similar to: Selecting / creating unique colours for behavioural / transitional data

I've found RColorBrewer useful for its qualitative palettes, but wished that it could generate more than 12 qualitative palettes (e.g. with Set3). Any suggestions for alternative color palette generators that can handle e.g. 18 distinctive colors? (I'm aware of using rainbow(), but this doesn't generate enough distinct colors when the number of palettes is large). Thanks, Andrew

Hi, I was trying to make a density plot with 13 samples. To distinguish each sample, it would be good if each color is as different as possible from the other colors. I could use the built in function, but that does not do more than 8 colors and then goes back to recycling the cols. If I use a palette, then it is really difficult to distinguish between the colors. So, is there a way that I can

Dear all, Myself Vijaykumar Muley working as senior research fellow. By training I am a computational biologist with not a strong knowledge of statistics. I have done some analysis which is explained as follows, I have 10340 (X) profiles of binary vectors with same length(N=845), I will call then "gene profiles" for example... v1 v2 v3 v4.....vN a 1 0 1 0 1 b 0

Anyone who is interested in using optimal colour palettes should look at the work of Cindy Brewer: www.colorbrewer.org I have written code to use her colour schemes in R. It is included below. Perhaps someone may find this interesting enough to work into a package. Included also is a function showpalette, which was posted here a while back. I don't remember who wrote it. I have copied all

Hola, no me funciona: Te contesto lo mismo que le contesté a otro compañero de la lista, espero ser más claro. Les comparto la carpeta con la capa y los datos que estoy usando. https://www.dropbox.com/s/umy0evt3qm1wr4d/dissolve.zip Esto es lo que estoy haciendo: library(rgdal) library(maptools) library(sp) library(classInt) library(RColorBrewer) zm <- readOGR(?.?, ?zmdis?) data <-

Hola, Intento representar en un mapa participaciones porcentuales de los sectores económicos y no logro hacerlo con spplot. He intentado con spplot(zm, c(?part88?, ?part93?), cuts=4, col.regions=brewer.pal(4, ?Set3?)) Lo pude hacer utilizando el base graphics de R, definiendo: > plotvar88 <- zm$part88 > nclr <- 8 > plotclr <- brewer.pal(nclr, "PuOr") > plotclr

Dear List, I am new to lattice plots, and am having problems with getting my plot to do what I want. Specifically: 1. I would like the legend to have the same symbols as the plot. I tried simpleKey but can't seem to get it to work with autoKey. Right now my plot has dots (pch=19) and my legend shows circles. 2. I have nine groups but xyplot seems to only be using seven colors, so two

Hola, El problema con la propuesta de Olivier es que los intervalos son diferentes para cada variable. La forma sencilla y rápida es: spplot(zm["part88"], col.regions=plotclr, at=class$brks) Pero para que quede más elegante hay que dar algunos pasos más: ## Intervalos en forma character op <- options(digits=4) tab <- print(class) options(op) intChar <- names(tab) ## Indice

Hello I'm using rainbow function to generate 10 colors for the plot and it is difficult to tell the neighboring colors from each other. How can I make the colors more differently. Thanks Zhaoming [[alternative HTML version deleted]]

On 16/04/2016 8:47 AM, Atte Tenkanen wrote: > Hi, > > How would you calculate the "mean colour" of several colours, for > example c("#FF7C00","#00BF40","#FFFF00")? > Bert answered your subject line question. Your text is asking something else: if those are colours, you don't want to treat each of them as a single integer. A

I'm looking for a scheme to generate a default color palette for plotting points, lines and text (on a white or transparent background) with from 2 to say 9 colors with the following constraints: - "red" is reserved for another purpose - colors should be highly distinct - avoid light colors (like "yellow"s) In RColorBrewer, most of the schemes are designed for area fill

Hm..., Should these two versions produce the same solution? Unfortunately and shame to confess, I don't know much about the colors in R: myColors <- c("#FF7C00","#00BF40","#FFFF00") Colors=rgb2hsv(col2rgb(myColors)) apply(Colors,1,mean) h s v 0.2122974 1.0000000 0.9163399 * * * * * # Average the 1st two by taking the middle colour

Hello R-folks, I don't get the color of the legend in a lattice-plot right. I select a palette from RColorBrewer and use it in the barchart plot. The resulting graph shows the new palette in the graph, but in the legend rectangles the standard palette is used. Adding a col argument into auto.key uses the new palette with the legend text, but not in the rectangle fill. What am I missing?

Hey everyone, I am new to R, and I'm making a scatter plot graph where i have a bunch of plots/points that fall into 9 unique categories. I want each category to have a unique colour, however, with the coding I have (below), the colour black is repeated for two of my plot types. Does anyone know a quick way to get 9 unique colours?? Coding: plotba = plot (predictedba ~ actualba,

Hello R-folks, I don't get the color of the legend in a lattice-plot right. I select a palette from RColorBrewer and use (with a col = mypalette argument) it in the barchart plot. The resulting graph shows the new palette in the graph, but uses the standard palette in the legend rectangles. Adding a col argument into auto.key uses the new palette with the legend text, but not in the

Hola, Yo lo resuelvo usando grid.rect. Tienes una posible solución aquí: https://github.com/oscarperpinan/spacetime-vis/blob/master/choropleth.R#L216 (que es una versión actualizada de este artículo https://procomun.wordpress.com/2012/02/18/maps_with_r_1/) Saludos. Oscar. ----------------------------------------------------------------- Oscar Perpiñán Lamigueiro Dpto. Ing. Eléctrica,

Hola He hecho el típico mapa con gadm y spplot: library(sp) ES <- local(get(load(url("http://biogeo.ucdavis.edu/data/gadm2/R/ESP_adm2.RData ")))) acerco las canarias: A <- which(ES en data$NAME_1 == "Islas Canarias") L <- length(ES en polygons[[A]]@Polygons) L <- length(ES en polygons[[A]]@Polygons) for (i in 1:L){ ES en polygons[[A]]@Polygons[[i]]@coords

Dear R users, I'd like to change the default order of colors & line types. Especially I am using ggplot2 and using color Set1. In Set1, the default color order is red, blue, green, violet,.. ect. However, I want to put red in fourth (not first). Likewise, I want to change the order of default linetype. I want to put "solid" line in fourth. How can I do thses? R code to draw the

Hi, How would you calculate the "mean colour" of several colours, for example c("#FF7C00","#00BF40","#FFFF00")? Yours, Atte Tenkanen

Full_Name: Hsiu-Khuern Tang Version: 1.8.0 OS: GNU/Linux (Debian unstable) Submission from: (NULL) (156.153.255.243) Hi, I use palette(rgb(red=..., green=..., blue=..., names=mycolors)) to define my own color palette. After doing this, the names `mycolors' are not stored in palette() anymore, so that palette() returns a mix of built-in color names and RGB values. Eg: > palette()