similar to: Running Edit() or Fix() on Linux Machine

Hi there, Just wondering if someone can help me with the correct syntax to use with for loops? I have split my original file by count, & wish to first of all assign new tables based on the splits. Then I just want to create a new variable. Please see code below. This code works outside of a loop so I am just trying to code so I don't have to repeat numerous times. Many

Hi there, Just wondering if anyone has any tips for using arrays? I am trying to convert the following SAS code to R: data A2; set A1; by subject_id; retain BX1-BX10 i; array b(1:10) BX1-BX10 ; if first.subject_id then do ; do j=1 to 10; b(j) = .; end; i=1; end; b(i) = BX; i = i+1; if last.subject_id then

Here I think S3 dispatch is very natural. Try the following: page <- function(x, method = c("dput", "print"), ...) UseMethod("page") page.getAnywhere <- function(x, ..., idx=NULL) { name <- x$name; objects <- x$obj; if (length(objects) == 0) stop("no object named '", name, "' was found"); if (is.null(idx)) {

Hi all, I am new to using R on a Linux machine & I have a few questions on set-up. If anyone has experience in this area any advice would be greatly appreciated. - When I open R I have the option to do the following: o 'Run in Terminal' o 'Display' o 'Cancel' o 'Run' - My only option to open a window such as we find in

Hi, I would like to construct a transition matrix from a data frame with annual transitions of marked plants. plant<-c(1:6) class<-c("seed","seed", "seed", "veg", "rep", "rep") fate<-c("dead", "veg","veg","rep", "rep", "veg") trans<-data.frame(plant, class, fate)

Hello all, turns out i'm having a bad R week. I am at my wits end with a function that I am trying to write. When I run the lines of code outside of a function, I get the desired output. When I wrap the lines of code into a function it doesn't work as expected. Not sure what is going on here. I suspected that the syntax of the if statement with the for loop was the culprit, but when I

I can't run fix() or edit() anymore. Did I break my system? I'm running Debian Linux with R-2.14.1. As far as I can tell, the R packages came from Debian's testing "wheezy" repository. I would like to know if users on other types of systems see the same problem. If no, then, obviously, it is a Debian-only issue and I can approach it from that point of view. And if no other

(moved from R-help) I tried this on Ubuntu with R-2.14.1 built from source, and I do not get the segfault problem. (I don't at the moment have a debian binary R, or I would confirm whether I get the segfault problem.) My sessioninfo() is reporting additional information about namespace imports: > library(ggplot2) Loading required package: reshape Loading required package: plyr

Hello. First post, though I have read scores. Mostly i can solve my problems reading the archives, but I lack the vocabulary to ask this one right. Any social faux pais, I apologize. I am sure this is a very basic question and I am embarrassed to ask, but I spent several hours scouring the archives and trying various suggestions, but I am too new to get any of them to work. I am trying to

Hi R listers, I am trying to group distances of nests to the vegetation into classes that are define by (0-5m, 6-10m, 11-15m, 16-20m, 21-25m, 26-30m, 31-35m, 36-40m, 41-45m, 46-50m, 51-55m, 56-60m). Each row is a nest and all the distances to the vegetation is in a column. In plyr, I have tried - below script but I think I am going about this the wrong way and am not successful. #Veg index

Hi all, How can I overlay these two histograms? ggplot(gg, aes(gg$Alz, fill = gg$veg)) + geom_histogram(alpha = 0.2) ggplot(tt, aes(tt$Cont, fill = tt$veg)) + geom_histogram(alpha = 0.2) thanks for any help! Elahe

i want to tag categories to its menuname. i have a csv containing menu item name and in other csv i have a column containing some strings, i want to pick that strings from categories and look into menu items if any menu item containing that string i want to create a new column next to menu item name flagged as 1 otherwise 0 and the only condition is once a menu item flagged as 1 i don't need

Hi R-listers, I am trying to do an ANOVA for the following scatterplot and received the following error: library(car) scatterplot(HSuccess ~ Veg, data = data.to.analyze, xlab = "Vegetation border (m)", ylab = "Hatching success (%)") anova(HSuccess ~ Veg, data=data.to.analyze) Error in UseMethod("anova") : no applicable

Hi R-users: [R 2.2 on OSX 10.4.3] I have a (sparse) vegetation data frame with 500 rows (sampling units) and 177 columns (plant species) where the data represent % cover. I need to summarize the cover data by returning the names of the most dominant and the second most dominant species per plot. I reduced the data frame to omit cover below 5%; this is what it looks like stacked. I have

R gurus, Every so often(*) someone asks how to suppress scientific notation in printing, so I thought I'd give it a shot, but I need some help. The formatting decision is made(**) on line 286 of src/main/format.c : if (mF <= *m) { /* IFF it needs less space : "F" (Fixpoint) format */ where mF is the number of characters for "normal" printing and *m is the number

While implementing R's new 'altrep' functionality in the TERR engine, I discovered a bug in R's 'deferred_string' altrep object: it is not using the correct value of the 'OutDec' option when it expands a deferred_string. See the following example: R 3.5.1: (same results in R 3.6.0 devel engine built 10/5) > options(scipen=0, OutDec=".") >

Hello all, I am going slightly mad trying to create a table for running co-correspondence analysis. What I have is seed bank and vegetation data, and my aim is to see if the vegetation found in a site (containing several seed bank samples) can predict the composition of a seed bank sample within that site. So for this I need two tables with matching rows. I have created an empty matrix,

Hi all, Given a data frame as... > head(veg) genus species trophia type geo zone importance 1 Sphagnum subsecundum M A En 100 2 Sphagnum denticulatum M A En 200 3 Molinia caerulea M A En 300 4 Sphagnum flexuosum M A En 400 5 Juncus squarrosus M A En 500 6

Hi All, I am wondering if anyone can tell me what the warning message below the model means? J add1(DTA.glm,~ Aeventexhumed + Veg + Berm + HTL + Estuary + Rayos) Single term additions Model: cbind(MaxHatch, TotalEggs - MaxHatch) ~ Aeventexhumed + Veg + Berm + HTL Df Deviance AIC <none> 488.86 4232.9 Estuary 1 454.96 4201.0 Rayos 3 258.80 4008.9 Warning

Hi R-listers, I have developed 47 GLM models with different combinations of interactions from 1 variable to 5 variables. I have manually made each model separately and put them into individual tables (organized by the number of variables) showing the AIC score. I want to compare all of these models. 1) What is the best way to compare various models with unique combinations and different number