lost and all results are placed together into the first Excel column. I have tried: write(), write.table(), write.matrix(), export() and have the same results. I Have checked the import/export FAQ and did a Google search to no avail. Any
2017 Jun 26
3
Jagged ROC curves?
Hi, I was trying to draw some ROC curves (prediction of case/control status), but seem to be getting a somewhat jagged plot. Can I do something that would 'smooth' it somewhat? Most roc curves seem to have many incremental changes (in x and y directions), but my plot only has 4 or 5 steps even though there are 22 data points. Should I be doing something differently? How can I provide a
2017 Jun 26
0
Jagged ROC curves?
> On Jun 26, 2017, at 11:40 AM, Brian Smith <bsmith030465 at gmail.com> wrote: > > Hi, > > I was trying to draw some ROC curves (prediction of case/control status), > but seem to be getting a somewhat jagged plot. Can I do something that > would 'smooth' it somewhat? Most roc curves seem to have many incremental > changes (in x and y directions), but my plot
2007 May 05
1
(no subject)
Dear Mailing-List, I think this is a newbie question. However, i would like to integrate a loop in the function below. So that the script calculates for each variable within the dataframe df1 the connecting data in df2. Actually it takes only the first row. I hope that's clear. My goal is to apply the function for each data in df1. Many thanks in advance. An example is as follows: df1
2010 Apr 18
3
xtabs() of proportions, and naming a dimension (not a row)
Hi, xtabs() creates a table of counts. I want a table of proportions -- that is, I want to divide every vector (along a particular dimension) by its sum. The tiny example below does that. The call to xtabs() creates a matrix "A" with dimensions ("x1","x2","y"). I transform "A" using aperm() and aaply() to get the matrix "B". The
2008 Oct 16
2
saving result of a "for" loop
Hi everyone, I have dataset which I take random samples of it 5 times. each time I get the mean for rows for each sample. at the end I need to calculate the Average of all means for each sample and each row. to clear it up I give an example: say this is my dataset. X8 X9X10X12 X13 X14 X15 X16X17X18X19 X20 X21 X22 s1 0 1 0 0 0 1 0 0 0 0 0 0 0 0 s2 0 0 0
2009 Aug 13
4
lm coefficients output confusing
Hi all, I have an issue with the lm() function regarding the listing of the coefficients. My data are below, showing a list of hours (HR) relating to the time spent resting (R) by an individual animal. Simply i want to run a lm() to run in an anova() to see if there is a significant difference in resting between hours. HR R 1 2 0.6666667 2 2 0.4666667 3 2 0.8000000 4 2
2011 Jan 26
0
Fwd: MAtrix addressing
Begin forwarded message: > From: David Winsemius <dwinsemius at comcast.net> > Date: January 26, 2011 8:32:30 AM EST > To: Alaios <alaios at yahoo.com> > Subject: Re: [R] MAtrix addressing > > > On Jan 26, 2011, at 7:58 AM, Alaios wrote: > >> Unfortunately right now is convoluted... by I was trying to find >> some solution. >> Bring again
2018 Mar 11
3
Empirical density estimation
Hi, Let say I have below vector of data-points : Dat = c(-0.444444444444444, -0.25, -0.237449799196787, -0.227467046669042, -0.227454464682363, -0.22, -0.214876033057851, -0.211781206171108, -0.199891067538126, -0.192920353982301, -0.192307692307692, -0.186046511627907, -0.184418145956608, -0.181818181818182, -0.181818181818182, -0.181266261925412, -0.181003118503119, -0.179064587973274,
2018 Mar 15
0
cubic complete Scheffe mixture models
Hello everyone I'm trying to use Scheffe's complete cubic model (mixture design). In the bibliographies, they indicate that the term is of the type: A * B * (A-B). But I see that trying to adjust the three cubic terms results in singularities. I know this implies not having the inverse matrix: solve (t (X)% *% X) does not exist. The bibliographies show all three cubic terms. So my
2009 Jan 09
5
grep : escape "*"
Dear R useRs, Sorry for this foolish question, but I can't find how to escape the * character when using grep : > grep("-", c("/3", "2*3", "4-4")) [1] 3 > grep("/", c("/3", "2*3", "4-4")) [1] 1 > grep("*", c("/3", "2*3", "4-4")) Erreur dans grep("*",
2006 Nov 29
2
filled.contour and NA's
Hi, I'm trying to do a filled.contour plot where some points are labelled as NA. How do I could plot this kind of graphics, so NA points are coloured black, keeping the levels of remaining points. NA's values represent land points (meaningless), and what I want to plot is the levels of a variable over the sea. x<-seq(length=21, from=-10, by=.25) y<-seq(length=8, from=36,
2018 Mar 11
0
Empirical density estimation
You need to re-read ?density and perhaps think again -- or do some study -- about how a (kernel) density estimate works. The points at which the estimate is calculated are *not* the values given, nor should they be! Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his
1997 May 01
0
R-alpha: eigen()
eigen() seems to work for symmetric matrices only. This is out of sync with the help file. > trpr.37 0 1 2 3 4 0 1.00000000 0.0000000 0.0000000 0.0000000 0.0000000 1 0.44444444 0.5555556 0.0000000 0.0000000 0.0000000 2 0.02439024 0.2439024 0.7317073 0.0000000 0.0000000 3 0.00000000 0.0000000 0.2307692 0.7692308 0.0000000 4 0.00000000 0.0000000