Displaying 1 result from an estimated 1 matches for "27.80000".
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27.10000
2013 Jan 28
6
Thank you your help.
Hi,
temp3<- read.table(text="
ID CTIME WEIGHT
HM001 1223 24.0
HM001 1224 25.2
HM001 1225 23.1
HM001 1226 NA
HM001 1227 32.1
HM001 1228 32.4
HM001 1229 1323.2
HM001 1230 27.4
HM001 1231 22.4236 #changed here to test the previous solution
",sep="",header=TRUE,stringsAsFactors=FALSE)
?tempnew<- na.omit(temp3)
?grep("\\d{4}",temp3$WEIGHT)
#[1] 7 9 #not correct