similar to: problem with Dates

Hi all, I am trying to create a "index.csv" with caliculating different types of caliculations . In that i have to caliculate on 10,000 studies and have to insert many no of rows more than 500,000 for that right now I am inserting every row after caliculating and doing data.frame but its taking much time to create that index.csv is there any thing like bulk insert in to file

Hi all, I got one intresting problem with caliculating mean that is while i am taking mean of values *0.6, -0.8, 4, -3.8* using *val<-c(0.6, -0.8, 4, -3.8)* *mean(val)* it given result as *2.775558e-17* but the actual result is *"0"* can any one suggest how can I get correct mean result in this case can any one suggest how I can farward thanks in regards kiran [[alternative

Hi all, I am trying to parse a vector for caliculating minimum in that vector the vector having values like 1 Kontrolle 2 Placebo 3 125mg/kg 4 250mg/kg 5 500mg/kg 6 1000mg/kg hear i tries for comverting it into numeric with using "as.numaric()" function but i got values like 5 6 2 3 4 1 it gives 1000mg/kg is the least one but i have

The interface for dates in R is a little confusing to me. I want to create a vector of Date objects from vectors of years, months, and days. One solution I found is: years <- c(1991, 1992) months <- c(1, 10) days <- c(1, 2) dates <- as.Date(ISOdate(years, months, days)) But, in this solution the ISOdate function converts the vectors into characters, which can cause serious

Example code it shown below. I think I am doing this the hard way. I'm just trying to get the full year value from an array of dates. An example array is shown below. Right now, I'm using a "for" loop to pull the year out of a list where the dates were split up into their individual components. This seems to work, but just wondering if there is an easier way. Thanks for

i have converted my data into date format like below: > day=as.Date(originaldate,"%m/%d/%Y") > day[1:5] [1] "2008-04-12" "2011-07-02" "2011-09-02" "2008-04-12" "2008-04-12" I wish to select only those observations from 2007 to 2009, how can I select from this list? [[alternative HTML version deleted]]

Dear All: I am having some trouble with date variables when NAs are present. The following example illustrates (see below for output of version): > library(chron) > minor.test <- c( "NA", "NA", "1988-02-08", + "1988-02-08", "NA", "1987-11-23", "1988-09-03", "1991-10-15", +

I can't get the scales parameter in xyplot of lattice to work as I expected. I'm using R-2.1.0 and lattice 0.11-8. There should be year labels from 1992 to 2004 for the x axis in the plot below, but instead only a few of them appear, and in the wrong spots, as if the coordinate system has changed after finishing with the panel function. library(chron) library(lattice) # vertical grid

Hi all, I have a problem with writing a *.CSV file in UTF-8 formate I tried to write a dataframe named "dfPREINDX" to the new file named "preindx.csv" in below formate write.table(dfPREINDX,PreIndex,fileEncoding="UTF-8",sep="|",row.names=FALSE) but its throed an error like Error in write.table(dfPREINDX, "preindx.csv", fileEncoding =

Hello everyone, I have a data generated in a way similar to the following library(chron);library(zoo) date<- seq(as.Date("1990-01-01"),, as.Date("2000-12-31"), by = 1) obs<- zoo(rnorm(length(date), mean = 10, sd = 2.5), order.by = date) monthly<- function(date) as.Date(as.yearmon(Date)) result<- data.frame ( Date = obs = aggregate(obs, monthly, sum)) Now, I want

Hello, I am looking for a documentation of the communication protocolls icecast is capable of: ICY, XAUDIOCAST and a modified HTTP. In order to write client software being capable of all available features I was searching on the net for those documentations but no luck so far. How come? Isn't this protocoll documented? How does the developer team know what options and functins are available

Hi, I have the next procedure: t1<-data.frame(table(substr(names(subset(lasker[[1]], lasker[[1]] >= 4)), 1, 7))) t1[1:5,] Var1 Freq 1 1988-02 3 2 1988-03 1 3 1988-04 1 4 1988-05 2 5 1988-06 3 How to make a new list?, dataframe? having 189 elements in the 'lasker' list: > str(lasker[[1]]) 'table' int [, 1:1274] 1 1 3 2 1 5 4 1 1 4 ... -

I need some help with sub-setting my data.  I am trying to divide a data frame into multiple data frames based on the year collected, and stored in a list with each new data frame labeled with "year X" where X is the year the data was collected.  When I run my current code I get nine error messages stating "In one_year[name] <- myear :  number of items to replace is not a

Hi, Having a dataframe 'l1' (dput output is below): >dim(l1) 1274 2 >l1[1:12,] Var1 Freq 1 1988-01-13 1 2 1988-01-16 1 3 1988-01-20 3 4 1988-01-25 2 5 1988-01-30 1 6 1988-02-01 5 7 1988-02-08 4 8 1988-02-14 1 9 1988-02-16 1 10 1988-02-18 4 11 1988-02-24 2 12 1988-03-04 1 I want to extract the times

Dear r-Help readers, 1) Is there support for NSUR in some R package yet? 2) Is there a general function of applying the Gauss-Newton or Marquard method, in which the function of calculating the partial derivatives can be specified by the user? Contemporaneously correlated non-linear models (NSUR) is a method to fit a system of non-linear equations. I want to use to fit several non-linear

Hello everyone. Just have a question , cant figure out how to make this histogram. I have this table, that i stored in a variable name new.data2. Table looks like this Year GeoArea SmpNo Month Gear Maturity Length Age YearC 1989 1 362 10 22 1 225 1 1988 1991 1 267 10 10 1 191 1 1990 1991 1 267 10 10 1 202 1 1990 1992

Hi, I have a list of 20 elements, each of them of variable length and with a structure like this: lasker[[1]][1:10,] Var1 Freq 1 1988-02 3 2 1988-03 1 3 1988-04 1 4 1988-05 2 5 1988-06 3 6 1988-07 1 7 1988-08 1 8 1988-09 1 9 1989-03 1 10 1989-04 1 How do I can insert in this list: 1988-01 0 1988-10 0 1988-11 0 1988-12 0 1989-01 0

cumsum() seems to be what you need. This can probably be done more elegantly, but ... out <- aggregate(Q ~ wyr, data = Daily, which.max) tbl <- table(Daily$wyr) out$Q <- out$Q + cumsum(c(0,tbl[-length(tbl)])) out ## yields wyr Q 1 1990 4 2 1991 6 3 1992 9 4 1993 15 5 1994 18 I leave the matter of Julian dates to you or others. Cheers, Bert Bert Gunter "The trouble

Using the dataset below, I got close to what I'm after, but not quite all the way there. Any suggestions appreciated: Daily <- read.table(textConnection(" Date wyr Q 1911-04-01 1990 4.530695 1911-04-02 1990 4.700596 1911-04-03 1990 4.898814 1911-04-04 1990 5.097032 1911-04-05 1991 5.295250 1911-04-06 1991 6.569508 1911-04-07 1991 5.861587 1911-04-08 1991 5.153666

Hello, I have a data of Patents from OECD in delimited text format with IPC being one column, I want to filter the data by selecting only certain IPC in that column and delete other rows which do not have my required IPCs. Please, can anybody guide me doing it, also the IPC codes are string variables. The data is somewhat like below, but its a huge dataset containing more than 11 million rows