similar to: Student

If I combine elements into a list b <- c(22.4, 12.2, 10.9, 8.5, 9.2) my.c <- sample.int(round(2*mean(b)), 5) my.list <- list(b, my.c) the names of the elements seems to get lost in the process: > str(my.list) List of 2 $ : num [1:5] 22.4 12.2 10.9 8.5 9.2 $ : int [1:5] 11 8 6 9 20 If I explicitly name the elements at list-creation, I get what I want: my.list <- list(b=b,

c <- structure(c(2L, 2L, 1L, 3L, 4L, 2L, 3L, 2L, 3L, 2L, 5L), .Label = c("foo", + "bar", "a really really long variable label mostly here to show the need of word-wrapping text in labels", + "a not so important value", "baz"), class = "factor") plot(c) Is there a way to get the long variable labels to automatically wrap so that all

Hello r-help! I have data with two kind of ratings on status of 100 occupations. The first kind of rating is on the percieved "objective" status that these occupations have in society at large, and the second kind or rating is on the status that the respondents think that these occuption *should* have. The ratings were originally integer values in the rage 1-9, but in the current data,

foo <- rnorm(30*34*12) dim(foo) <- c(30, 34, 12) I want to make a data.frame out of this three-dimensional array. Each dimension will be a variabel (column) in the data.frame. I know how this can be done in a very slow way using for loops, like this: x <- rep(seq(from = 1, to = 30), 34) y <- as.vector(sapply(1:34, function(x) {rep(x, 30)})) month <- as.vector(sapply(1:12,

I want 100 integers. Each integer, x, can be in the range 1 =< x => 10. Does the following code give 1 and 10 the same chances to be selected as 2:8? round(runif(100, min = 1, max = 10)) -- Hans Ekbrand -------------- next part -------------- A non-text attachment was scrubbed... Name: not available Type: application/pgp-signature Size: 197 bytes Desc: Digital signature URL:

Dear R users, I have a problem since I try to plot my datas with different colors. plot(tvar, var, xlab="zeit [s]",ylab="Variation [%]", col = ifelse(var <= varstability, 'green','red')) this works well! But since I add a type="l" to my plot, it will color all the plot with green!!! Is there any solution? I avoid to use teachingDemos. Thanks. --

Hi all Say I have a function: myname=function(dat,x=5,y=6){ res<<-x+y-dat } for various input such as myname(dat1) myname(dat2) myname(dat3) myname(dat4) myname(dat5) how should I modify the 'res' line, to have new informative variable name correspondingly, such as dat1.res dat2.res dat3.res dat4.res dat5.res stored in the workspace. This is only an example of a complex

Hello, I have a nasty loop that I have to do 11877 times. The only thing that slows it down really is this merge: xx1 = merge(dt,ua_rd,by.x=1,by.y= 'rt_date',all.x=T) Any ideas on how to speed it up? The output can't change materially (it works), but I'd like it to go faster. I'm looking at getting around the loop (not shown), but I'm trying to speed up the merge first.

Dear All, I am trying to install rgl on my mac notebook from the source file. I tried using: /usr/bin/R64 CMD INSTALL rgl_0.92.798.tar.gz and get the following error message: checking for X... no configure: error: X11 not found but required, configure aborted. ERROR: configuration failed for package ?rgl? * removing ?/Library/Frameworks/R.framework/Versions/2.14/Resources/library/rgl? *

Hi list I have a data frame I would like to loop over. To begin with I would like crosstabulations using the first variabel in the data frame, which is called "meriter". > table(meriter[[1]], meriter[[3]]) ja nej Annan 0

Hi r-help! Consider the following data-frame: var1 var2 var3 1 3 1 4 2 2 2 3 3 2 2 3 4 4 4 NA 5 4 3 5 6 2 2 3 7 3 4 3 How can I get R to convert this into the following? Value 1 2 3 4 5 var1 0 3 2 2 0 var2 1 3 1 2 0 var3 0 0 4 1 1 TIA, -- Hans Ekbrand (http://sociologi.cjb.net) <hans at

I must be missing something obvious here: According to the help page for read.spss, the reencode option is only active when R is run under a UTF-8 locale. read.spss can only import the SPSS file when run under a iso88591(5) locale, under a UTF-8 locale I get: Error in read.spss("wo.sav") : error reading system-file header In addition: Warning message: In read.spss("wo.sav")

Hi, I'm using Samba 2.0.7 and I'm experimenting with shares at the moment. I created a share on my SuSE 6.4 box and accessed it from a Win2000 machine. Than I deleted this share entirely, and expected that I wouldn't be able to see it anymore from the win2000 box (after refreshing the view in windows explorer) but the opposite happened. What could be the explanation and the

Hi, 1. I have 2 panes, each having approximately 45-50 slides, all the slide images are 110x82 pixels in size, enclosed in their respective div''s. 2. These divs are further enclosed in a parent div, which is defined as a Sortable on page load. 3. There is a destination div on the RHS also. Sortable.create("div_leftDiv", {ghosting:true, revert: true, dropOnEmpty:true,

By default the prototype.js gives us the function /* prevent memory leaks in IE */ Event.observe(window, ''unload'', Event.unloadCache, false); But there is no unload event in out application as the content of the div keeps changing using the Ajax.Updater function. To handle such a scenario, we''ve added the following lines of code to prototype.js /* prevent

Dear R helpers, I have a large data set with 36 variables and about 50.000 cases. The variabels represent labour market status during 36 months, there are 8 different variable values (e.g. Full-time Employment, Student,...) Only cases with at least one change in labour market status is included in the data set. To analyse sub sets of the data, I have used daisy in the cluster-package to create

Hi list! Short version: How do I convert a whole data.frame from latin1 encoding to utf8? I get SPSS files with latin1 encoding. My OS is GNU/Linux and the locale sv_SE.utf8, and I normally interface R with Emacs/ESS. I have used the following hack to convert a data.frame in latin1 to utf8: > Sys.setlocale(category = "LC_ALL", locale = "sv_SE.iso88591") > foo <-

Hi, I'me trying to write a function that will shuffle a vector. At the moment I'm baically making a vector of randomized indices and then making a new vector from the original one using these random indices. However, is there an alternative (more elegant) method to do this? I tried help.search('shuffle') but it does'nt return anything relevant. Thanks,

Please, is there anyone who can give me some suggestions? (1) I have to use a package from R on my work. The package is the "quantreg" developed by Koenker (Uni Illinois). I have installed the package in the R library tree /usr/local/lib/R/ library of my Linux Operating System. I did R CMD INSTALL -l /usr/local/lib/R/ library /path/to/quantreg_x.y-z.tar.gz. However, when I call any

My name is Stuardo, from Guatemala and i have this problem: We want to stream a local radio, but the bandwidth here in Guatemala is no so cheam ass in USA, so we have a server in USA. What we want to do is this: to stream the local radio from Guatemala to USA, this means that the local machine will only have 1 client. Then we want that the server in USA "rebounds" what it recives