Displaying 20 results from an estimated 1000 matches similar to: "automatic exploration of all possible loglinear models?"
2008 Jun 26
2
stuck on making a line graph across time, with 4 categories
I can't seem to find just what I'm looking for in R help, Everitt and
Hothorn HSAUR, Murrell's book, or the R graphics gallery at
http://addictedtor.free.fr/graphiques/. Probably not looking
efficiently, but anyway,
If my data look like this:
> head(data)
cat startyear studentid
1 other 2001 12
2 UHS 2001 17
3 Lourdes 2001 10
4
2007 Jul 13
3
THANK YOU: Updating R version
Based on the feedback received, I did the following:
a) moved my lib sub-directory from the existing installed R version to
c:\myRLib
b) installed the updated R version
c) created .Renviron file in the home directory (C:\R-2.5.1) with the line
R_LIBS=c:/myRLib
d) used .libPaths() command to confirm that the new R installation was
recognizing the myRLib sub-directory
e) deleted my old R
2009 Jun 30
4
conditional coloring of output text in console or in GUI
suppose I have some logical vector
x <- as.logical(c(0,0,0,1,0,0,1,1,0))
x
How would I make the words TRUE appear on the screen in a different
color from the words FALSE?
Thanks.
--Chris
--
Christopher W. Ryan, MD
SUNY Upstate Medical University Clinical Campus at Binghamton
40 Arch Street, Johnson City, NY 13790
cryanatbinghamtondotedu
"If you want to build a ship, don't drum
2008 Jul 14
2
question about a small "for" loop
R 2.5.1 on WinXP
I'm trying to create new variables in a dataframe called jaw, as powers
of jaw$age up to the sixth power, and name them
jaw$age.(--the digit corresponding to the power--)
Obviously none of these work (silly for me to try, I suppose):
for (i in 2:6) {
jaw$age.'i' <- jaw$age^i
}
for (i in 2:6) {
jaw$age.i <- jaw$age^i
}
for (i in 2:6) {
2011 Aug 30
3
having trouble extracting week from chron object
Running R 2.13.1 on Windows XP.
I would like to get week of the year (1-52) for each date.
library(chron)
dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92"))
dts
dts.chron <- as.chron(dts)
dts.chron
class(dts.chron)
# all of these component extractions work:
months(dts.chron)
weekdays(dts.chron)
years(dts.chron)
2009 Jan 27
2
using Sweave with a master file that has several iputted .tex files
Suppose I have a Master.Rnw file that looks something like this:
\documentclass[12pt]{mypaper}
\usepackage[margin=1in]{geometry}
\usepackage{setspace}
\usepackage{url}
\usepackage{indentfirst}
\usepackage{fancyhdr}
\usepackage{Sweave}
\pagestyle{fancy}
\lhead{sonographic rectal diameter and ADHD}
\rhead{ }
\usepackage{abbrevs}
%\usepackage{natbib}
%\usepackage{apacite}
2018 May 01
2
How would I color points conditional on their value in a plot of a time series
How would I color points conditional on their value in a plot of a time
series. Something like this:
## demonstration data
ttt <- ts(rpois(12, lambda = 8), start = c(2000, 1), freq = 4)
ttt
plot(ttt, type = "p")
## doesn't work--all points the same color
plot(ttt, type = "p", col = ifelse(ttt < 8, "black", "red"))
## also doesn't work--all
2009 Jan 21
1
trouble converting an array to a dataframe
I start with a dataframe called xrays. It contains scores on films from
each of two radiologists. It is in "long" format. I used the reshape
package to melt a data frame and then cast it into "wide" format, one
line for each patient (identified by redlognumb) with scores from both
radiologists for a given patient on the same line.
I named the result of the casting xrays.data.
2009 Jan 30
1
problem using identify() after plot()
I can't seem to use the point-and-click identify() function properly.
I'm running R 2.5.1 (I know, I need to get around to upgrading) under
Win XP. The problem is, when I click on a point on the graph, I get an
error, "no point within 0.25 inches." But in some areas, I can click
where there is no visible point anywhere close, and an identify() label
will pop up. The troublesome
2018 May 01
2
How would I color points conditional on their value in a plot of a time series
Excellent! Worked like a charm. Thanks.
--Chris Ryan
On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote:
> The ts method for plot() is quirky. You can use the default method:
>
> plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8,
> "black", "red"))
>
>
> Bill Dunlap
> TIBCO Software
2018 May 01
0
How would I color points conditional on their value in a plot of a time series
The ts method for plot() is quirky. You can use the default method:
plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8,
"black", "red"))
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, May 1, 2018 at 1:17 PM, Christopher W Ryan <cryan at binghamton.edu>
wrote:
> How would I color points conditional on their value in a plot
2012 Apr 18
6
introducing R to high school students
I participate peripherally on a listserve for middle- and high-school
science teachers. Sometimes questions about graphing or data analysis
come up. I never miss an opportunity to advocate for R. However, the
teachers are often skeptical that their students would be able to
issue commands or write a little code; they think it would be too
difficult. Perhaps this stems from the Microsoft- and
2010 Apr 14
1
Sig differences in Loglinear Models for Three-Way Tables
Hi all,
I've been running loglinear models for three-way tables: one of the
variables having three levels, and the other two having two levels each.
An example looks like below:
> yes.no <- c("Yes","No")
> switch <- c("On","Off")
> att <- c("BB","AA","CC")
> L <- gl(2,1,12,yes.no)
> T <-
2018 May 01
0
How would I color points conditional on their value in a plot of a time series
You may also want to check this out:
plot(ttt, type = "p")
points(ttt, col = ifelse(ttt < 8, "black", "red"))
Eivind K. Dovik
Bergen, NO
On Tue, 1 May 2018, Christopher W Ryan wrote:
> Excellent! Worked like a charm. Thanks.
>
> --Chris Ryan
>
> On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote:
>
>> The
2012 Jun 08
1
Fwd: How to best analyze dataset with zero-inflated loglinear dependent variable?
Dear netters,
Sorry for cross-posting this question. I am sure R-Help is not a
research methods discussion list, but we have many statisticians in
the list and I would like to hear from them. Any function/package in R
would be able to deal with the problem from this researcher?
---------- Forwarded message ----------
From: Heidi Bertels
Date: Tue, Jun 5, 2012 at 4:31 PM
Subject: How to best
2011 Jan 19
3
question about result of loglinear analysis
Hi all:
Here's a question about result of loglinear analysis.
There're 2 factors:area and nation.The raw data is in the attachment.
I fit the saturated model of loglinear with the command:
glm_sat<-glm(fre~area*nation, family=poisson, data=data_Analysis)
After that,I extract the coefficients:
result_sat<-summary(glm_sat)
result_coe<-result_sat$coefficients
I find that all the
2009 May 19
1
loglinear analysis
Dear R Users,
A would like to fit a loglinear analysis to a three dimensional contingency
table. But I Don't want to run a full saturated modell. Is there any package
in R that could handle somekind of stepwise search to choose out the best
soultion? And how can I fit a non fully saturated modell, which only use the
important interactions?
Best Regards
Zoltan Kmetty
[[alternative HTML
2002 Oct 23
2
loglinear models
I am using the loglin function of the base package to fit log-linear models.
I am interested in obtaining the parameter values and their standard errors.
Parameters are easily obtained, but I haven't found the way of obtaining
their standad errors. Is this possible with the loglin function? If not, is
there any other function to get them?
Many thanks,
--
Vicente Piorno
Departamento de Ecolox?a
2007 Oct 07
5
how to use \Sexpr{} with sweave
I'm trying to learn Sweave. So far things are going well with the chunks of code identified by << >>=
But I'm having trouble with the in-line text use of \Sexpr.
Here is a short example .Rnw file:
\documentclass[12pt]{article}
\usepackage[margin=1.25in]{geometry}
\usepackage{graphicx}
\usepackage{Sweave}
\begin{document}
<<test>>=
pnorm(1)
@
\Sexpr{2+6}
2011 Mar 22
2
adding vertical segments to an xyplot in lattice
I have a dataframe that looks like this:
> str(chr)
'data.frame': 84 obs. of 7 variables:
$ county: Factor w/ 3 levels "Broome","Nassau",..: 3 3 3 3 3 3 3 3 3 3 ...
$ item : Factor w/ 28 levels "Access to healthy foods",..: 21 19 20
18 16 3 2 6 17 8 ...
$ value : num 8644 15 3.5 3.9 7.7 ...
$ low : num 7897 9 2.5 2.6 7 ...
$ high : num 9390