similar to: Taking diff of character vectors

Dear group, I have a matrix like the following: Name Sample1 sample2 sample3 sample4 ..... sample(n) nm1 10.5 13.5 30 31 nm2 8 11 34 29 nm3 9 10.3 27.8 35 nm(j) I want to be able to calculate correlation between all pairs of names. For example (nm1,nm2),

Hi Listers, This has a simple answer but it has been eluding me nonetheless. I have been building a PCA plot from scratch with the ability to plot predefined groups in different colors. This has worked fine but when I try to get a polygon drawn around each of the groups it is not recognising my colour file correctly and is only printing the first colour in the file....code is below

Dear all, Myself Vijaykumar Muley working as senior research fellow. By training I am a computational biologist with not a strong knowledge of statistics. I have done some analysis which is explained as follows, I have 10340 (X) profiles of binary vectors with same length(N=845), I will call then "gene profiles" for example... v1 v2 v3 v4.....vN a 1 0 1 0 1 b 0

Hi. I am trying to use the linear optimizer from package lpSolve in R 2.4.1 on Windows XP (Version 5.1). The problem I am trying to solve has 2843 variables (2841 integer, 2 continuous) and 8524 constraints, and I have 2 Gb of memory. After I load the input data into R, I have at most 1.5 Gb of memory available. If I start the lp with significantly less memory available (say 1 Gb), I get

Hi. I have defined a function, f1, that calls another function, f2. Inside f1 an intermediate variable called nm1 is created; it is a matrix. f2 takes a matrix argument, and I defined f2 (schematically) as follows: f2<-function(nmArg1=nm1,...){nC<-ncol(nmArg1); ... } so that it expects nm1 as the default value of its argument. f1 is defined (schematically) as:

Hello, I?m new at programming and I will greatly appreciate if you can help me with this. I have a very large matrix (hundreds of rows and columns), with the first raw filled with different numbers (between 0 and 1). The rest of the matrix is filled with values 0, 1, 2. What I need is to replace the values in the matrix (except the first row will has to remain intact). In each column I have to

Dear R-users, I am trying to reshape the DF "dat2" in the "long" format, but can't figure out how to use the "split"-option: > dat2 a.1995.z b.1995.z a.1996.z var 1 100.00000 100.00000 100.00000 Neue Anlagen insgesamt 2 40.09904 23.60890 40.88960 Neue Ausr??stungen 3 59.90096 76.39110 59.11040 Neue Bauten This

Hello, colnames seems to be not optimized well for data.frame. It escapes processing for data.frame in if (is.data.frame(x) && do.NULL) return(names(x)) but only when do.NULL true. This makes huge difference when do.NULL false. Minimal edit to `colnames`: if (is.data.frame(x)) { nm <- names(x) if (do.NULL || !is.null(nm)) return(nm) else

Hello R people, How can I compute the mean of the "Pulse_rate" column of the data frame or matrix from the following character object called "str_got". It has 14 entries and each entry has 8 values, separated by commas. Please go thru the following R commands to know how I tried to unstring and unlist the values to form a data frame. > str_got [1]

I'm reading in some data from a csv file, and it's reading in some of the columns as character variables instead of numeric. I know I can fix this by doing as.numeric for each of the columns, but the problem is I have a LOT of different quantitative variables that I would have to do this for. I've been trying something along the following but it hasn't really been working

Dear all, I created a function which it has many arguments i.e. Mu(x, Y, B, X, P) where Mu is the function. This function works perfect but when I am trying to use it in the apply() function in the manner apply(Matr, 1, Mu, Y=y, B=b, X=x, P=p) it does not work and the output is: Error in match.fun(FUN) : '1' is not a function, character or symbol When I transform the function Mu to have

Hi people, If there is a fn "colMeans" why isn't there a "colSDs" etc Thanks, Phil. -- Philip Rhoades Pricom Pty Limited (ACN 003 252 275) GPO Box 3411 Sydney NSW 2001 Australia Mobile: +61:0411-185-652 Fax: +61:2:8923-5363 E-mail: pri at chu.com.au -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

Hi, I'm working with a big square matrix (15k x 15k) and I have some trouble. I want to delete selecting rows and columns. I'm using something like this: > sel_r=c(15,34,384,985,4302,6213) > sel_c=c(3,151,324,3384,7985,14302) > matrix=matrix[-sel_r,-sel_c] but it works very slow. Does anybody know how to make it in faster way? Thank's -- View this message in context:

Hi R fans I am trying to make a program to ask the user to choose data file: print("Choose data file please !") matr=read.table(file.choose(),dec=".",header=TRUE) The problem is that the prompt Choose data file please ! comes after I have chosen the file. What am doing wrong? Thanks in advance Ralf Finne

I need to calculate a large number of t statistics, and would like to do so via matrix operations. So far I have figured out a way to calculate the mean of each row of the matrix: d <- matrix(runif(100000,1,10), 1000, 10) # some test data s <- rep(1,ncol(d)) # a sum vector to use for matrix multiplication means <- (d%*%s)/ncol(d) This is at least 1 order of magnitude faster than

Dear list, Following a recent enquiry, I've been playing with the idea of creating a colour gradient for a polygon, using the Grid package. The idea is to draw a number of stripes of different colours, using the grid.clip function. Below is my current attempt at this, library(grid) rotate.polygon <- function(g, angle=0){ # utility function, works fine matR <- matrix(c(cos(angle),

I am using the R 2.2.1 in a Windows XP environment. I have a dataframe with 12 columns and 1,000 rows. (Some of the rows have 1 or fewer values.) I am trying to use rowVars to calculate the variance of each row. I am getting the following message: ?Error in na.remove.default(x) : length of 'dimnames' [1] not equal to array extent? Is there a good work-around?

Hi, I have a problem with Kolmogorov-Smirnov test fit. I try fit distribution to my data. Actualy I create two test: - # First Kolmogorov-Smirnov Tests fit - # Second Kolmogorov-Smirnov Tests fit see below. This two test return difrent result and i don't know which is properly. Which result is properly? The first test return lower D = 0.0234 and lower p-value = 0.00304. The lower 'D'

On Thu, Jan 21, 2016 at 04:57:34AM -0800, ivenhov wrote: > Hi > > Does anyone had similar issues in the past? > I still cannot find reason why notification of file modification of files in > subdirs is not visible on client machines Someone needs to send network traces and debug level 10 logs for this. And try to reproduce the same against a Windows server. Volker -- SerNet

Is it possible to compute the variance of every column in a matrix without a loop? -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch