similar to: Sum of character vector

Dear mailing list I have a data that have 20,000 rows and 20 columns. Io wonted to extract the 10th row only. Example the 10th, 20th, 30th 40th…..20000 th. can you please help me how do I do that.Than kyou. Example is below. Inpute: AG GG GG AG CC CC CC CC CT CC CT CT GG GG GG GG CC CC CC CC GG GG GG GG CC CC CC CC GG CG CG GG GG GG GG GG *CC CC CC CC* AA AG AG AA AA AA AA AA GG AG AG GG GG AG AG

Dear All I have a data.frame like that: structure(list(name = c("Gga_rs10722041", "Gga_rs10722249", "Gga_rs10722565", "Gga_rs10723082", "Gga_rs10723993", "Gga_rs10724555", "Gga_rs10726238", "Gga_rs10726461", "Gga_rs10726774", "Gga_rs10726967", "Gga_rs10727581", "Gga_rs10728004",

Hi, I am trying to split multiple columns. One column works just fine, but I want to do it for multiple columns??? Example > a ID V2 V3 V4 V5 V6 V7 V8 V9 V10 1 PBBA0644 -- GG AA -- AA -- AA GG GG 2 PBBA1010 -- GG AA -- AA -- AA GG GG 3 0127ATPR -- GG AA -- AA -- AA GG GG 4 0128EHAB -- GG AA -- AG -- AA AG GG 5 PBBA0829 -- GG AA -- AA -- AA GG AG

I HAVE A VERY BIG DATA OF 67 COLMS AND 25000 ROWS AND WOULD LIKE TO TRANSPOSE IT THE R HELP WAS NOT ENOUGH INFORMATION BECOUSE I AM NOT A PROGRAMMER AND FIRST TIME R USER. SO CAN YOU GIVE SOME HINTS OF CODING, AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC TO AA AA AA AA AA TT TT TT TT TT GG GG GG GG GG GG GG GG GG GG CC CC CC CC CC [[alternative HTML

The documentation for assignment says: In all the assignment operator expressions, 'x' can be a name or an expression defining a part of an object to be replaced (e.g., 'z[[1]]'). A syntactic name does not need to be quoted, though it can be (preferably by backticks). But the implementation allows assignment to a character string (i.e. not a name), which it

Dear R users, I am trying to fill in arrays (5 different according to distinct "id") from objects produced from arbitrary data set below. a <-

Dear Contributors I have a problem with the collection of data from the results of a test. I need to perform a comparative test over groups of data , recall the value of the pvalue and create a table. My problem is in the way to replicate the analysis over and over again over subsets of data according to a condition. I have this database, called y: gg t1 t2 d 40 1 1

I was going through the example below which is taken from the example section in the R documentation for accessing the function call stack. I am confused and I have 3 questions that I was hoping someone could answer. 1) why is y equal to zero even though the call was done with gg(3) 2) what does parents are 0,1,2,0,4,5,6,7 mean ? I understand what a parent frame is but how do the #'s relate

I have a more complicated function I am trying to write, but I run in to a problem when I want to add something to the plot from more than one data set while simultaneously controlling the appearance of the additional layer. # Toy data: foo <- data.frame ( x = 1:4, y = 4:1 , membership = c( "A", "A", "B", "B" ) ) bar <- data.frame ( x = 1:4 + 1 , y

Hi, I have a large dataset on which I would like to do the following: x<-data.frame(id=c(1,2,3), snp1=c("AA","GG", "AG"),snp2=c("GG","AG","GG"),snp3=c("GG","AG","AA")) > x id snp1 snp2 snp3 1 1 AA GG GG 2 2 GG AG AG 3 3 AG GG AA And then

I'm switching from OpenLDAP to the newly released Fedora Directory Server (formely known as the Netscape Directory Server) as a LDAP backend for my Samba domain. I'm now faced with a problem regarding how Fedora DS handles the userPassword field. Unlike OpenLDAP it encodes it in base64 so instead of reading userPassword: {SSHA}0lP+r3Z1NVan7Caf4CG9oSgnTbQRrv/p it reads: userPassword::

I am trying to create plots within a for loop and output them to a pdf. Here is a working example using plot: gg <- data.frame(datadate=1:4, spread=5:8) pdf() for (i in 1:3) { plot(gg$datadate, gg$spread, main=i) } dev.off() I am trying to learn more about ggplot2 so I try a slight modification and it doesn't work. Anyone

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA

Hello, I have a question regarding competing risk regression using cmprsk package (function crr()). I am using R2.9.1. How can I do to assess the effect of qualitative predictor (gg) with more than two categories (a,b,c) categorie c is the reference category. See above results, gg is considered like a ordered predictor ! Thank you for your help Jan > # simulated data to test > set.seed(10)

Can you try out the attached patch? Aki > On 03 February 2019 at 17:17 Marcel Menzel <mail at mcl.gg> wrote: > > > All I did was > > ??? - create a sqlite database with: # sqlite3 /tmp/storage.db (/run > only to test for perm issues in other folders) > > ??? - change it's owner to mail (that's the user owning the mail files): > # chown mail:mail

Dear all, I am puzzled by the following behavior of the new grid.cap() function, which appears to run out of time when capturing the output of a graphic. It works fine if I introduce a Sys.sleep(1) before executing more code, library(grid) quartz() grid.circle(gp=gpar(fill="black")) gg <- grid.cap() dev.new() grid.raster(gg) ## completely blank gg[gg!="white"] ## indeed

I have a data set like this in one .txt file (cols separated by !): APE!KKU!684! APE!VAL!! APE!UASU!! APE!PLA!1! APE!E!10! APE!TPVA!17122009! APE!STAP!1! GG!KK!KK! APE!KKU!684! APE!VAL!! APE!UASU!! APE!PLA!1! APE!E!10! APE!TPVA!17122009! APE!STAP!1! GG!KK!KK! APE!KKU!684! APE!VAL!! APE!UASU!! APE!PLA!1! APE!E!10! APE!TPVA!17122009! APE!STAP!1! GG!KK!KK! it contains over 14 000 000 records. Now

Dear folks? Is there a function to correctly find (and count) the NAs in a factor when exclude=NULL, regardless of whether their origin is in the original data or by subsequent assignment? In example number 1 below, where NAs are assigned by is.na()<-, testing the factor with is.na() finds the correct number of NAs. In example number 2, where the NAs are from the data, neither is.na(), ==NA,

<!doctype html> <html> <head> <meta charset="UTF-8"> </head> <body> <div> Can you provide steps on how to reproduce this? Tracked as DOP-899 </div> <blockquote type="cite"> <div> On 03 February 2019 at 16:50 Aki Tuomi < <a

I place the following data in a file id rs835 rs169 rs174 1001 CC GG CC 10032 CC GG CC 10066 CC NA CC If I read it in as tempDat <- read.table("tempDat.txt",na.strings="NA",header=TRUE) I get the following. id rs835 rs169 rs174 1 1001 CC GG CC 2 10032 CC GG CC 3 10066 CC <NA> CC NA has been assigned a missing