similar to: R grep & gsub issue - sign seems to be causing an issue...

Say I have the following data: house_number<-floor(runif(100, 200, 600)) water_evaluation<-c("No water damage", "Water damage", "Water On", "Water off", "water pipes damaged", "leaking water") water_evaluation_selection<-floor(runif(100, 1,6)) house_info<-data.frame(water_evaluation[water_evaluation_selection],

The following code works, to gsub single quotes to double quotes: line <- gsub("'", '"', line) (that's a single quote within doubles then a double within singles if your viewer's font is not good). But The R Language Manual tells me that Quotes and other special characters within strings are specified using escape sequences: \' single quote \"

In a string context, grep, gsub, sub are improperly treating NA (missing) as the string "NA", and returning unexpected results > grep("A", c(NA,"NA")) [1] 1 2 # expected: # [1] 2 > gsub("A", "X", c(NA,"NA")) [1] "NX" "NX" # expected # [1] NA "NX" > sub("A", "X",

Hello, I have an expression that I want to substitute for something else. myvector<-c("ajkhfkiuwe","Variable(kg/min)") if I use the following code to extract "variable(kg/min)" and substitute it for "va" gsub(myvector[grep("var", myvector, ignore=T)], "va", myvector) grep identifies the element of the vector that matches my

Hi all, Let Names a vector of chatacters. For example, > Names [1] "g 604 be-0 -p1 (602 matches)" "g 606 Phli-0 -p2 (517 matches)" [3] "g 608 alu-0 (659 matches)" I try to use gsub or grep functions for two problems : 1. First, I would like to delete all the characters between parentheses. [1] "g 604 be-0 -p1" "g 606 be-0 -p2" [3] "g

Dear R-users -- I'm using R 1.3.0 on a PC running SuSE Linux 7.1. I'm confused by the following behavior from the gsub() function. Am I doing something wrong? ## A string of characters > string<-c("q","w","e","(",")","q","w","e") ## Use gsub to replace `q' with `A' >

Full_Name: Jerome Asselin Version: 1.5.1 OS: linux redhat 7.2 Submission from: (NULL) (142.103.173.179) gsub() return different answers depending on how the input variables were created. Here is an example of code that replicates the problem. The vectors y and yy appear to be the same, but gsub() doesn't return the same answer. It should remove all the blanks when I use the vector y, but it

Hi, I would like to substitute a semicolon with two double quotation marks and a comma inbetween. It suppose to look like that: I have: FBpp0070086;FBpp0099643;FBpp0112915 I would like to have: "FBpp0070086","FBpp0099643","FBpp0112915" I tried with various numbers of backslashes, but noe have worked. for example: gsub(";", "\\\",\"",

Dear helpers, I'm trying to replace a character with a unicode code inside a data frame using gsub(), but unsuccessfully. > data.frame(animals=c("dog","wolf","cat"))->my.data > gsub("o","\u0254",my.data$animals)->my.data$animals > my.data$animals [1] "d??g" "w??lf" "cat" It's not that a data

R Version 1.9.1 (2004-06-21) Mac OS X.3.5 Dual 2GHz PowerPC G5 GUI = "AQUA" I have a data.frame comprising percentiles with the column headings containing % characters, e.g. > (pp <- colnames(temp2)) [1] "5%" "10%" "25%" "50%" "75%" "90%" "95%" I use xtable to convert the data.frame to Latex but I want to

| Confirmed for R-devel (current) on Ubuntu 17.10. But ... isn't the regexp | you use wrong, ie isn't R-devel giving the correct answer? No, I don't think R-devel is correct (or at least consistent with the documentation). My interpretation of gsub("(\\w)", "\\U\\1", entry, perl = TRUE) is "Take every word character and replace it with itself, converted to

I am trying this: I want to replace all the text in between java comments: /* start */ replace this text here /* end */ I''m trying: text.gsub(//* start */(.*)/* end *//im, replace_with) But i''m getting errors relating to expecting keyword_end. How should I be escaping /* and */ ? Also, does string interpolation work in gsub regex? Say I had variables like: start_tag =

Hello. I'd like to be able to print variable strings which contain "\" as-is, without interpreting (for example) "abcde\nuvxyz" as having an embedded newline (or whatever other escaped instruction). To do this, I've tried gsub, and here's some of my output (I've tried all kinds of variations to the arguments): >

Experimenting a bit further, I've "found" the following 1) the problem seems only gsub(), not sub() > sub(" ", "", "b c + d | a * b", perl=TRUE) [1] "bc + d | a * b" > gsub(" ", "", "b c + d | a * b", perl=TRUE) NULL 2) only if perl = TRUE, not otherwise 3) Also modifying the replacement string

Hi all, I'd like to discuss a infelicity/possible bug with gsub. Take the following function: f <- function(x) { gsub("\u{A0}", " ", gsub(" ", "\u{A0}", x)) } As you might expect, in utf-8 locales it is idempotent: Sys.setlocale("LC_ALL", "UTF-8") f("x y") # [1] "x y" But in the C locale it is not:

Hi Guys, I am relatively new to R and was wondering if I could next my gsub command in identifying one object I have data which looks like this: <name>Taiwan_250km</name> I want it to look like this: Taiwan_250km So essentially I just want to gsub '<name>' and </name> with nothing! So far I have got this: PolyNam <-

Hi! I experience an error with an invalid UTF-8 character passed to gsub(..., perl=TRUE); the interesting point is that with perl=FALSE (the default) no error happens. (The character itself was read from an invalid HTML file.) Illustration of the error: gsub("a", "", "\U3e3965", perl=FALSE) # [1] "\U3e3965" gsub("a", "",

Hello everybody, this might be a trivial question, but I have been unable to find this using Google. I am trying to replace double backslashes with single backslashes using gsub. There seems to be some unexpected behaviour with regards to the replacement string "\\". The following example uses the string C:\\ which should be converted to C:\ . > gsub("\\\\",

Hi A while back I used gsub to do the following temp<-"000US00231" gsub("something here", "", temp) "00231" I think it involved the `meta characters' somehow. I do not know how to do this anymore. I know strsplit will also work but I remember gsub was much faster. In essence the question is how to delete all characters before a particular

Dear R users, my problem today deals with my ignorance on regular expressions. a matter I recently discovered. Consider the following foo <- c("V_7_101110_V", "V_7_101110_V", "V_9_101110_V", "V_9_101110_V", "V_9_s101110_V", "V_9_101110_V", "V_9_101110_V", "V_11_101110_V", "V_11_101110_V",