similar to: Interpolate x from y

Displaying 20 results from an estimated 5000 matches similar to: "Interpolate x from y"

2008 Sep 01
2
Interpolation Problems
Dear all, I'm trying to interpolate a dataset to give it twice as many values (I'm giving the dataset a finer resolution by interpolating from 1 degree to 0.5 degrees) to match that of a corresponding dataset. I have the data in both a data frame format (longitude column header values along the top with latitude row header values down the side) or column format (in the format latitude,
2013 Feb 14
1
approxfun values
Readers, According to the help '?approxfun', the function can be used to obtain the interpolated values. The following test was tried: > testinterpolation<-read.csv('test.csv',header=FALSE) > testinterpolation V1 V2 1 10 2 2 20 NA 3 30 5 4 40 7 5 50 NA 6 60 NA 7 70 2 8 80 6 9 90 9 10 100 NA >
2006 Jul 17
3
information about a function
Hi people, I am new in this list and could not find a FAQ for it in particular, furthermore I could not find my question answered in the official R FAQ or docs. I have simply something like this: > f<-approxfun(data[,1],data[,2]) and f is: > f function (v) .C("R_approx", as.double(x), as.double(y), as.integer(n), xout = as.double(v), as.integer(length(v)),
2004 Aug 16
3
bus error /segmentation fault from 'approx' (PR#7177)
Full_Name: joerg van den hoff Version: 1.9.1 OS: MacOS and SunOS Submission from: (NULL) (149.220.4.88) follow up to ID 7166. something like approx(c(1,2),c(NA,NA),1.5,rule=2) crashes 1.9.1 on both systems (MacOS 10.3.5.: bus error, SunOS 5.9: segmentation fault) even if xout is within given x range (as in example above) where rule=2 seems not be relevant anyway.
2007 Mar 15
1
How to use result of approxfun in a package?
I am working on a project where we start with start with 2 long, equal-length vectors, massage them in various ways, and end up with a function mapping one interval to another. I'll call that function "f1." The last step in R is to generate f1 as the value of the approxfun function. I would like to put f1 into a package, but without having the package redo the creation of
2008 Jun 19
1
error related to approxfun in R 2.7.0
I'm testing R version 2.7.0 on windows and there seems to be a compatibility issue with objects that were created by "approxfun" in older versions. As long as the objects were created in version 2.7.0 things work ok, but calling the interpolated functions from R version 2.0.1 causes this error: Error in .C("R_approx", as.double(x), as.double(y), as.integer(n), xout =
2013 Jan 16
1
function approx interpolation of time series data sets
Readers, Am trying to use the function 'approx' to interpolate time series data sets: data1: 01:23:40 5 01:23:45 10 01:23:50 12 01:23:55 7 data2: 01:23:42 01:23:47 01:23:51 01:23:54 The objective is to obtain interpolated values of 'data1' column 2 (5, 10, 12, 7) for the times shown in data2. Tried the following command but received the error shown:
2010 Sep 15
1
approxfun returning value higher than I would expect
Below is the code that I am using in a much larger function. I would expect a bankfull measure at zero to be between 0.6 and 0.8 approxfun is returning 0.8136986. I am sure that I am missing something. measure_bkf <- (structure(list(measurment_num = c(0, 0.2, 0.4, 0.6, 0.8, 1, 1.2, 1.4, 1.6, 1.8, 2, 2.2, 2.4, 2.6, 2.8, 3, 3.2, 3.4), bankfull_depths_m = c(-0.48, -0.48, -0.42, -0.26, 0.58,
2011 May 04
1
bivariate linear interpolation
Hi, I have three matrices (X,Y,P) with the same dimension. The X,Y grid is regular and I want to perform linear interpolation to pick out certain points. In matlab appropriate call is something like Pout=interp2(X,Y,P,Xout,Yout, method="linear") where Xout and Yout are the locations where I want the Pout data (typically a different grid). (Scipy has this routine in
2010 Dec 07
3
how to get vector of data from line ?
I have created a density line d<- density(X) now I need to read values from that line for example what is the value of this line at x = 1, 2, 3 etc... -- View this message in context: http://r.789695.n4.nabble.com/how-to-get-vector-of-data-from-line-tp3076943p3076943.html Sent from the R help mailing list archive at Nabble.com.
2009 Dec 01
3
paste name in for loop?
Hello, I am trying to create subsets of grouped data (by area size), and use the area size as part of the output name. The code below works for area (xout) 1 and 50, the other files are given NA for an area. A simple example: xout <- c(1,5,10,25,50,100) for(i in xout) { print(paste("Areal_Ppt_",xout[i],"sqmi.txt", sep="")) } [1] "Areal_Ppt_1sqmi.txt"
2005 Jul 21
1
About object of class mle returned by user defined functions
Hi, There is something I don't get with object of class "mle" returned by a function I wrote. More precisely it's about the behaviour of method "confint" and "profile" applied to these object. I've written a short function (see below) whose arguments are: 1) A univariate sample (arising from a gamma, log-normal or whatever). 2) A character string
2013 Feb 26
2
Help on a code
Dear List,   I have the following code:   x <-c(0, 13.8333333333333, 38.1666666666667, 62.1666666666667, 85.9166666666667, 108.916666666667) y <-c(1.77, 2.39, 3, 2.65, 2.62, 1.8) Interpolated <- approx(x, y,xout=0:tail(x, n=1),method="linear") plot(Interpolated)   in this code x is time in hours (cumulative), and y is a biological variable. I am using linear interpolation
2013 Mar 07
1
create vector from indices interpolated values
Readers, Is it possible to create a plot command based upon the indices of missing values in a data set? dataset1<-read.table(text=' 10 2 20 NA 30 5 40 7 50 NA 60 NA 70 2 80 6 90 NA 100 9 ') dataset2<-read.table(text=' 0.2 0.4 0.1 0.9 0.2 0.3 1.1 0.7 0.9 0.6 0.4 ') The 'approx' function is used to obtain the interpolated values for 'NA' in dataset1.
2015 Jun 30
3
Loop for: mostrar el nombre de la variables
Buenos días: Después de más de 20 años en SAS, ahora igual me toca trabajar en R. Y la transición es muy dura: la "lógica" de los dos lenguajes es, para mi, totalmente diferente. Disculpen si lo que pregunto es una obviedad, pero llevo todo el día con esto y no logro encontrar la respuesta adecuada con google. Estoy intentado crear una función que realice una descriptiva simple de
2013 Jan 17
1
Help with interpolation
hi guys I need to interpolate values for the zero coupon yield curve. Following data is given date days rate 1996 01
2012 Feb 17
1
time series manipulation what functions are "best"
Newbie question - mechanical engineer trying to learn R I've had success with plotting time series data and even made a heat map using R Graphs Cookbook by Mittal. I have a new problem - I need to align a number of time series data "columns" to the desired regular exact time stamp vector. The target time vector could be finer or more course than the typical time stamp spacing found.
2012 Jun 06
2
package zoo, function na.spline with option maxgap -> Error: attempt to apply non-function?
Hello, I'm trying to use na.spline (package zoo) to fill some missing data in a time series. this works fine, however, if I apply the 'maxgap' argument, I always get the error: <------ Error in na.spline.vec(x., coredata(object.), xout = xout., ...) : attempt to apply non-function ------> I couldn't find a similar error for this case in the mailing lists and zoo vignette,
2019 May 08
3
[R] approx with NAs --> new argument 'na.rm=TRUE' ?!
>>>>> Robert Almgren >>>>> on Fri, 3 May 2019 15:45:44 -0400 writes [ __ to R-help __ -- here diverted to R-devel on purpose] > There is something I do not think is right in the approx() > function in base R, with method="constant" and in the > presence of NA values. I have 3.6.0, but the behavior > seems to be the same in
2017 Sep 25
5
bowed linear approximations
Dear Rich, Assuming that I understand what you want to do, try adding the following to your script (which, by the way, is more complicated that it needs to be): xx <- 10:50 m <- lm(y ~ x) yy <- predict(m, data.frame(x=xx)) lines(spline(xx, yy), col="blue") m <- lm(y ~ log(x)) yy <- predict(m, data.frame(x=xx)) points(xx, yy, col="magenta") The first set of