Displaying 5 results from an estimated 5 matches for "expatriation".
2005 Aug 24
1
How to collect better estimations of a logistic model parameters, by using bootstrapping things ?
...but I'm still
waiting to find the right way to use it.
As well I would like to find a fine way to do stepwise forward
selection In R, as I am not sure wich kind of variable may be
involved in the model, which is composed with 13 numeric variables,
and a dichotomic variable named "expatriation". I have got a total of
41 observations, as mentionned above.
I'm using R on macintosh, I have used the function lrm, brlr,
bootstrap (but for others uses than logistic regressions), and I am
looking for a great and paved way to do Confiance Intervals, and to
compute significance...
2004 Jan 25
3
looking for iax termination
Hi,
I am looking for voip termination all over the world especially based on IAX or SIP.
Regards.
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2007 Jul 05
0
universally
ERMX Continues To Expand As Stock Climbs Up 16.6%!
EntreMetrix Inc. (ERMX)
$0.21 UP 16.6%
ERMX announced further expansion with K-9 Genetics. Healthy and Premium
dog foods grossed $3.6 Billion in 2006, up from $1.9 billion in previous
years. Read up on ERMX over the holiday, we think you will see even more
fireworks on Thursday morning!
I may need one like this.
" "Happy" and
2007 Jul 05
0
universally
ERMX Continues To Expand As Stock Climbs Up 16.6%!
EntreMetrix Inc. (ERMX)
$0.21 UP 16.6%
ERMX announced further expansion with K-9 Genetics. Healthy and Premium
dog foods grossed $3.6 Billion in 2006, up from $1.9 billion in previous
years. Read up on ERMX over the holiday, we think you will see even more
fireworks on Thursday morning!
I may need one like this.
" "Happy" and
2012 Jan 21
4
Create subset using variable
I am trying to create a loop that will perform a series of analyses. I am
using geeglm from geepack, which fails if there are any null values.
Creating a subset solves this, but do not seem to be able to set the subset
dynamically based on a changing variable.
while (j <= y.num) {
strSubset = as.character(df.IV$IV[j]) #Gives column name in quotes
df.data.sub = subset(df.data,