similar to: Column name assignment problem

Dear all, I am trying to manually re-sort rows in a number of tables. The rows aren't sorted on any particular values but are simply ordered by user choice (as shown by the row numbers in the code). I have been able to carry out each re-arrangement without the use of the 'for' loop, but cannot seem to successfully execute the statements when incorporated into the loop. The code I have

Dear all, I am trying to use 'merge' within a loop, however, I receive an error relating to the 'by' argument of the command, as follows: > merge_year <- 1986 > > for (i in 1:10) { # Number of file pairs + assign(paste("merged_arunfek_", merge_year, sep=""), merge(x=paste("arunoff_",start_arunoff, sep=""),

Hi all, I would like to have a function like this: split.vec.by.NA <- function(x) That takes a vector like this: x <- c(2,1,2,NA,1,1,2,NA,4,5,2,3) And returns a list of length of 3, each element of the list is the relevant segmented vector, like this: $`1` [1] 2 1 2 $`2` [1] 1 1 2 $`3` [1] 4 5 2 3 I found how to do it with a loop, but wondered if there is some smarter (vectorized) way

I created a 2 D plan: > plot(range(-2.5,0.95),range(0.00,1.00),type="n",axes=TRUE) I made a projection of points with their coordonates (X,Y) in that plan > fullpoints=read.csv2("fullpoints.csv",h=T) > plot(fullpoints) The points are listed in that .csv file it is organized this way: 0,48875 0,142857143 0,409 0,142857143 0,45611 0,25 0,49833 0,222222222 0,61158

Hello dear R-help group. My task looks simple, but I can't seem to find a "smart" (e.g: non loop) solution to it. Task: I wish to randomize a data.frame by one column, while keeping the inner-order in the second column as is. So for example, let's say I have the following data.frame: xx <-data.frame(a= c(1,2,2,3,3,3,4,4,4,4) , b =

Hello dear R members. I have been learning the Anova syntax in order to perform an SS type III Anova with repeated measures designs (thank you Prof. John Fox!) And another question came up: where/what are the (between/within) residuals for my model? ############ Play code: phase <- factor(rep(c("pretest", "posttest", "followup"), c(5, 5, 5)),

Hi All, I am new comer here and for Statistics R. I want to know how to use R to calculate one way repeated measure ANOVA, for example, on three groups of data. I appreciate if someone can help me solve this problem. John

Hello R help members. I came across today with an article on Barnard's exact test (http://www.cytel.com/Papers/twobinomials.pdf), that is supposed to give a more powerful fisher.test - Because it doesn't assume that we know the row and column totals are in advance. Any pointers to such a function ? Thanks, Tal -- ---------------------------------------------- My contact information:

Hello all, I wrote a small function to add labels for outliers in a boxplot. This function will only work on a simple boxplot/formula command (e.g: something like boxplot(y~x)). Code + example follows in this e-mail. I'd be happy for any suggestions on how to improve this code, for example: - Handle boxplot.matrix (which shouldn't be too hard to do) - Handle cases of complex

*(note*: This is an R community question, not a statistical nor coding question. Since this is my first time writing such a post, I hope no one will take offence of it.) Hello all, I will be attending useR 2009 next week, and was wondering if there are any of you who are *bloggers *intending to participate and report on useR 2009? If so - I would love to know your blogs URL so as to follow you.

Dear all, I'm trying to replace NA values with -9999 in one column of a data frame. I've tried using is.na and the testdata[testdata$onecolumn==NA] <- 9999 approach, but whilst neither generate errors, neither result in -9999s appearing - the NAs remain there! I'd be grateful for any advice on what I'm doing wrong or any other suitable approaches. Many thanks, Steve

Hello Martin Maechler and All, A simple question (I hope): How can I compute the "sum of the dissimilarities" that appears in the pam command (from the cluster package) ? Is it the "manhattan" distance (such as the one implemented by "dist") ? I am asking since I am running clustering on a dataset. I found 7 medoids with the pam command, and from it I have the

(I use R 2.9.1 with win XP) If I run this code: seq(-0.1,.9, by = .05)[seq(-0.1,.9, by = .05) <= 0.5] I get this output: [1] -0.10 -0.05 0.00 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 0.45 Why is 0.50 not in the results ? (It seems that it gives a slightly bigger number then 0.5 but I don't understand why it does that) Where as if I try: seq(-0.1,.9, by = .05)[seq(-0.1,.9, by = .05) <=

Hello all, A friend recently brought to my attention that vector assignment actually recreates the entire vector on which the assignment is performed. So for example, the code: x[10]<- NA # The original call (short version) Is really doing this: x<- replace(x, list=10, values=NA) # The original call (long version) # assigning a whole new vector to x Which is actually doing this: x<-

Dear all, I am trying to read in and assign data from 50 tables in an automated fashion. I have the following code, which I created with the help of textbooks and the internet, but it only seems to read in the final data file over and over again. For example, when I type:> table_1951 I get the same values in the table as when I type> table_2000 despite the values in the source tables

Hi, I'm trying to use the function "error.bars", but the program don't find it, and I dont't found any package with this function. Is there some another functin to draw barplots with error bars? Sueli Rodrigues Eng. Agr?noma - UNESP Mestranda - USP/ESALQ PPG-Solos e Nutri??o de Plantas Fones (19)93442981 (19)33719762

Hello dear R mailing list members. I have recently became curious of the possibility applying model selection algorithms (even as simple as AIC) to regressions of large datasets. I searched as best as I could, but couldn't find any reference or wrapper for using step or stepAIC to packages such as biglm. Any ideas or directions of how to implement such a concept ? Best, Tal --

Hello all. I wish to run k-means with "manhattan" distance. Since this is not supported by the function "kmeans", I turned to the "pam" function in the "fpc" package. Yet, when I tried to have the algorithm run with different starting points, I found that pam ignores and keep on starting the algorithm from the same starting-points (medoids). For my

(Have searched for this already) Hi, How do you find the strength of correlation between two variables using an ANOVA table? "Pr(>F)" gives the statistical significance of the association, but not the strength of the correlation. See data (from R) below Readable: "Df" "Sum Sq" "Mean Sq" "F value"

Hello people. I wish to reorder a simple vector of numbers by another vector of the order (and then do the same, but with a data frame rows) I try this (which doesn't work) : > aa <- c(3, 1 ,2 ) > aa[aa] [1] 2 3 1 The same won't work if I try to order a data frame: > data.frame(matrix(c(3,1,2), 3,2))[c(3,1,2),] X1 X2 3 2 2 1 3 3 2 1 1 How should I do this? p.s: