similar to: coefficient graph

Displaying 11 results from an estimated 11 matches similar to: "coefficient graph"

2009 Mar 15
2
xyplot of a specific ID number
Dear R list members, I have a question regarding xyplot. I managed to make a xyplot of all the IDs by using the syntax below: xyplot(PA ~ CRPC + CRPT | ID, data = redinteract) Now, I'd like to make a graph of a specific ID number (e.g., only ID number 301). I thought I could use "subset", but it seems to be not working. Could anyone let me know how I can make a graph of a
2011 May 11
0
Can't log into SSL sites with Mac, Wine
Using any version I have tried, from old 1.1, to new 1.3.19, I cannot use IE7 or IE8 to log into a https site. Not even Google. ie either hangs, or, on many sites, simply says that the password is wrong. I've tried many https sites I log into. I also overrode wininet and winhttp, and crpt, to no avail. Any other ideas? What sort or trace might be useful were I to file a bug report?
2010 Apr 30
1
QIC for GEE
Hi, I'm using 'geepack' to run Generalized Estimating Equations. I'm aware that I can use anova to compare two models, but would it be possible to test QIC on R? It seems that there were similar questions a couple of years ago, but the question has not been answered yet. I'd appreciate if someone could show me the code! Thank you, Sachi [[alternative HTML version
2010 Apr 29
1
Generalized Estimating Equation (GEE): Why is Link = Identity?
Hi, I'm running GEE using geepack. I set corstr = "ar1" as below: > m.ar <- geeglm(L ~ O + A, + data = firstgrouptxt, id = id, + family = binomial, corstr = "ar1") > summary(m.ar) Call: geeglm(formula = L ~ O + A, family = binomial, data = firstgrouptxt, id = id, corstr = "ar1") Coefficients:
2010 Apr 29
1
Changing from 32-bit builds to 64-bit builds
Hi, Probably this is a very simple question for all the programmers, but how do you change from 32-bit builds (default) to 64-bit builds? I've been trying to run Anova to compare two models, but I get the following error message: Error: cannot allocate vector of size 1.2 Gb R(3122,0xa0ab44e0) malloc: *** mmap(size=1337688064) failed (error code=12) *** error: can't allocate region ***
2010 Jun 08
1
GEE: estimate of predictor with high time dependency
Hi, I'm analyzing my data using GEE, which looks like below: > interact <- geeglm(L ~ O + A + O:A, + data = data1, id = id, + family = binomial, corstr = "ar1") > summary(interact) Call: geeglm(formula = lateral ~ ontask + attachment + ontask:attachment, family = binomial, data = firstgroupnowalking, id = id, corstr = "ar1") Coefficients:
2008 Dec 12
1
How can we predict differences in a slope, given that the random component was significant?
Dear R users, Using R lme function, I found that both fixed and random effects of variable A on variable B are significant. Now, I'd like to analyze what variables are predicting differences in the slope. In other words, I'd like to know what variables (e.g., variable C) are predicting individual differences in the effects of A on B. I have many data points for A and B for each
2010 Apr 14
1
Sig differences in Loglinear Models for Three-Way Tables
Hi all, I've been running loglinear models for three-way tables: one of the variables having three levels, and the other two having two levels each. An example looks like below: > yes.no <- c("Yes","No") > switch <- c("On","Off") > att <- c("BB","AA","CC") > L <- gl(2,1,12,yes.no) > T <-
2009 Jun 28
1
HLM - centering level 2 predictor
Dear R-helpers, I'm analyzing a data with hierarchical linear model. I have one level 1 predictor and one level 2 predictor, which looks like below: fm1 <- lmer(y ~ 1 + x1 + x2 + x1:x2 + (1 + x1 | id.full)) where: y is the outcome variable. x1 is the level 1 predictor variable. x2 is the level 2 predictor variable. id.full is the conditioned variable. It runs beautifully when only x1
2009 Jul 23
6
SSH attacks from china
Okay, I have a server connected to the net but have not added fail2ban or anything on top of my firewall yet. Thought you guys might get a kick out of this one user, ip is from china, who has got a heck of a knack for making assumptions on possible usernames. Enjoy this..., 8000+ attempts. Scroll down for funky ones. I have no root access enabled on this server and it is pretty bare. Just using
2010 Aug 30
0
Posthoc test for 3-way interaction (log-linear model)
Hi, I have analyzed my data using log-linear model as seen below: > yes.no <- c("Yes","No") > tk <- c("On","Off") > ats <- c("S","V","M") > L <- gl(2,1,12,yes.no) > T <- gl(2,2,12,tk) > A <- gl(3,4,12,ats) > n <- c(1056,4774,22,283,326,2916,27,360,274,1770,15,226) >